UPDATE данных не работает с PHP MySQL

Question

Я с простым заявлением UPDATE MySQL, выбирая id_pt из таблицы tbl_pt и обновления не рабочей появляется ошибка You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'WHERE id_pt = '1'' at line 6

простой код для обновления aksi_identitas.php

<?php 
session_start(); 
if (empty($_SESSION['namauser']) AND empty($_SESSION['passuser'])){ 
    echo "<link href='style.css' rel='stylesheet' type='text/css'> 
<center>Untuk mengakses modul, Anda harus login <br>"; 
    echo "<a href=../../index.php><b>LOGIN</b></a></center>"; 
} 
else{ 
include "../../../config/koneksi.php"; 

$module=$_GET[module]; 
$act=$_GET[act]; 

// Update identitas 
if ($module=='identitas' AND $act=='update'){ 

    $c = mysql_query("UPDATE tbl_pt SET nama_pt = '$_POST[nama_pt]', 
              alamat_pt = '$_POST[alamat_pt]', 
              phone_pt  = '$_POST[phone_pt]', 
               email_pt = '$_POST[email_pt]', 
               fax_pt  = '$_POST[fax_pt]', 
           WHERE id_pt = '$_POST[id]'"); 
    if ($c) { 
     header('location:../../media.php?module='.$module); 
    }else{ 
     echo "Gagal ".mysql_error(); 
    } 
    } 
} 
?> 

И identitas.php

<?php 
    $aksi="modul/mod_identitas/aksi_identitas.php"; 
    switch($_GET[act]){ 
    // Tampil identitas 
    default: 
    $sql = mysql_query("SELECT * FROM tbl_pt LIMIT 1"); 
    $r = mysql_fetch_array($sql); 


    echo " 
    <div id='main-content'> 
    <div class='container_12'> 
    <div class='grid_12'> 
    </div> 

    <div class='grid_12'> 
    <div class='block-border'> 
    <div class='block-header'> 
    <h1>IDENTITAS PERUSAHAAN</h1> 
    <span></span> 
    </div> 
    <div class='block-content'> 

    <form method=POST enctype='multipart/form-data' action=$aksi?module=identitas&act=update> 
    <input type=hidden name=id value=$r[id_pt]> 

    <p class=inline-small-label> 
    <label for=field4>Nama Perusahaan</label> 
    <input type=text name='nama_pt' size=50 value='$r[nama_pt]'> 
    </p>  

    <p class=inline-small-label> 
    <label for=field4>Alamat Perusahaan</label> 
    <input type=text name='alamat_pt' size=50 value='$r[alamat_pt]'> 
    </p> 

    <p class=inline-small-label> 
    <label for=field4>Telepon Perusahaan</label> 
    <input type=text name='phone_pt' size=50 value='$r[phone_pt]'> 
    </p> 

    <p class=inline-small-label> 
    <label for=field4>Email Perusahaan</label> 
    <input type=text name='email_pt' size=50 value='$r[email_pt]'> 
    </p> 

    <p class=inline-small-label> 
    <label for=field4>Fax Perusahaan</label> 
    <input type=text name='fax_pt' size=50 value='$r[fax_pt]'> 
    </p>"; 

    echo "<div class=block-actions> 
     <ul class=actions-right> 
     <li> 
     <a class='button red' id=reset-validate-form href='?module=identitas'>Batal</a> 
     </li> </ul> 
     <ul class=actions-left> 
     <li> 
     <input type='submit' name='upload' class='button' value='&nbsp;&nbsp;&nbsp;&nbsp; Simpan &nbsp;&nbsp;&nbsp;&nbsp;'> 
     </form>"; 

    break; 
    } 
    ?> 


    </div> 
    </div> 
    </div> 
    <div class='clear height-fix'></div> 
    </div></div> 

Любая помощь будет оценена Спасибо!

Answer 1

Там есть дополнительная запятая, прежде чем WHERE