Поиск файла с определенным именем с любым расширением

Question

Обратите внимание, что я хочу, чтобы номер отсека изменился.

<?php 
    $compartment = "1"; 

     /* HERE I NEED SOME SCRIPT TO FIND THE EXTENSION OF THE FILE NAME $compartment AND TO SAVE THAT AS A VARIABLE NAMED 'EXTENSION'.*/ 

    if (file_exists($compartment.$extension)) { 
     echo "$compartment.$extension exists! 
    } else { 
     echo "No file name exists that is called $compartment. Regardless of extension." 
    } 
?> 


<?php 
    $compartment = "2"; 

     /* HERE I NEED SOME SCRIPT TO FIND THE EXTENSION OF THE FILE NAME $compartment AND TO SAVE THAT AS A VARIABLE NAMED 'EXTENSION'.*/ 

    if (file_exists($$compartment.$extension)) { 
     echo "$compartment.$extension exists! 
    } else { 
     echo "No file name exists that is called $compartment. Regardless of extension." 
    } 
?> 

Thank you!

Answer 1

Необходимо glob().

$compartment = "2"; 

$files = glob("/path/to/files/$compartment.*"); // Will find 2.txt, 2.php, 2.gif 

// Process through each file in the list 
// and output its extension 
if (count($files) > 0) 
foreach ($files as $file) 
{ 
    $info = pathinfo($file); 
    echo "File found: extension ".$info["extension"]."<br>"; 
} 
else 
    echo "No file name exists called $compartment. Regardless of extension." 

, кстати, то, что вы делаете выше, плачет за цикл. Дон»повторить свои блоки кода, но обернуть один из них в этом:

$compartments = array(1, 3, 6, 9); // or whichever compartments 
            // you wish to run through 

foreach ($compartments as $compartment) 
    { 
    ..... insert code here ....... 
    } 

Answer 2

Посмотрите:

• glob - Найти имена пути, совпадающие с шаблоном
• fnmatch - Match имя файла с шаблоном
• pathinfo - Возвращает информацию о пути к файлу