MSSQL вопрос таблица запроса

Question

может кто-то показать мне путь, чтобы получить правильные результаты данных использования MSSQL между двумя таблицами, как показано ниже

**Person_Table**   **Departemnt_Table** 
===========     ================ 
person_id     depatment_id 
age       department name 
gender       
department_id 

И я хочу, чтобы получить результат, как и следующие столбцы:

Department Names, 
Number under 20 aged Males in each department, 
number of under 20 aged Females in each department, 
total number of Males in each department, 
total number of Females in each department and, 
Total number of Persons in each department 

пример результат должен выглядеть так

DepartmentName|(Under20)Male|(Under20)Female|Total(M)| Total(F)| Grand Total 
Department1 | 1  | 3   | 1  | 3  | 4 
Department2 | 3  | 1   | 15 | 1  | 16 
Department3 | 0  | 0   | 0  | 0  | 0 

Answer 1

Вы должны Youse предложения GROUP BY с агрегатной функцией с.

SELECT DT.DepartmentName, 
     SUM(CASE WHEN PT.age < 20 AND PT.gender='MALE' THEN 1 ELSE 0 END) As [(Under20)Male] 
     ,SUM(CASE WHEN PT.age < 20 AND PT.gender='FEMALE' THEN 1 ELSE 0 END) As [(Under20)FeMale], 
     ,SUM(CASE WHEN PT.gender='MALE' THEN 1 ELSE 0 END) As [Total(M)] 
     ,SUM(CASE WHEN PT.gender='FEMALE' THEN 1 ELSE 0 END) As [Total(F)] 
     ,COUNT(*) As [Grand Total] 
FROM Departemnt_Table DT 
INNER JOIN Person_Table PT ON DT.depatment_id = PT.depatment_id 
GROUP BY DT.DepartmentName 

Answer 2

DECLARE @Person TABLE(person_id int null, 
age int null, 
gender varchar(10) null, 
department_id INT null) 

DECLARE @Department TABLE(
department_id INT, DepartmentName Varchar(200)) 

INSERT INTO @Department VALUES (1,'A') 
INSERT INTO @Department VALUES (2,'B') 
INSERT INTO @Department VALUES (3,'C') 
INSERT INTO @Department VALUES (4,'D') 

INSERT INTO @Person VALUES (1,19,'M',1) 
INSERT INTO @Person VALUES (2,12,'F',1) 
INSERT INTO @Person VALUES (3,30,'M',1) 
INSERT INTO @Person VALUES (4,40,'F',1) 

INSERT INTO @Person VALUES (5,20,'M',2) 
INSERT INTO @Person VALUES (6,12,'F',2) 
INSERT INTO @Person VALUES (7,30,'M',2) 
INSERT INTO @Person VALUES (8,40,'F',2) 

INSERT INTO @Person VALUES (9,20,'M',3) 
INSERT INTO @Person VALUES (10,12,'F',3) 
INSERT INTO @Person VALUES (11,30,'M',3) 
INSERT INTO @Person VALUES (12,40,'F',3) 

INSERT INTO @Person VALUES (13,20,'M', 4) 
INSERT INTO @Person VALUES (14,12,'F',4) 
INSERT INTO @Person VALUES (15,30,'M',4) 
INSERT INTO @Person VALUES (16,17,'F',4) 


Select D.DepartmentName , 
SUM([(Under20)Male]) [(Under20)Male], 
SUM([(Under20)Female])[(Under20)Female], 
SUM([Total(M)]) [Total(M)], 
SUM([ Total(F)]) [ Total(F)], 
SUM([Grand Total]) [Grand Total] 
FROM 

(

Select department_id,COUNT(*) as [(Under20)Male],0 [(Under20)Female],0 [Total(M)],0 [ Total(F)],0 [Grand Total] From @Person WHERE age<20 and gender='M' group by department_id 
Union all 
Select department_id,0 as [(Under20)Male],COUNT(*) [(Under20)Female],0 [Total(M)],0 [ Total(F)],0 [Grand Total] From @Person WHERE age<20 and gender='F' group by department_id 
Union all 
Select department_id,0 as [(Under20)Male],0 [(Under20)Female],COUNT(*) [Total(M)],0 [ Total(F)],0 [Grand Total] From @Person WHERE gender='M' group by department_id 
Union all 
Select department_id,0 as [(Under20)Male],0 [(Under20)Female],0 [Total(M)],COUNT(*) [ Total(F)],0 [Grand Total] From @Person WHERE gender='F' group by department_id 
union all 
Select department_id,0 as [(Under20)Male],0 [(Under20)Female],0 [Total(M)],0 [ Total(F)],COUNT(*) [Grand Total] From @Person group by department_id 
)A 

INNER JOIN 
@Department D 

ON A.department_id=D.department_id 
GROUP BY D.DepartmentName