Я планирую уведомление, которое будет запущено, когда сообщение получено службой Firebase, но проблема, с которой уведомление запускается дважды (один раз вовремя и второй раз через 30 минут), вот мой код :Firebase onMessageReceived запускается дважды
sharedPreferences = PreferenceManager
.getDefaultSharedPreferences(getApplicationContext());
// Check if message contains a data payload.
if (remoteMessage.getData().size() > 0) {
Intent myIntent = new Intent(MyFirebaseMessagingService.this, MyAlarmService.class);
pendingIntent = PendingIntent.getService(MyFirebaseMessagingService.this, 0, myIntent, 0);
AlarmManager alarmManager = (AlarmManager)getSystemService(ALARM_SERVICE);
long currentTime = System.currentTimeMillis();
int hour=sharedPreferences.getInt("Hour",9);
int min=sharedPreferences.getInt("Min",0);
Calendar calendar = Calendar.getInstance();
calendar.set(Calendar.HOUR_OF_DAY,hour);
calendar.set(Calendar.MINUTE,min);
alarmManager.set(AlarmManager.RTC_WAKEUP,calendar.getTimeInMillis() , pendingIntent);
Это MyAlarmService onStartCommand:
public int onStartCommand(Intent intent, int flags, int startId) {
Uri uri = RingtoneManager.getDefaultUri(RingtoneManager.TYPE_NOTIFICATION);
NotificationCompat.Builder mBuilder = new NotificationCompat.Builder(this);
mBuilder.setSmallIcon(R.mipmap.ic_launcher);
mBuilder.setContentTitle("Figures");
mBuilder.setContentText("New Figures has been updated!");
mBuilder.setAutoCancel(true);
mBuilder.setSound(uri);
Intent resultIntent = new Intent(this, LoginActivity.class);
TaskStackBuilder stackBuilder = TaskStackBuilder.create(this);
stackBuilder.addParentStack(LoginActivity.class);
stackBuilder.addNextIntent(resultIntent);
PendingIntent resultPendingIntent = stackBuilder.getPendingIntent(0, PendingIntent.FLAG_UPDATE_CURRENT);
mBuilder.setContentIntent(resultPendingIntent);
NotificationManager mNotificationManager = (NotificationManager) getSystemService(Context.NOTIFICATION_SERVICE);
mNotificationManager.notify(0, mBuilder.build());
return super.onStartCommand(intent, flags, startId);
}
А вот Vb.net отправки Функция уведомления:
Private Function sendNotification() As Integer
Try
Dim url As String = "https://fcm.googleapis.com/fcm/send"
Dim tRequest As WebRequest = WebRequest.Create(url)
tRequest.Method = "post"
tRequest.ContentType = "application/json"
Dim data = New With { _
Key .[to] =myTopic, _
Key .TTL = "109", _
Key .data = New With { _
Key .body = "Updated", _
Key .title = "Daily" _
} _
}
Dim jssons As String = Newtonsoft.Json.JsonConvert.SerializeObject(data)
Dim bytearray As Byte() = Encoding.UTF8.GetBytes(jssons)
tRequest.Headers.Add(String.Format("Authorization: key={0}", MyKey))
tRequest.Headers.Add(String.Format("Sender: id={0}", MySenderId))
tRequest.ContentLength = bytearray.Length
tRequest.ContentType = "application/json"
Using datastream As Stream = tRequest.GetRequestStream()
datastream.Write(bytearray, 0, bytearray.Length)
Using tresponse As WebResponse = tRequest.GetResponse
Using dataStreamResponse As Stream = tresponse.GetResponseStream()
Using tReader As StreamReader = New StreamReader(dataStreamResponse)
Dim sResponseFromServer As String = tReader.ReadToEnd()
Log(sResponseFromServer, w)
End Using
End Using
End Using
End Using
Catch ex As WebException
Log(ex.Message, w)
Return ex.Status
End Try
Log("Notification sent", w)
Return 200
End Function
есть ли лучший способ отправить уведомление ?, есть ли какие-либо проблемы в AlarmManager? Спасибо.