Петля через имена из файла JSON

Question

Мне нужно вывести значение «имя» из каждой строки в этом файле JSON.

Я использовал следующий код ниже, но я не могу показаться, чтобы получить правильное значение

$json="{"minlon":-0.352323,"minlat":51.277789,"maxlon":0.147677,"maxlat":51.777789,"searchlon":-0.102323,"searchlat":51.527789,"page":1,"rpp":25,"total":362,"request_time":"2014-03-14T09:35:07+00:00","stations":[ 
    {"station_code":"ZFD","atcocode":null,"tiploc_code":"FRNDNLT","name":"Farringdon (London)","mode":"train","longitude":-0.105205,"latitude":51.520165,"distance":1401}, 
{"station_code":"OLD","atcocode":null,"tiploc_code":"OLDST","name":"Old Street","mode":"train","longitude":-0.088535,"latitude":51.52583,"distance":1574}, 
{"station_code":"KGX","atcocode":null,"tiploc_code":"KNGX","name":"London Kings Cross","mode":"train","longitude":-0.122926,"latitude":51.530882,"distance":2359}, 
{"station_code":"EXR","atcocode":null,"tiploc_code":"ESSEXRD","name":"Essex Road","mode":"train","longitude":-0.096276,"latitude":51.540704,"distance":2407}, 
{"station_code":"CTK","atcocode":null,"tiploc_code":"CTMSLNK","name":"City Thameslink","mode":"train","longitude":-0.10359,"latitude":51.513934,"distance":2483}, 
{"station_code":"STP","atcocode":null,"tiploc_code":"STPADOM","name":"London St Pancras","mode":"train","longitude":-0.126463,"latitude":51.532512,"distance":2817}, 
{"station_code":"BFR","atcocode":null,"tiploc_code":"BLFR","name":"London Blackfriars","mode":"train","longitude":-0.103332,"latitude":51.511808,"distance":2861}, 
    {"station_code":"STP","atcocode":null,"tiploc_code":"STPX","name":"London St Pancras","mode":"train","longitude":-0.127189,"latitude":51.532389,"distance":2888}, 
{"station_code":"STP","atcocode":null,"tiploc_code":"STPXBOX","name":"London St Pancras","mode":"train","longitude":-0.127343,"latitude":51.532166,"distance":2893}, 
{"station_code":"LST","atcocode":null,"tiploc_code":"LIVST","name":"London Liverpool Street","mode":"train","longitude":-0.081426,"latitude":51.517989,"distance":2913}, 

        {"station_code":"HOX","atcocode":null,"tiploc_code":"HOXTON","name":"Hoxton","mode":"train","longitude":-0.075682,"latitude":51.53151,"distance":3040} 
]}"; 
$obj = json_decode($json); 

foreach($obj>stations as $item) { 

} 

Answer 1

обернуть данные в формате JSON вокруг одинарных кавычек вместо двойных кавычек.

foreach($obj->stations as $item) 
{ 
    echo $item->name; 
    echo "<br>"; 
} 

Demo

OUTPUT :

Farringdon (London) 
Old Street 
London Kings Cross 
Essex Road 
City Thameslink 
London St Pancras 
London Blackfriars 
London St Pancras 
London St Pancras 
London Liverpool Street 
Hoxton