-4
Я обещаю, это будет последний вопрос сегодня. Но я получил ошибку «Warning: mysql_fetch_assoc(): поставляется аргумент не является допустимым MySQL результаты ресурс в /home/a1014025/public_html/practice/cart/cart.php на линии 58» с этим кодом:Предупреждение: mysql_fetch_assoc(): предоставленный аргумент не является допустимым ресурсом результата MySQL в PHP?
<?php
include('connect.php');
session_start();
?>
<html>
<head>
<title>Cart</title>
<link rel='stylesheet' href='css/main.css' />
</head>
<body>
<?php
$page = 'index.php';
if(isset($_GET['add'])){
$add_id = $_GET['add'];
$quantity = mysql_query("SELECT id, quantity FROM products WHERE id='$add_id'");
while($quantity_row = mysql_fetch_assoc($quantity)){
if($quantity_row['quantity'] [email protected]$_SESSION['cart_'.$add_id]){
@$_SESSION['cart_'.$_GET['add']]+='1';
header('Location: index.php');
}
else{
header('Location: index.php?err=max');
}
}
}
if(isset($_GET['remove'])){
$_SESSION['cart_'.(int)$_GET['remove']]--;
header("Location: index.php");
}
if(isset($_GET['delete'])){
$_SESSION['cart_'.(int)$_GET['delete']]='0';
header('Location: index.php');
}
function products(){
$get = mysql_query("SELECT id, name, description, price FROM products WHERE quantity > 0 ORDER BY id DESC");
if(mysql_num_rows($get) == 0){
echo "There are no products to display.";
}
else{
while($get_row = mysql_fetch_assoc($get)){
echo '<p>'.$get_row['name'].'<br />'.$get_row['description'].'<br />$'.$get_row['price'].' <a href="cart.php?add='.$get_row['id'].'">Add</a></p>';
}
}
}
function paypal_items(){
$num = 0;
foreach($_SESSION as $name => $value){
if($value!=0){
if(substr($name, 0, 5) == 'cart_'){
$id = substr($name, 5, strlen($name)-5);
$get = mysql_query("SELECT id, name, price, shipping, shipping2 FROM products WHERE id=".$id);
while($get_row = mysql_fetch_assoc($get)){
$num++;
echo '<input type="hidden" name="item_number_'.$num.'" value="'.$id.'">';
echo '<input type="hidden" name="item_name_'.$num.'" value="'.$get_row['name'].'">';
echo '<input type="hidden" name="amount_'.$num.'" value="'.$get_row['price'].'">';
echo '<input type="hidden" name="shipping_'.$num.'" value="'.$get_row['shipping'].'">';
echo '<input type="hidden" name="shipping2_'.$num.'" value="'.$get_row['shipping2'].'">';
echo '<input type="hidden" name="quantity_'.$num.'" value="'.$value.'">';
}
}
}
}
}
function cart(){
$total = 0;
foreach($_SESSION as $name => $value){
if($value>0){
if(substr($name, 0, 5)=='cart_'){
$id = substr($name, 5, strlen($name)-5);
$get = mysql_query("SELECT id, name, price FROM products WHERE id='$id'");
while($get_row = mysql_fetch_assoc($get)){
$sub = $get_row['price']*$value;
echo $get_row['name'].' x '.$value.' @ $'.number_format($get_row['price'], 2).' = $'.$sub.' <a href="cart.php?add='.$id.'">[+]</a> <a href="cart.php?remove='.$id.'">[-]</a> <a href="cart.php?delete='.$id.'">[Delete]</a><br />';
}
}
$total += $sub;
}
}
if($total==0){
echo "You cart is empty.";
}
else{
echo "<p>Checkout with PayPal for your $".$total." total.</p>";
?>
<form action="https://www.paypal.com/cgi-bin/webscr" method="post">
<input type="hidden" name="cmd" value="_cart">
<input type="hidden" name="upload" value="1">
<input type="hidden" name="business" value="[email protected]">
<?php paypal_items(); ?>
<input type="hidden" name="currency_code" value="USD">
<input type="hidden" name="amount" value="<?php echo $total; ?>">
<input type="image" src="http://www.paypal.com/en_US/i/btn/x-click-but03.gif" name="submit" alt="Make payments with PayPal - it's fast, free and secure!">
</form>
<?php
}
}
?>
</body>
Считаете ли вы, что ищете свою проблему в Google? http://i.imgur.com/2YxuPMi.png –
Да, но я ничего не нашел, поэтому пришел сюда. – WorldxFree
Повторите поиск https://www.google.com/search?q=Warning%3A+mysql_fetch_assoc()%3A+supplied+argument+is+not+a+valid+MySQL+result+resource –