Как правильно проанализировать json-объект?

-1

Я пытаюсь разобрать этот объект JSON и перебрать его, чтобы сделать таблицу в html. На испытаниях я не могу присвоить ценности. Как мне это сделать правильно?Как правильно проанализировать json-объект?

{"1":{"1":"Employer+EID","2":"File+Creation+Date","3":"File+Creation+Time","4":"Payer+EID","5":"Payer+QID","6":"Payer+Bank+Short+Name","7":"Payer+IBAN","8":"Salary+Year+and+Montd","9":"Total+Salaries","10":"Total+records","11":"","12":"","13":"","14":"","15":""},"2":{"1":"12435800","2":"20160714","3":"0318","4":"12435800","5":"","6":"DBQ","7":"QA79DOHB021104613880010010000","8":"201606","9":"183941.22166664","10":"113","11":"","12":"","13":"","14":"","15":""},"3":{"1":"Record+ID","2":"Employee+QID","3":"Employee+Visa+ID","4":"Employee+Name","5":"Employee+Bank+Short+Name","6":"Employee+Account","7":"Salary+Frequency","8":"Number+of+Working+Days","9":"Net+Salary","10":"Basic+Salary","11":"Extra+hours","12":"Extra+Income","13":"Deductions","14":"Payment+Type","15":"Notes/+Comments"},"4":{"1":"1","2":"27835620341","3":"","4":"SHIJAN+THARAKAN+THOMAS","5":"DBQ","6":"2025","7":"M","8":"30","9":"7300","10":"5000","11":"0.00","12":"2500.00000000","13":"200","14":"","15":""}}

Я пробовал:

$data = json_decode($_POST['data'],true); 

//echo count($data); 

echo ($data[4][2]);`

Результат был null JSON. Как я могу сделать это правильно?

источник

2016-07-14 Bineesh

После использования 'json_decode()', используйте 'print_r()' на массив для проверки данных массива. Что он выводит? – Ben

echo '$ data [4] [2]' работает со мной и перекликается с 27835620341, возможно, '$ post ['data']' undefined? – briosheje

Работает для меня: [https://eval.in/605361](https://eval.in/605361) – FirstOne

Ваш JSON Строка -

$str = '{"1":{"1":"Employer+EID","2":"File+Creation+Date","3":"File+Creation+Time","4":"Payer+EID","5":"Payer+QID","6":"Payer+Bank+Short+Name","7":"Payer+IBAN","8":"Salary+Year+and+Montd","9":"Total+Salaries","10":"Total+records","11":"","12":"","13":"","14":"","15":""},"2":{"1":"12435800","2":"20160714","3":"0318","4":"12435800","5":"","6":"DBQ","7":"QA79DOHB021104613880010010000","8":"201606","9":"183941.22166664","10":"113","11":"","12":"","13":"","14":"","15":""},"3":{"1":"Record+ID","2":"Employee+QID","3":"Employee+Visa+ID","4":"Employee+Name","5":"Employee+Bank+Short+Name","6":"Employee+Account","7":"Salary+Frequency","8":"Number+of+Working+Days","9":"Net+Salary","10":"Basic+Salary","11":"Extra+hours","12":"Extra+Income","13":"Deductions","14":"Payment+Type","15":"Notes/+Comments"},"4":{"1":"1","2":"27835620341","3":"","4":"SHIJAN+THARAKAN+THOMAS","5":"DBQ","6":"2025","7":"M","8":"30","9":"7300","10":"5000","11":"0.00","12":"2500.00000000","13":"200","14":"","15":""}}'; 

$result_array = json_decode($str, true); 
echo '<pre>'; print_r($result_array); 
echo $result_array[4][2];

Он отлично работает для меня. Пожалуйста, проверьте переменную $_POST['data']. Это может неопределенными отлаживать эту переменную с помощью print_r($_POST); если данные индекс определяется вы увидите указатель данных, таких как -

Array 
(
    ['data'] => 'some_value', 
)

источник

2016-07-14 14:22:44

Как правильно проанализировать json-объект?

ответ

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