Загрузить OpenXML generated

Question

В настоящее время я создаю лист Excel в консольном приложении для тестирования. Мне нужно реализовать свой код на странице ASP.Net .aspx.

Как я могу предложить этот лист Excel пользователю для загрузки без сохранения его в любой форме на местном уровне?

Это мой код:

 static void Main(string[] args) 
    { 
     SpreadsheetDocument spreadsheetDocument = SpreadsheetDocument.Create(DateTime.Now.ToString("ddMMyyyyHHmmss") + @".xlsx", SpreadsheetDocumentType.Workbook); 

     WorkbookPart workbookpart = spreadsheetDocument.AddWorkbookPart(); 
     workbookpart.Workbook = new Workbook(); 

     // Add a WorksheetPart to the WorkbookPart. 
     WorksheetPart worksheetPart = workbookpart.AddNewPart<WorksheetPart>(); 
     worksheetPart.Worksheet = new Worksheet(new SheetData()); 

     // Add Sheets to the Workbook. 
     Sheets sheets = spreadsheetDocument.WorkbookPart.Workbook.AppendChild<Sheets>(new Sheets()); 

     // Append a new worksheet and associate it with the workbook. 
     Sheet sheet = new Sheet() 
     { 
      Id = spreadsheetDocument.WorkbookPart. 
      GetIdOfPart(worksheetPart), 
      SheetId = 1, 
      Name = "mySheet" 
     }; 

     sheets.Append(sheet); 

     Cell cell = InsertCellInWorksheet("A", 1, worksheetPart); 
     cell.CellValue = new CellValue("23.289374"); 
     cell.DataType = new EnumValue<CellValues>(CellValues.Number); 

     Cell cellString = InsertCellInWorksheet("B", 1, worksheetPart); 
     cellString.CellValue = new CellValue("hello"); 
     cellString.DataType = new EnumValue<CellValues>(CellValues.String); 

     // Close the document. 
     workbookpart.Workbook.Save(); 
     spreadsheetDocument.Close(); 
    } 

    // Given a column name, a row index, and a WorksheetPart, inserts a cell into the worksheet. 
    // If the cell already exists, returns it. 
    private static Cell InsertCellInWorksheet(string columnName, uint rowIndex, WorksheetPart worksheetPart) 
    { 
     Worksheet worksheet = worksheetPart.Worksheet; 
     SheetData sheetData = worksheet.GetFirstChild<SheetData>(); 
     string cellReference = columnName + rowIndex; 

     // If the worksheet does not contain a row with the specified row index, insert one. 
     Row row; 
     if (sheetData.Elements<Row>().Where(r => r.RowIndex == rowIndex).Count() != 0) 
     { 
      row = sheetData.Elements<Row>().Where(r => r.RowIndex == rowIndex).First(); 
     } 
     else 
     { 
      row = new Row() { RowIndex = rowIndex }; 
      sheetData.Append(row); 
     } 

     // If there is not a cell with the specified column name, insert one. 
     if (row.Elements<Cell>().Where(c => c.CellReference.Value == columnName + rowIndex).Count() > 0) 
     { 
      return row.Elements<Cell>().Where(c => c.CellReference.Value == cellReference).First(); 
     } 
     else 
     { 
      // Cells must be in sequential order according to CellReference. Determine where to insert the new cell. 
      Cell refCell = null; 
      foreach (Cell cell in row.Elements<Cell>()) 
      { 
       if (string.Compare(cell.CellReference.Value, cellReference, true) > 0) 
       { 
        refCell = cell; 
        break; 
       } 
      } 

      Cell newCell = new Cell() { CellReference = cellReference }; 
      row.InsertBefore(newCell, refCell); 

      worksheet.Save(); 
      return newCell; 
     } 
    } 

Answer 1

Используйте MemoryStream. например

public MemoryStream CreateSpreadSheet() 
{ 
    MemoryStream mem = new MemoryStream(); 
    SpreadsheetDocument spreadsheetDocument = SpreadsheetDocument. 
      Create(mem, SpreadsheetDocumentType.Workbook); 

    WorkbookPart workbookpart = spreadsheetDocument.AddWorkbookPart(); 
    workbookpart.Workbook = new Workbook(); 

    // Code omitted for brevity.... 

    // Close the document. 
    workbookpart.Workbook.Save(); 
    spreadsheetDocument.Close(); 
    return mem; 
} 

Затем вам нужно будет сделать что-то вроде этого в код вашей страницы ASPX:

using (MemoryStream mem = new CreateSpreadSheet(mem)) 
{ 
    Response.Clear(); 
    Response.ContentType = 
     @"application/vnd.openxmlformats-officedocument.spreadsheetml.sheet.main+xml"; 
    Response.AddHeader("content-disposition", "attachment;filename=name_your_file.xlsx"); 
    mem.WriteTo(Response.OutputStream); 
    Response.End(); 
}