TSQL - Создание вида на основе строк таблицы и ячейках значение

Question

я застрял ниже левую структуру таблицы (SQL Server 2012), чтобы создать представление или функцию, которая будет выводить правильную таблицу на скриншоте:

TestOutput таблица содержит данные, начиная с RowNumber 10 (Step0_Name1) для каждого ID. В реальном сценарии есть несколько шагов, чем я привел здесь в качестве примера.

Я надеюсь, что по какой-то логике, чтобы получить все пары написанных LKE Step0_Name1 и Step0_Name1_Status быть его именем распознавания/номер или нумерацией строк.

Я предполагаю, что курсоры понадобятся для создания какой-то логики цикла.

К сожалению sqlfiddle.com выдает ошибку, поэтому я вставил схему здесь:

Создание теста:

CREATE TABLE [dbo].[Test](
    [ID] [nchar](5) NOT NULL, 
    [Version] [smallint] NOT NULL, 
    [RowNumber] [int] NOT NULL, 
    [COLUMN1] [nvarchar](max) NULL, 
    [COLUMN2] [nvarchar](max) NULL, 
    [COLUMN3] [nvarchar](max) NULL, 
    [COLUMN4] [numeric](15, 3) NULL, 
CONSTRAINT [PK_Test] PRIMARY KEY CLUSTERED 
( [ID] ASC, 
    [RowNumber] ASC 
)WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY] 
) ON [PRIMARY] TEXTIMAGE_ON [PRIMARY] 

Вставка теста:

INSERT INTO [dbo].[Test] 
      ([ID] ,[Version] ,[RowNumber],[COLUMN1],[COLUMN2],[COLUMN3],[COLUMN4]) 
Values 
('00010',1, 1, 'Sheet', 'Part',    'A',   NULL), 
('00010',1, 2, 'Sheet', 'Name',    'PartName',  NULL), 
('00010',1, 3, 'Sheet', 'Price',   NULL,   1.470), 
('00010',1, 4, 'Sheet', 'Step0_SOP',  '2015 CW 09', NULL), 
('00010',1, 5, 'Sheet', 'Step1_SOP',  '2015 CW 10', NULL), 
('00010',1, 6, 'Sheet', 'Step2_SOP',  '2015 CW 11', NULL), 
('00010',1, 7, 'Sheet', 'Step0_Status',  'pending',  NULL), 
('00010',1, 8, 'Sheet', 'Step1_Status',  'frozen',  NULL), 
('00010',1, 9, 'Sheet', 'Step2_Status',  'released',  NULL), 
('00010',1, 10,'Sheet', 'Step0_Name1',  'Auser',  NULL), 
('00010',1, 11,'Sheet', 'Step0_Name2',  NULL,   NULL), 
('00010',1, 12,'Sheet', 'Step0_Name3',  'Buser',  NULL), 
('00010',1, 13,'Sheet', 'Step0_Name1_Status','started',  NULL), 
('00010',1, 14,'Sheet', 'Step0_Name2_Status',NULL,   NULL), 
('00010',1, 15,'Sheet', 'Step0_Name3_Status','pending',  NULL), 
('00010',1, 16,'Sheet', 'Step1_Name1',  'Wuser',  NULL), 
('00010',1, 17,'Sheet', 'Step1_Name2',  'Cuser',  NULL), 
('00010',1, 18,'Sheet', 'Step1_Name3',  'Duser',  NULL), 
('00010',1, 19,'Sheet', 'Step1_Name1_Status','released', NULL), 
('00010',1, 20,'Sheet', 'Step1_Name2_Status','pending',  NULL), 
('00010',1, 21,'Sheet', 'Step1_Name3_Status','released', NULL), 

('00020',1, 1, 'Sheet', 'Part',    'B',   NULL), 
('00020',1, 2, 'Sheet', 'Name',    'PartName',  NULL), 
('00020',1, 3, 'Sheet', 'Price',   NULL,   2.190), 
('00020',1, 4, 'Sheet', 'Step0_SOP',  '2016 CW 19', NULL), 
('00020',1, 5, 'Sheet', 'Step1_SOP',  '2016 CW 20', NULL), 
('00020',1, 6, 'Sheet', 'Step2_SOP',  '2015 CW 21', NULL), 
('00020',1, 7, 'Sheet', 'Step0_Status',  'released',  NULL), 
('00020',1, 8, 'Sheet', 'Step1_Status',  'frozen',  NULL), 
('00020',1, 9, 'Sheet', 'Step2_Status',  'pending',  NULL), 
('00020',1, 10,'Sheet', 'Step0_Name1',  'Xuser',  NULL), 
('00020',1, 11,'Sheet', 'Step0_Name2',  NULL,   NULL), 
('00020',1, 12,'Sheet', 'Step0_Name3',  'Wuser',  NULL), 
('00020',1, 13,'Sheet', 'Step0_Name1_Status','started',  NULL), 
('00020',1, 14,'Sheet', 'Step0_Name2_Status',NULL,   NULL), 
('00020',1, 15,'Sheet', 'Step0_Name3_Status','pending',  NULL), 
('00020',1, 16,'Sheet', 'Step1_Name1',  'Auser',  NULL), 
('00020',1, 17,'Sheet', 'Step1_Name2',  'Cuser',  NULL), 
('00020',1, 18,'Sheet', 'Step1_Name3',  'Buser',  NULL), 
('00020',1, 19,'Sheet', 'Step1_Name1_Status','frozen',  NULL), 
('00020',1, 20,'Sheet', 'Step1_Name2_Status','pending',  NULL), 
('00020',1, 21,'Sheet', 'Step1_Name3_Status','released', NULL) 

Создать TestOutput:

CREATE TABLE [dbo].[TestOutput](
    [ID] [nchar](5) NOT NULL, 
    [StepCount] [int] NULL 
    [StepNo] [int] NULL, 
    [Name] [nvarchar](max) NULL, 
    [Status] [nvarchar](max) NULL 
    ) 

Вставка TestOutput:

INSERT INTO [dbo].[TestOutput] ([ID] ,[StepCount] ,[StepNo],[Name],[Status]) 
Values 
('00010',1, 0, 'Auser', 'started'), 
('00010',2, 0, NULL, NULL), 
('00010',3, 0, 'Buser', 'pending'), 
('00010',1, 1, 'Wuser', 'released'), 
('00010',2, 1, 'Cuser', 'pending'), 
('00010',3, 1, 'Duser', 'released'), 

('00020',1, 0, 'Xuser', 'started'), 
('00020',2, 0, NULL, NULL), 
('00020',3, 0, 'Wuser', 'pending'), 
('00020',1, 1, 'Auser', 'frozen'), 
('00020',2, 1, 'Cuser', 'pending'), 
('00020',3, 1, 'Buser', 'released') 

Я надеюсь, что вы можете показать мне путь, как это может быть решена.

спасибо.

Answer 1

Там нет необходимости для курсора.

Вы могли бы сначала получить StepNo, а затем вычислить StepCount с использованием оконной функции и присоединиться результаты:

SELECT s1.ID, 
     s1.StepCount, 
     s1.StepNo, 
     [Name]  = s1.Column3, 
     [Status] = s2.Column3 
FROM (SELECT *, 
     [StepCount] = ROW_NUMBER() OVER (PARTITION BY ID, StepNo ORDER BY RowNumber) 
     FROM (SELECT *, 
       [StepNo] = SUBSTRING(Column2, 5, CHARINDEX('_', Column2)-5) 
      FROM Test 
      WHERE Column2 LIKE 'Step%_Name%' 
       AND Column2 NOT LIKE '%Status') AS sub) AS s1 
JOIN (SELECT *, 
     [StepCount] = ROW_NUMBER() OVER (PARTITION BY ID, StepNo ORDER BY RowNumber) 
     FROM (SELECT *, 
      [StepNo] = SUBSTRING(Column2, 5, CHARINDEX('_', Column2)-5) 
      FROM Test 
      WHERE Column2 LIKE 'Step%_Name%_Status') AS sub) AS s2 
    ON s1.ID = s2.ID 
AND s1.StepCount = s2.StepCount 
AND s1.StepNo = s2.StepNo 
ORDER BY ID, StepNo, StepCount; 

LiveDemo

Выход:

╔═══════╦═══════════╦════════╦═══════╦══════════╗ 
║ ID ║ StepCount ║ StepNo ║ Name ║ Status ║ 
╠═══════╬═══════════╬════════╬═══════╬══════════╣ 
║ 00010 ║   1 ║  0 ║ Auser ║ started ║ 
║ 00010 ║   2 ║  0 ║  ║   ║ 
║ 00010 ║   3 ║  0 ║ Buser ║ pending ║ 
║ 00010 ║   1 ║  1 ║ Wuser ║ released ║ 
║ 00010 ║   2 ║  1 ║ Cuser ║ pending ║ 
║ 00010 ║   3 ║  1 ║ Duser ║ released ║ 
║ 00020 ║   1 ║  0 ║ Xuser ║ started ║ 
║ 00020 ║   2 ║  0 ║  ║   ║ 
║ 00020 ║   3 ║  0 ║ Wuser ║ pending ║ 
║ 00020 ║   1 ║  1 ║ Auser ║ frozen ║ 
║ 00020 ║   2 ║  1 ║ Cuser ║ pending ║ 
║ 00020 ║   3 ║  1 ║ Buser ║ released ║ 
╚═══════╩═══════════╩════════╩═══════╩══════════╝ 

---

То же самое с КТР:

;WITH cte_name AS 
(
    SELECT *, 
     [StepCount] = ROW_NUMBER() OVER (PARTITION BY ID, StepNo ORDER BY RowNumber) 
    FROM (SELECT *, 
      [StepNo] = SUBSTRING(Column2, 5, CHARINDEX('_', Column2)-5) 
     FROM #Test 
     WHERE Column2 LIKE 'Step%_Name%' 
     AND Column2 NOT LIKE '%Status') AS sub 
), cte_status AS 
(
    SELECT *, 
     [StepCount] = ROW_NUMBER() OVER (PARTITION BY ID, StepNo ORDER BY RowNumber) 
    FROM (SELECT *, 
      [StepNo] = SUBSTRING(Column2, 5, CHARINDEX('_', Column2)-5) 
     FROM #Test 
     WHERE Column2 LIKE 'Step%_Name%_Status') AS sub 
) 
SELECT s1.ID, 
     s1.StepCount, 
     s1.StepNo, 
     [Name]  = s1.Column3, 
     [Status] = s2.Column3 
FROM cte_name s1 
JOIN cte_status s2 
    ON s1.ID = s2.ID 
AND s1.StepCount = s2.StepCount 
AND s1.StepNo = s2.StepNo 
ORDER BY ID, StepNo, StepCount; 

Answer 2

Попробуйте это:

select 
    t.id 
    ,row_number() over(
    partition by t.id, 
        substring(t.column2, 1, charindex('_', t.column2)) 
    order by t.column2 
) StepCount 
    ,substring(t.column2, 5, charindex('_', t.column2) - 5) [StepNo] 
    ,t.column3 [Name] 
    ,(
    select 
     t1.column3 
    from 
     @test t1 
    where 
     t.column2 + '_Status' = t1.column2 
     and t1.id = t.id 
) [Status] 
from 
    @test t 
where 
    t.column2 like 'step[0-9]_name[0-9]' 
;