это мой файлдобавление столбца в CSV и делать деление + AWK
$ cat test1
"Rec_Open_Date","MSISDN","IMEI","Data_Volume_Bytes","Device_Manufacturer","Device_Model","Product_Description"
"2015-10-06","427","060","137765","Samsung Korea","Samsung SM-G900I","$39 Plan"
"2015-10-06","592","620","0","Apple Inc","Apple iPhone 6 (A1586)","PREPAY STD - TRIAL - #16"
"2015-10-06","007","290","0","Apple Inc","Apple iPhone 6 (A1586)","PREPAY PLUS - $0 -"
"2015-10-06","592","050","48836832","Apple Inc","Apple iPhone 5S (A1530)","Talk and Text Connect Flexi Plan"
"2015-10-06","409","720","113755347","Samsung Korea","Samsung SM-G360G","$29 CARRYOVER PLAN"
"2015-10-06","742","620","19840943","Apple Inc","Apple iPhone S (A1530)","PREPAY STD - $0 - #2"
"2015-10-06","387","180","0","HUAWEI Technologies Co Ltd","HUAWEI HUAWEI G526-L11","PREPAY STD - $1 - #4"
"2015-10-06","731","570","2258243","Samsung Korea","Samsung SM-N910U","Business Freedom"
"2015-10-06","556","910","13332272","Samsung Korea","Samsung GT-I9505","$49 Plan"
эта команда добавляет столбец к концу.
$ awk -F"," 'BEGIN { OFS = "," } {$7=($4); print}' test1
"Rec_Open_Date","MSISDN","IMEI","Data_Volume_Bytes","Device_Manufacturer","Device_Model","Data_Volume_Bytes"
"2015-10-06","427","060","137765","Samsung Korea","Samsung SM-G900I","137765"
"2015-10-06","592","620","0","Apple Inc","Apple iPhone 6 (A1586)","0"
как я получаю следующий вывод: для простоты это просто $7=($4/1)
.
"Rec_Open_Date","MSISDN","IMEI","Data_Volume_Bytes","Device_Manufacturer","Device_Model","Data_Volume_Bytes"
"2015-10-06","427","060","137765","Samsung Korea","Samsung SM-G900I","137765"
"2015-10-06","592","620","0","Apple Inc","Apple iPhone 6 (A1586)","0"
То, что я действительно хочу, чтобы быть в состоянии сделать это $7=$4/10124/1024
, но по некоторым причинам я не могу получить разделение на работу.
Я пробовал это, но только получаю $ 7 = равным нулю.
awk -F"," 'BEGIN { OFS = "," } {$7=($4/1024); print}' test1
"Rec_Open_Date","MSISDN","IMEI","Data_Volume_Bytes","Device_Manufacturer","Device_Model",0
"2015-10-06","427","060","137765","Samsung Korea","Samsung SM-G900I",0
EDIT1: Thsi как изменить имя заголовка Col в колонке 7. Не уверен, что при использовании \"
является лучшим или единственным способом сохранить его в двойные кавычки.
$ awk -F"," '{ OFS = "," } NR<=1{$7="\"Data_Volume_MB\""; print}' test1
"Rec_Open_Date","MSISDN","IMEI","Data_Volume_Bytes","Device_Manufacturer","Device_Model","Data_Volume_MB"
EDIT2 ЭТО ЧТО я хочу, но она включает в себя casting from a string to an int in awksubstr($4,2,(length($4)-2))
. однако ответ не в двойных кавычках 0.131383
, для единообразия, как я могу это достичь?
$ awk -F"," '{ OFS = "," } NR>1{$7=substr($4,2,(length($4)-2))/1024/1024; print}' test1
"2015-10-06","427","060","137765","Samsung Korea","Samsung SM-G900I",0.131383
"2015-10-06","592","620","0","Apple Inc","Apple iPhone 6 (A1586)",0
"2015-10-06","007","290","0","Apple Inc","Apple iPhone 6 (A1586)",0
"2015-10-06","592","050","48836832","Apple Inc","Apple iPhone 5S (A1530)",46.5744
Это связано с тем, что мои значения заключены в двойные кавычки «137765». – HattrickNZ
Я бы предложил обратиться к чему-то вроде Python или Ruby, который имеет фактический синтаксический анализатор CSV, который знает, как правильно обращаться с цитируемыми значениями, или, может быть, что-то вроде инструмента командной строки csv (https://github.com/gaal/ приложение-CSV). – larsks