Android multipart http-запрос

Question

Я пытаюсь отправить доступный для сервера, но он говорит мне, что мой запрос неверен. Я добавил имя файла для запроса (он отсутствовал), но ничего не меняется. Пожалуйста, укажите на мою ошибку. Благодарю.

import java.io.BufferedReader; 
import java.io.File; 
import java.io.FileInputStream; 
import java.io.FileOutputStream; 
import java.io.IOException; 
import java.io.InputStream; 
import java.io.InputStreamReader; 
import java.io.OutputStream; 
import java.net.HttpURLConnection; 
import java.net.URL; 

import android.os.Environment; 

/** 
* This utility class provides an abstraction layer for sending multipart HTTP 
* POST requests to a web server. 
* 
* @author www.codejava.net 
* 
*/ 
public class MultipartUtility { 
    private final String boundary; 
    private HttpURLConnection httpConn; 
    private OutputStream outputStream; 

    /** 
    * This constructor initializes a new HTTP POST request with content type is 
    * set to multipart/form-data 
    * 
    * @param requestURL 
    * @param charset 
    * @throws IOException 
    */ 
    public MultipartUtility(String requestURL) throws IOException { 

     // creates a unique boundary based on time stamp 
     boundary = "===" + System.currentTimeMillis() + "==="; 

     URL url = new URL(requestURL); 
     httpConn = (HttpURLConnection) url.openConnection(); 
     httpConn.setDoOutput(true); // indicates POST method 
     httpConn.setDoInput(true); 
     httpConn.setRequestProperty("Connection", "Keep-Alive"); 
     httpConn.setRequestProperty("Content-Type", 
       "multipart/form-data; boundary=" + boundary); 
     outputStream = httpConn.getOutputStream(); 
    } 

    /** 
    * Adds a upload file section to the request 
    * 
    * @param fieldName 
    *   name attribute in <input type="file" name="..." /> 
    * @param uploadFile 
    *   a File to be uploaded 
    * @throws IOException 
    */ 
    public void addFilePart(InputStream inputStream) throws IOException { 
     File temp = new File(Environment.getExternalStorageDirectory() 
       .getPath(), Urls.ICON_NAME); 
     // write the inputStream to a FileOutputStream 
     OutputStream out = new FileOutputStream(temp); 
     int read = 0; 
     byte[] bytes = new byte[1024]; 
     while ((read = inputStream.read(bytes)) != -1) { 
      out.write(bytes, 0, read); 
     } 
     inputStream.close(); 
     out.flush(); 
     out.close(); 

     outputStream.write("--*****\r\n".getBytes()); 
     outputStream.write(("Content-Disposition: form-data; name=\"" 
       + "photo" + "\";filename=\"" 
       + Urls.ICON_NAME + "\"\r\n").getBytes()); 
     outputStream.write("\r\n".getBytes()); 

     //outputStream.write("Content-Type", "image/png"); 

     FileInputStream fileInputStream = new FileInputStream(temp); 
     byte[] buffer = new byte[4096]; 
     int bytesRead = -1; 
     while ((bytesRead = fileInputStream.read(buffer)) != -1) { 
      outputStream.write(buffer, 0, bytesRead); 
     } 

     outputStream.write("\r\n".getBytes()); 
     outputStream.write("--*****--\r\n".getBytes()); 

     outputStream.flush(); 
     fileInputStream.close(); 

     temp.delete(); 
    } 

    /** 
    * Completes the request and receives response from the server. 
    * 
    * @return a list of Strings as response in case the server returned status 
    *   OK, otherwise an exception is thrown. 
    * @throws IOException 
    */ 
    public String finish() throws IOException { 
     StringBuilder strBuilder = new StringBuilder(); 
     // checks server's status code first 
     int status = httpConn.getResponseCode(); 
     if (status == HttpURLConnection.HTTP_OK) { 
      BufferedReader reader = new BufferedReader(new InputStreamReader(
        httpConn.getInputStream())); 
      String line = ""; 
      while ((line = reader.readLine()) != null) { 
       strBuilder.append(line).append("\n"); 
      } 
      reader.close(); 
      httpConn.disconnect(); 
     } else { 
      throw new IOException("Server returned non-OK status: " + status); 
     } 

     return strBuilder.toString(); 
    } 
} 

Answer 1

почему вы используете «*****», как граница, тогда как вы определили в своем заголовке:

"Content-Type", "multipart/form-data; boundary=" + boundary

Вы должны использовать границы, определенные в вашем заголовке, как границы в вашем теле запроса.

Answer 2

Попробуйте это,

String url="<Your URL>"; 
String fileName="<Your file>"; 
HttpClient httpclient = new DefaultHttpClient(); 
HttpPost httppost = new HttpPost(url); 
FileBody fileContent= new FileBody(new File(fileName)); 
StringBody comment = new StringBody("Filename: " + fileName); 
MultipartEntity reqEntity = new MultipartEntity(); 
reqEntity.addPart("file", fileContent); 
httppost.setEntity(reqEntity); 
System.out.println("post length"+reqEntity.getContentLength()); 
HttpResponse response = httpclient.execute(httppost); 
HttpEntity resEntity = response.getEntity();