Android JSON Исключение - JSONArray не могут быть преобразованы в JSONObject

Question

Я пытаюсь читать JSon URL-адрес

Мой код:

// Creating JSON Parser instance 
JSONParser jParser = new JSONParser(); 

// getting JSON string from URL 
JSONObject json = jParser.getJSONFromUrl(url); 

Если я исполню мой код, я не в состоянии получить строку из URL

Вот мой LogCat Ошибка:

06-04 17:13:45.162: E/JSON Parser(15988): Error parsing data org.json.JSONException: Value ["<a href='http:\/\/freshersadda.com\/jsonFeed\/faJsonFeedDetails.php?jid=12036'>SPICE JET Recruits Freshers Data Entry Operator in Gurgaon<\/a><br><br><br>","<a href='http:\/\/freshersadda.com\/jsonFeed\/faJsonFeedDetails.php?jid=12035'>TOSHIBA Freshers off Campus Drive Trainee Engineers in Bangalore <\/a><br><br><br>","<a href='http:\/\/freshersadda.com\/jsonFeed\/faJsonFeedDetails.php?jid=12034'>EMC Corporation Recruits Fresher Jobs Technical Support Engineers in bangalore<\/a><br><br><br>","<a href='http:\/\/freshersadda.com\/jsonFeed\/faJsonFeedDetails.php?jid=12033'>AON Hewitt Freshers Walk in Drive 4th to 8th June in Chennai<\/a><br><br><br>","<a href='http:\/\/freshersadda.com\/jsonFeed\/faJsonFeedDetails.php?jid=12032'>APPLIED MATERIALS Recruits Fresher Jobs Software Engineer on June in Bangalore<\/a><br><br><br>","<a href='http:\/\/freshersadda.com\/jsonFeed\/faJsonFeedDetails.php?jid=12031'>US TECH Solutions Recruits Off-Campus Drive: Trainee on 14th June in Panipat<\/a><br><br><br>","<a href='http:\/\/freshersadda.com\/jsonFeed\/faJsonFeedDetails.php?jid=12030'>SURPRISE SOLUTIONS Fresher Walk-in Software Engineer on 5th to 15th June in Chennai <\/a><br><br><br>","<a href='http:\/\/freshersadda.com\/jsonFeed\/faJsonFeedDetails.php?jid=12029'>MPHASIS Freshers Walk-in: Associate\/Senior Associate on 4th & 5th June in Bangalore<\/a><br><br><br>","<a href='http:\/\/freshersadda.com\/jsonFeed\/faJsonFeedDetails.php?jid=12028'>ARROWSOFTWARE Technologies Recruits MBA Jobs: HR Last Date: 10th June in Hyderabad<\/a><br><br><br>","<a href='http:\/\/freshersadda.com\/jsonFeed\/faJsonFeedDetails.php?jid=12027'>NUA TRANS MEDIA Fresher Walk-in: Trainee - Developer On 5th to 7th June in Chennai<\/a><br><br><br>","<a href='http:\/\/freshersadda.com\/jsonFeed\/faJsonFeedDetails.php?jid=12026'>PCS Technology Recruits IT Helpdesk \/ Call Co Coordinator in Chennai<\/a><br><br><br>","<a href='http:\/\/freshersadda.com\/jsonFeed\/faJsonFeedDetails.php?jid=12025'>ICICI Bank Recruits Bank Jobs Chartered Accountants<\/a><br><br><br>","<a href='http:\/\/freshersadda.com\/jsonFeed\/faJsonFeedDetails.php?jid=12024'>BIOCON Recruits Engineering Jobs Executive\/ Jr Executive<\/a><br><br><br>","<a href='http:\/\/freshersadda.com\/jsonFeed\/faJsonFeedDetails.php?jid=12023'>INTEL Technology Recruits Engineering Jobs Research Intern<\/a><br><br><br>","<a href='http:\/\/freshersadda.com\/jsonFeed\/faJsonFeedDetails.php?jid=12022'>SUTHERLAND global Recruits Healthcare Jobs Medical Coder <\/a><br><br><br>"] of type org.json.JSONArray cannot be converted to JSONObject 

Может кто-нибудь помочь?

Answer 1

Значение, которое вы получаете от URL-адреса, это JSONArray, а не объект JSONOB. (То, что означают квадратные скобки). Попробуйте следующее:

JSONArray json = jParser.getJSONFromUrl(url); 
JSONObject firstObject = json.getJSONObject(0); 
JSONObject secondObject = json.getJSONObject(1); 
...etc 

Answer 2

Это потому, что JSONArray не является ребенком JSONObject.

JSONArray распространяется только на java.lang.Object.

Сигнатура класса JSONArray является:

public class org.json.JSONArray { 
    ... class body ... 
} 

Answer 3

Ключ находится в конце, за исключением: ... of type org.json.JSONArray cannot be converted to JSONObject. JSON по данному URL-адресу действителен JSON, но в форме JSONArray, а не JSONObject.

Попробуйте изменить линию на JSONArray json = jParser.getJSONFromUrl(url);, и она должна работать.