SQL сводная таблица с столбцом и строкой составляет

Question

В пытается добавить строки и столбец сумму в эту сводной таблицу

 create table test4(city nvarchar(10), race nvarchar(30), sex nvarchar(10), age int) 
      insert into test4 values ('Austin', 'African-American', 'male', 21) 
      insert into test4 values ('Austin', 'Asian', 'female', 22) 
      insert into test4 values ('Austin', 'Caucasian', 'male', 23) 
      insert into test4 values ('Austin', 'Hispanic', 'female', 24) 
      insert into test4 values ('Austin', 'African-American', 'Unknown', 25) 
      insert into test4 values ('Austin', 'Asian', 'male', 26) 
      insert into test4 values ('Austin', 'Caucasian', 'female', 27) 
      insert into test4 values ('Austin', 'Hispanic', 'Unknown', 28) 
      insert into test4 values ('Austin', 'Asian', 'male', 29) 
      insert into test4 values ('Austin', 'Caucasian', 'female', 31) 
      insert into test4 values ('Dallas', 'Hispanic', 'Unknown', 32) 
      insert into test4 values ('Dallas', 'African-American', 'male', 33) 
      insert into test4 values ('Dallas', 'Asian', 'female', 34) 
      insert into test4 values ('Dallas', 'Caucasian', 'Unknown', 35) 
      insert into test4 values ('Dallas', 'Hispanic', 'male', 500) 
      insert into test4 values ('Dallas', 'African-American', 'female', 36) 
      insert into test4 values ('Dallas', 'Asian', 'Unknown', 37) 
      insert into test4 values ('Dallas', 'Caucasian', 'male', 38) 
      insert into test4 values ('Dallas', 'Hispanic', 'female', 39) 
      insert into test4 values ('Dallas', 'African-American', 'Unknown', 41) 
      insert into test4 values ('Houston', 'Asian', 'male', 42) 
      insert into test4 values ('Houston', 'Caucasian', 'female', 43) 
      insert into test4 values ('Houston', 'Hispanic', 'Unknown', 44) 
      insert into test4 values ('Houston', 'African-American', 'male', 45) 
      insert into test4 values ('Houston', 'Asian', 'female', 46) 
      insert into test4 values ('Houston', 'Caucasian', 'Unknown', 47) 
      insert into test4 values ('Houston', 'Hispanic', 'male', 48) 
      insert into test4 values ('Houston', 'African-American', 'female', 49) 
      insert into test4 values ('Houston', 'Asian', 'Unknown', 51) 
      insert into test4 values ('Houston', 'Caucasian', 'male', 52); 

      WITH T AS (
      SELECT 
        A.city as city, A.sex as sex, 
        CASE 
         WHEN A.age BETWEEN 20 AND 30 THEN '20-30_' + race 
         WHEN A.age BETWEEN 31 AND 40 THEN '31-40_' + race 
         WHEN A.age BETWEEN 41 AND 50 THEN '41-50_' + race 
        END AS age_range_race 
      FROM test4 AS A 
      ) 
      SELECT * 
      FROM T 
      PIVOT(COUNT(age_range_race) FOR age_range_race 
       IN(
        [20-30_African-American], 
        [20-30_Asian], 
        [20-30_Caucasian], 
        [20-30_Hispanic], 
        [31-40_African-American], 
        [31-40_Asian], 
        [31-40_Caucasian], 
        [31-40_Hispanic], 
        [41-50_African-American], 
        [41-50_Asian], 
        [41-50_Caucasian], 
        [41-50_Hispanic] 
       ) 
      ) AS P 

Я пытаюсь добиться этого результата

1 http://img853.imageshack.us/img853/8112/sqltotal.jpg

единственных примерами Я могу найти в Google хранимые процедуры, написанные для SQL 2000. Пожалуйста, помогите! Заранее спасибо

Answer 1

Здесь вы попробуете.

WITH T AS (
      SELECT 
        A.city as city, A.sex as sex, 
        CASE 
         WHEN A.age BETWEEN 20 AND 30 THEN '20-30_' + race 
         WHEN A.age BETWEEN 31 AND 40 THEN '31-40_' + race 
         WHEN A.age BETWEEN 41 AND 50 THEN '41-50_' + race 
        END AS age_range_race 
      FROM #test4 AS A 
      ) 


SELECT *, ([20-30_African-American] + [20-30_Asian] + [20-30_Caucasian]+ [20-30_Hispanic]+ [31-40_African-American]+ [31-40_Asian]+ [31-40_Caucasian]+ [31-40_Hispanic]+[41-50_African-American]+ [41-50_Asian]+ [41-50_Caucasian]+ [41-50_Hispanic]) Total 
into #tmp_result 
FROM T 
PIVOT(COUNT(age_range_race) FOR age_range_race 
    IN(
     [20-30_African-American], 
     [20-30_Asian], 
     [20-30_Caucasian], 
     [20-30_Hispanic], 
     [31-40_African-American], 
     [31-40_Asian], 
     [31-40_Caucasian], 
     [31-40_Hispanic], 
     [41-50_African-American], 
     [41-50_Asian], 
     [41-50_Caucasian], 
     [41-50_Hispanic] 
    ) 
) AS P 

select * 
from #tmp_result 
union all 
select 'Grand Total','',SUM([20-30_African-American]), SUM([20-30_Asian]), SUM([20-30_Caucasian]), SUM([20-30_Hispanic]),SUM([31-40_African-American]), SUM([31-40_Asian]), SUM([31-40_Caucasian]), SUM([31-40_Hispanic]),SUM([41-50_African-American]), SUM([41-50_Asian]), SUM([41-50_Caucasian]),SUM([41-50_Hispanic]), sum(Total) 
from #tmp_result 

Answer 2

Пожалуйста, попробуйте, как следовать ..

WITH T AS (
      SELECT 
        A.city as city, A.sex as sex, 
        CASE 
         WHEN A.age BETWEEN 20 AND 30 THEN '20-30_' + race 
         WHEN A.age BETWEEN 31 AND 40 THEN '31-40_' + race 
         WHEN A.age BETWEEN 41 AND 50 THEN '41-50_' + race 
        END AS age_range_race 
      FROM #test4 AS A 
      ) 


SELECT *, ([20-30_African-American] + [20-30_Asian] + [20-30_Caucasian]+ [20-30_Hispanic]+ [31-40_African-American]+ [31-40_Asian]+ [31-40_Caucasian]+ [31-40_Hispanic]+[41-50_African-American]+ [41-50_Asian]+ [41-50_Caucasian]+ [41-50_Hispanic]) Total 
FROM T 
PIVOT(COUNT(age_range_race) FOR age_range_race 
    IN(
     [20-30_African-American], 
     [20-30_Asian], 
     [20-30_Caucasian], 
     [20-30_Hispanic], 
     [31-40_African-American], 
     [31-40_Asian], 
     [31-40_Caucasian], 
     [31-40_Hispanic], 
     [41-50_African-American], 
     [41-50_Asian], 
     [41-50_Caucasian], 
     [41-50_Hispanic] 
    ) 
) AS P