Я нахожусь в курсе начинающего CS, и я пытаюсь написать программу на C, которая запрашивает двухзначное число и возвращает выписанную форму этого числа. Я написал весь код, и он работает, когда я пробую цифры 10-19, но не другие. Составлено с использованием стандарта C89, если это имеет значениеПочему логические операторы работают не так, как ожидалось?
#include <stdio.h>
int main(void)
{
printf("\n Number to Word Conversion Program");
printf("\n\n This program takes a two-digit number and outputs the English word for the number");
int number = 0;
int numberH1 = 0;
int numberH2 = 0;
printf("\n\n Please enter a two-digit number: ");
scanf("%d", &number);
numberH1 = number/10;
numberH2 = number % 10;
if (number == 10 || 11 || 12 || 13 || 14 || 15 || 16 || 17 ||18 || 19)
{
switch (number)
{
case 10:
{
printf("\n\n The number entered was Ten.\n\n");
}
break;
case 11:
{
printf("\n\n The number entered was Eleven.\n\n");
}
break;
case 12:
{
printf("\n\n The number entered was Twelve.\n\n");
}
break;
case 13:
{
printf("\n\n The number entered was Thirteen.\n\n");
}
break;
case 14:
{
printf("\n\n The number entered was Fourteen.\n\n");
}
break;
case 15:
{
printf("\n\n The number entered was Fifteen.\n\n");
}
break;
case 16:
{
printf("\n\n The number entered was Sixteen.\n\n");
}
break;
case 17:
{
printf("\n\n The number entered was Seventeen.\n\n");
}
break;
case 18:
{
printf("\n\n The number entered was Eighteen.\n\n");
}
break;
case 19:
{
printf("\n\n The number entered was Nineteen.\n\n");
}
break;
}
}
else
{
switch (numberH1)
{
case 2:
{
printf("\n\n The numer entered was Twenty");
}
break;
case 3:
{
printf("\n\n The numer entered was Thirty");
}
break;
case 4:
{
printf("\n\n The numer entered was Forty");
}
break;
case 5:
{
printf("\n\n The numer entered was Fifty");
}
break;
case 6:
{
printf("\n\n The numer entered was Sixty");
}
break;
case 7:
{
printf("\n\n The numer entered was Seventy");
}
break;
case 8:
{
printf("\n\n The numer entered was Eighty");
}
break;
case 9:
{
printf("\n\n The numer entered was Ninety");
}
break;
}
switch (numberH2)
{
case 0:
{
printf(".\n\n");
}
break;
case 1:
{
printf("-one.\n\n");
}
break;
case 2:
{
printf("-two.\n\n");
}
break;
case 3:
{
printf("-three.\n\n");
}
break;
case 4:
{
printf("-four.\n\n");
}
break;
case 5:
{
printf("-five.\n\n");
}
break;
case 6:
{
printf("-six.\n\n");
}
break;
case 7:
{
printf("-seven.\n\n");
}
break;
case 8:
{
printf("-eight.\n\n");
}
break;
case 9:
{
printf("-nine.\n\n");
}
break;
}
}
return 0;
}
'if (number == 10 || 11 || 12 || 13 || 14 || 15 || 16 || 17 || 18 || 19) '->' if (9
BLUEPIXY
Это код спагетти. Используйте массив строк, пожалуйста ... –