Извлечение телефонного номера

Question

Я использую намерение восстановить номер телефона. он отображает список контактов. и теперь я хочу получить один контакт. но когда я нажал на какой-либо один контакт, получил исключение. это происходило во время получения номера, но исправлялось для получения имени контакта.

Intent intent = new Intent(Intent.ACTION_PICK); 
intent.setType(ContactsContract.Contacts.CONTENT_TYPE); 
startActivityForResult(intent, 2); 


Uri contactUri = data.getData(); 
     //String[] projection = {Phone.NUMBER}; 

       Cursor cursor = getContentResolver() 
       .query(contactUri, null, null, null, null); 
       cursor.moveToNext(); 

      // String name = cursor.getString(cursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME));// name got me. 
       String phone = cursor.getString(cursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER)); // exception for phone number. 

       System.out.println("name "+name+phone); 

LogCat: -

06-21 18:06:38.394: E/AndroidRuntime(30700): java.lang.RuntimeException: Failure delivering  result ResultInfo{who=null, request=2, result=-1, data=Intent { dat=content://com.android.contacts/contacts/lookup/1135r4-2727494D372D37.3754r14-2727494D372D37/4 }} to activity {com.MednymaSecureChat/com.MednymaSecureChat.XMPPClient}: java.lang.IllegalStateException: Couldn't read row 0, col -1 from CursorWindow. Make sure the Cursor is initialized correctly before accessing data from it. 
06-21 18:06:38.394: E/AndroidRuntime(30700): at android.app.ActivityThread.deliverResults(ActivityThread.java:2980) 
06-21 18:06:38.394: E/AndroidRuntime(30700): at android.app.ActivityThread.handleSendResult(ActivityThread.java:3023) 
06-21 18:06:38.394: E/AndroidRuntime(30700): at android.app.ActivityThread.access$1100(ActivityThread.java:123) 
06-21 18:06:38.394: E/AndroidRuntime(30700): at android.app.ActivityThread$H.handleMessage(ActivityThread.java:1177) 
06-21 18:06:38.394: E/AndroidRuntime(30700): at android.os.Handler.dispatchMessage(Handler.java:99) 
06-21 18:06:38.394: E/AndroidRuntime(30700): at android.os.Looper.loop(Looper.java:137) 
06-21 18:06:38.394: E/AndroidRuntime(30700): at android.app.ActivityThread.main(ActivityThread.java:4424) 
06-21 18:06:38.394: E/AndroidRuntime(30700): at java.lang.reflect.Method.invokeNative(Native Method) 
06-21 18:06:38.394: E/AndroidRuntime(30700): at java.lang.reflect.Method.invoke(Method.java:511) 
06-21 18:06:38.394: E/AndroidRuntime(30700): at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:817) 
06-21 18:06:38.394: E/AndroidRuntime(30700): at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:584) 
06-21 18:06:38.394: E/AndroidRuntime(30700): at dalvik.system.NativeStart.main(Native Method) 
06-21 18:06:38.394: E/AndroidRuntime(30700): Caused by: java.lang.IllegalStateException: Couldn't read row 0, col -1 from CursorWindow. Make sure the Cursor is initialized correctly before accessing data from it. 
06-21 18:06:38.394: E/AndroidRuntime(30700): at android.database.CursorWindow.nativeGetString(Native Method) 
06-21 18:06:38.394: E/AndroidRuntime(30700): at android.database.CursorWindow.getString(CursorWindow.java:442) 
06-21 18:06:38.394: E/AndroidRuntime(30700): at android.database.AbstractWindowedCursor.getString(AbstractWindowedCursor.java:51) 
06-21 18:06:38.394: E/AndroidRuntime(30700): at android.database.CursorWrapper.getString(CursorWrapper.java:114) 
06-21 18:06:38.394: E/AndroidRuntime(30700): at com.MednymaSecureChat.XMPPClient.onActivityResult(XMPPClient.java:480) 
06-21 18:06:38.394: E/AndroidRuntime(30700): at android.app.Activity.dispatchActivityResult(Activity.java:4654) 
06-21 18:06:38.394: E/AndroidRuntime(30700): at android.app.ActivityThread.deliverResults(ActivityThread.java:2976) 
06-21 18:06:38.394: E/AndroidRuntime(30700): ... 11 more 

пожалуйста кто-нибудь не поможет мне

Answer 1

Попробуйте этот код

@Override 
    public void onActivityResult(int requestCode, int resultCode, Intent intent) 
    { 
     if (requestCode == 2) 
     { 
     Uri contactUri = data.getData(); 
     //String[] projection = {Phone.NUMBER}; 

       Cursor cursor = getContentResolver() 
       .query(contactUri, null, null, null, null); 
       cursor.moveToNext(); 

      // String name = cursor.getString(cursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME));// name got me. 
       String phone = cursor.getString(cursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER)); // exception for phone number. 

       System.out.println("name "+name+phone); 
    } 
    } 

(или) Попробуйте ссылке ниже стека пост для приемистости контакта нет и имя это сработало для меня

Pick a Number and Name From Contacts List in android app

Answer 2

Intent intent = new Intent(Intent.ACTION_PICK, ContactsContract.Contacts.CONTENT_URI); 
startActivityForResult(intent, 1); 

// ... 

@Override 
public void onActivityResult(int reqCode, int resultCode, Intent data) { 
    super.onActivityResult(reqCode, resultCode, data); 
    if (resultCode == Activity.RESULT_OK) { 
     Uri contactData = data.getData(); 
     Cursor c = managedQuery(contactData, null, null, null, null); 
     if (c.moveToFirst()) { 
      String name = c.getString(c.getColumnIndexOrThrow(ContactsContract.Contacts.DISPLAY_NAME)); 
      Cursor phones = getContentResolver().query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI,null, 
    ContactsContract.CommonDataKinds.Phone.CONTACT_ID +" = "+ id,null, null); 
    phones.moveToFirst(); 
    String phone= phones.getString(phones.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER)); 
     tv.setText(name+" "+phone); 
     } 
    } 
}