Как обработать исключение метода SOAP на Android

Question

Я отправляю запрос на веб-службу, но я получил следующее исключение. Как я могу исправить эту проблему?

02-27 17:09:43.169: INFO/System.out(7904): Soap Method Error 
    ->SoapFault - faultcode: 'soap:Server' faultstring: 
    'Server was unable to process request. ---> Object reference not set to 
    an instance of an object.' faultactor: 'null' detail: 
    org.kxml2.kdom.Node@405b9a28 

Код:

public String RegisterUser(String unval,String eval,String pwdval,String cpwdval,String mnoval,String fnval, 
     String mnval, String lnval,String cityval,String stateval,String zcval) throws SoapFault 
{ 
    String data = ""; 
    String serviceUrl = RB_Constant.RB_Webservice_URL; 
    String serviceNamespace = RB_Constant.RB_Webservice_Namespace; 
    String soapAction = "http://www.roadbrake.com/RegisterNewUser"; 
    String type_of_soap = "RegisterNewUser"; 
    try 
    { 
     SoapObject Request = new SoapObject(serviceNamespace, type_of_soap); 
     Request.addProperty("strUserName", unval); 
     Request.addProperty("strEmail", eval); 
     Request.addProperty("strPassword", pwdval); 
     Request.addProperty("strConfirmPassword", cpwdval); 
     Request.addProperty("strMobileNumber", mnoval); 
     Request.addProperty("strFirstName",fnval); 
     Request.addProperty("strMiddleName",mnval); 
     Request.addProperty("strLastName",lnval); 
     Request.addProperty("strCity",cityval); 
     Request.addProperty("strState",stateval); 
     Request.addProperty("strZipcode",zcval); 
     Request.addProperty("strSource", "Android"); 

     System.out.println("request ->"+Request.toString()); 

     SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11); 
     envelope.dotNet = true; 
     envelope.setOutputSoapObject(Request); 

     try 
     { 
      HttpTransportSE androidHttpTransport = new HttpTransportSE(serviceUrl); 
      androidHttpTransport.call(soapAction, envelope); 
     } 
     catch(Exception e) 
     { 
      System.out.println("Webservice calling error ->"+e.toString()); 
     } 

     **// The app is crashed here** 

     SoapPrimitive response = (SoapPrimitive)envelope.getResponse(); 
     data = response.toString(); 
     System.out.println(" RB WS Response--"+response.toString()); 
    } 
    catch(Exception e) 
    { 
     System.out.println("Soap Method Error ->"+e.toString()); 
    } 
    return data; 
} 

Answer 1

Вы можете поймать это исключение, как показано ниже.

catch(SoapFault sf){ 
    //Do something upon a SOAP exception 
}