печати несколько списков на Python

Question

Когда я присоединять recipe к list и распечатать каждый список, эта ошибка появляется в оболочке Python:

смелый представляет вход пользователей

Вот является образец взаимодействия:

Welcome to Mohamed Ismail's Recipe Viewer 

Add Recipe (add), Load Recipe (load) or Delete Recipe (delete) 

add 

Input recipe id = 1 

Input recipe name = Cake 

Summary 

Recipe id = 1 

Recipe for Cake 

Save Recipe? 

Yes 

... 

Saved Succesfully 

Add Recipe (add), Load Recipe (load) or Delete Recipe (delete) 

load 

Here are your existing recipe id's 

Loading... 

['1'] 

Select Recipe by id 1 

[('Recipe id =', '1')] 

    [<function function.<locals>.fileb at 0x105920400>] # this is the error 
Go back? or exit 

Это мой код:

import time 

currentrecipes = [] 
rp1 = [] 
rp2 = [] 


print("Welcome to Mohamed Ismail's Recipe Viewer") 
time.sleep(1) 

def function(): 
    print('Add Recipe (add), Load Recipe (load) or Delete Recipe (delete)') 
    choice = input() 
    if choice == 'add': 
      a = input('Input recipe id = ') 
      b = input('Input recipe name = ') 
      filea = ("Recipe id =",a) 
      fileb = ("Recipe for =",b) 
      print('') 
      print("Summary") 
      print("------------------") 
      file1 = print("Recipe id =",a) 
      file2 = print("Recipe for",b) 

      def file(): 
       return filea 
      def fileb(): 
       return fileb 
      file() 
      fileb() 
      print('Save Recipe?') 
      userinput = input() 
      if userinput == 'Yes': 
        if a == '1': 
         currentrecipes.append(a) 
         rp1.append(file()) 
         rp2.append(fileb()) 
         print('...') 
         time.sleep(0.5) 
         print("Saved Sucesfully") 
         function() 
        else: 
         print("Choose a recipe id of 1") 
         print("Going back...") 
         time.sleep(2) 
         function() 
      else: 
       function() 
    elif choice == 'load': 
      if currentrecipes == []: 
       print("Error 619: You have no current recipes") 
       function() 
      else: 
       print("Here are your existing recipe id's") 
       print("Loading...") 
       time.sleep(2) 
       print(currentrecipes) 
       option = input("Select Recipe by id ") 
       if option == '1': 
        print(rp1) 
        print(rp2) 
        userchoice = input("Go back? or exit ") 
        if userchoice == 'Go back': 
         function() 
      else: 
        exit()  


    elif choice == 'delete': 
      if currentrecipes == []: 
       print("Error 619: You have no current recipes") 
       function() 
      else: 

       print("Here are your existing recipe id's") 
       print("Loading...") 
       time.sleep(2) 
       print(currentrecipes) 
       option = input("Which recipe do you wish to delete ") 
       if option == '1': 
        if '1' not in currentrecipes: 
        print("Error 404: Recipe is not in saved recipes") 
        function() 
       else: 
        currentrecipes.remove('1') 
        print('Loading...') 
        time.sleep(1) 
        print(currentrecipes) 
        time.sleep(0.5) 
        print("Deleted Succesfully") 

    else: 
      print("Please select one of the 3 options") 
      time.sleep(1) 
      function() 

function() 

Answer 1

Ваш переменный файлb имеет две «функциональности». Это имя функции и переменной. Попробуйте изменить имя функции.