Выберите количество из двух разных таблиц без подзадача в подзапросе

Question

Я пытаюсь сделать подсчет из нескольких таблиц в том же запросе, и результаты для 2 из них полностью ошибочны. Я следующие 3 таблицы, используемые в этом запросе:

CREATE TABLE `assignments` (
    `id` int(11) NOT NULL, 
    `lead_id` int(11) NOT NULL, 
    `buyer_id` int(11) NOT NULL, 
    `refunded` int(11) NOT NULL DEFAULT '0', 
    `date_assigned` int(11) NOT NULL, 
    `date_refunded` int(11) DEFAULT NULL 
) ENGINE=MyISAM DEFAULT CHARSET=utf8; 

CREATE TABLE `leads` (
    `id` int(11) NOT NULL, 
    `vertical_id` int(11) NOT NULL, 
    `source_id` int(11) NOT NULL, 
    `agent_id` varchar(255) DEFAULT NULL, 
    `status_id` int(11) NOT NULL DEFAULT '0', 
    `completeness` enum('Partial','Complete') DEFAULT NULL, 
    `freshness` enum('New','Duplicate') NOT NULL, 
    `date_created` int(11) NOT NULL, 
    `date_updated` int(11) NOT NULL, 
) ENGINE=MyISAM DEFAULT CHARSET=utf8; 

CREATE TABLE `verticals` (
    `id` int(11) NOT NULL, 
    `name` varchar(255) NOT NULL, 
) ENGINE=MyISAM DEFAULT CHARSET=utf8; 

То, что я хочу сделать, это приводит захватить и поместить их в таблицу, как это:

Name  New Duplicate Partial Complete Total Assigned Refunded 
Automotive 4 1   3  2  5  36  9 
Education 16 7   9  14  23 36  9 

Первые 5 номеров столбцов являются правильными , Проблема в том, что присвоенные и возвращенные номера столбцов являются полностью неправильными. Вот мой запрос:

select v.*, 
(select count(*) from `leads` where vertical_id=v.id and `freshness`='New' and `date_created` between 1470009600 and 1471923227) as `new`, 
(select count(*) from `leads` where vertical_id=v.id and `freshness`='Duplicate' and `date_created` between 1470009600 and 1471923227) as `duplicate`, 
(select count(*) from `leads` where vertical_id=v.id and `completeness`='Partial' and `date_created` between 1470009600 and 1471923227) as `partial`, 
(select count(*) from `leads` where vertical_id=v.id and `completeness`='Complete' and `date_created` between 1470009600 and 1471923227) as `complete`, 
(select count(*) from `leads` where vertical_id=v.id and `date_created` between 1470009600 and 1471923227) as `total`, 
(select count(*) from `assignments` where lead_id=l.id and `refunded`=0) as `assigned`, 
(select count(*) from `assignments` where lead_id=l.id and `refunded`=1) as `refunded` 
from `verticals` as v 
left join `leads` as l on (l.vertical_id = v.id) 
where l.date_created between 1470009600 and 1471923227 
group by v.id 

Как я могу исправить это без использования подвыбора внутри подзапросов (что было бы ужасно для производительности)?

EDIT: Я считаю, что почти у это работает, но там должен быть лучший способ, чтобы написать этот запрос (также, это, кажется, группируя assignments по lead_id):

select o.*, 
(select count(*) from `leads` where {$sql_column}=o.id and `freshness`='New' and `date_created` between {$date_from} and {$date_to}) as `new`, 
(select count(*) from `leads` where {$sql_column}=o.id and `freshness`='Duplicate' and `date_created` between {$date_from} and {$date_to}) as `duplicate`, 
(select count(*) from `leads` where {$sql_column}=o.id and `completeness`='Partial' and `date_created` between {$date_from} and {$date_to}) as `partial`, 
(select count(*) from `leads` where {$sql_column}=o.id and `completeness`='Complete' and `date_created` between {$date_from} and {$date_to}) as `complete`, 
(select count(*) from `leads` where {$sql_column}=o.id and `date_created` between {$date_from} and {$date_to}) as `total`, 
(select count(*) from `assignments` where `lead_id` in 
    (select `id` from `leads` where {$sql_column}=o.id and `date_created` between {$date_from} and {$date_to}) and `refunded`=0) as `assigned`, 
(select count(*) from `assignments` where `lead_id` in 
    (select `id` from `leads` where {$sql_column}=o.id and `date_created` between {$date_from} and {$date_to}) and `refunded`=1) as `refunded` 
from {$sql_object} as o 

Answer 1

select v.*,COUNT(CASE WHEN `freshness`='New' THEN freshness END) as new,COUNT(CASE WHEN `freshness`='Duplicate' THEN freshness END) as duplicate from `verticals` as v left join `leads` as l on (l.vertical_id = v.id) where l.date_created between 1470009600 and 1471923227 group by v.id 

Надеюсь, это поможет. попробуй.

Answer 2

Учитывая эти данные

/* 
truncate table verticals; 
INSERT INTO VERTICALS VALUES 
(1,'Automotive'),(2,'Educational'); 

truncate table leads; 
insert into leads values 
(1,1,1,1,1,'Partial','New', 1470009600, 1470009600), 
(2,2,1,1,1,'Partial','New', 1470009600, 1470009600), 
(3,1,1,1,1,'Partial','Duplicate', 1470009600, 1470009600), 
(4,2,1,1,1,'Partial','Duplicate', 1470009600, 1470009600), 
(5,1,1,1,1,'Complete','New', 1470009600, 1470009600), 
(6,2,1,1,1,'Complete','New', 1470009600, 1470009600), 
(7,1,1,1,1,'Complete','Duplicate', 1470009600, 1470009600), 
(8,2,1,1,1,'Complete','Duplicate', 1470009600, 1470009600), 
(9,1,1,1,1,'Complete','New', 1470009600, 1470009600), 
(10,1,1,1,1,'Complete','Duplicate', 1470009600, 1470009600); 

truncate table assignments; 
insert into assignments values 
(1,1,1,0,1470009600, 1470009600), 
(2,2,1,1,1470009600, 1470009600), 
(3,3,1,0,1470009600, 1470009600), 
(4,4,1,1,1470009600, 1470009600), 
(5,5,1,1,1470009600, 1470009600); 
*/ 

Этот запрос

select v.*, 
SUM(CASE WHEN L.`freshness`='New' THEN 1 ELSE 0 END) as `new`, 
SUM(CASE WHEN L.`freshness`='Duplicate' THEN 1 ELSE 0 END) AS `duplicate`, 
SUM(CASE WHEN L.`completeness`='Partial' THEN 1 ELSE 0 END) as `partial`, 
SUM(CASE WHEN L.`completeness`='Complete' THEN 1 ELSE 0 END) as `complete`, 
count(L.id) as `total`, 
SUM(CASE WHEN A.`refunded`=0 THEN 1 ELSE 0 END) as `assigned`, 
SUM(CASE WHEN A.`refunded`=1 THEN 1 ELSE 0 END) as `refunded` 
from `verticals` as v 
left join `leads` as l on (l.vertical_id = v.id) AND (l.date_created between 1470009600 and 1471923227) 
LEFT JOIN ASSIGNMENTS A ON A.LEAD_ID = L.ID 
group by v.id 

Результаты

+----+-------------+------+-----------+---------+----------+-------+----------+----------+ 
| id | name  | new | duplicate | partial | complete | total | assigned | refunded | 
+----+-------------+------+-----------+---------+----------+-------+----------+----------+ 
| 1 | Automotive | 3 |   3 |  2 |  4 |  6 |  2 |  1 | 
| 2 | Educational | 2 |   2 |  2 |  2 |  4 |  0 |  2 | 
+----+-------------+------+-----------+---------+----------+-------+----------+----------+