Миграция столбцов на основе ключей в MySQL

Question

Мне нужно вставить combined_streets из table1 в combined_streets в table2. Общий ключ stop_id, но обратите внимание, что stop_id уникален в table1, но есть повторы stop_id в table2.

table1

+---------+-----------+--------------+-----------+------------+-----------------+---------+---------------+----------------------+ 
| stop_id | on_street | cross_street | boardings | alightings | month_beginning | daytype | location  | combined_streets  | 
+---------+-----------+--------------+-----------+------------+-----------------+---------+---------------+----------------------+ 
|  137 | JACKSON | KOLMAR  | 4.6  | 14.2  | 10/01/2012  | Weekday | "(41.87696338 | JACKSON & KOLMAR  | 
|  138 | JACKSON | KENTON  | 5   | 15.2  | 10/01/2012  | Weekday | "(41.87696546 | JACKSON & KENTON  | 
|  139 | JACKSON | KILPATRICK | 38.9  | 242.1  | 10/01/2012  | Weekday | "(41.87692666 | JACKSON & KILPATRICK | 
|  140 | JACKSON | CICERO  | 0.2  | 1.7  | 10/01/2012  | Weekday | "(41.87685893 | JACKSON & CICERO  | 
|  141 | JACKSON | 4900 WEST | 0   | 0   | 10/01/2012  | Weekday | "(41.87682102 | JACKSON & 4900 WEST | 
|  142 | JACKSON | LAVERGNE  | 0   | 0   | 10/01/2012  | Weekday | "(41.87680393 | JACKSON & LAVERGNE | 
|  143 | JACKSON | 5056 WEST | 0   | 0   | 10/01/2012  | Weekday | "(41.87675729 | JACKSON & 5056 WEST | 
|  144 | JACKSON | LEAMINGTON | 0   | 0   | 10/01/2012  | Weekday | "(41.87672858 | JACKSON & LEAMINGTON | 
|  145 | JACKSON | LARAMIE  | 59.1  | 172.9  | 10/01/2012  | Weekday | "(41.87673038 | JACKSON & LARAMIE | 
|  146 | JACKSON | LOCKWOOD  | 14.3  | 92   | 10/01/2012  | Weekday | "(41.87667680 | JACKSON & LOCKWOOD | 
+---------+-----------+--------------+-----------+------------+-----------------+---------+---------------+----------------------+ 

table2

+---------+-------+------------------+ 
| stop_id | route | combined_streets | 
+---------+-------+------------------+ 
|  74 | 126 | NULL    | 
|  74 | 132 | NULL    | 
|  74 | 143 | NULL    | 
|  74 | 147 | NULL    | 
|  75 | 1  | NULL    | 
|  75 | 7  | NULL    | 
|  75 | X28 | NULL    | 
|  75 | 126 | NULL    | 
|  75 | 129 | NULL    | 
|  76 | 3  | NULL    | 
+---------+-------+------------------+ 

Answer 1

UPDATE table2 t2 LEFT JOIN table1 t1 ON t2.stop_id = t1.stop_id SET t2.combined_streets = t1.combined_streets; 

Answer 2

UPDATE table1, table2 SET table2.combined_streets = table1.combined_streets WHERE 
table1.stop_id=table2.stop_id;