MSSQL - Pivot мульти поля

Question

я имею ниже таблице & данные:

USE tempdb; SET NOCOUNT ON; 
IF OBJECT_ID('tempdb.dbo.#abcd', 'U') IS NOT NULL DROP TABLE dbo.#abcd; 
CREATE TABLE #abcd 
(
    [Company] [NVARCHAR](30) NOT NULL, 
    [FatherNum] [NVARCHAR](30) NOT NULL, 
    [FormatCode] [NVARCHAR](20) NULL, 
    [AcctName] [NVARCHAR](8) NULL, 
); 

INSERT INTO [#abcd] ([Company],[FatherNum],[FormatCode],[AcctName])VALUES('FR','100002','123456','ACCOUNT1'); 
INSERT INTO [#abcd] ([Company],[FatherNum],[FormatCode],[AcctName])VALUES('FR','100002','123321','ACCOUNT2'); 
INSERT INTO [#abcd] ([Company],[FatherNum],[FormatCode],[AcctName])VALUES('UK','100002','123456','ACCOUNT1'); 
INSERT INTO [#abcd] ([Company],[FatherNum],[FormatCode],[AcctName])VALUES('UK','100002','123321','ACCOUNT3'); 
INSERT INTO [#abcd] ([Company],[FatherNum],[FormatCode],[AcctName])VALUES('UK','100003','125467','TESTA'); 
INSERT INTO [#abcd] ([Company],[FatherNum],[FormatCode],[AcctName])VALUES('USA','100000','45725','TESTB'); 
INSERT INTO [#abcd] ([Company],[FatherNum],[FormatCode],[AcctName])VALUES('USA','100002','123456','ACCOUNT1'); 

желаемый результат запроса этой таблице:

USE tempdb; SET NOCOUNT ON; 
IF OBJECT_ID('tempdb.dbo.#abcd1', 'U') IS NOT NULL DROP TABLE dbo.#abcd1; 
CREATE TABLE #abcd1 
(

    [FatherNum] [NVARCHAR](30) NOT NULL, 
    [FR] [NVARCHAR](20) NULL, 
    [FRName] [NVARCHAR](20) NULL, 
    [UK] [NVARCHAR](20) NULL, 
    [UKName] [NVARCHAR](20) NULL, 
    [USA] [NVARCHAR](20) NULL, 
    [USAName] [NVARCHAR](20) NULL, 

); 

INSERT INTO [#abcd1] ([FatherNum],[FR],[FRName], [UK], [UKName], [USA], [USAName]) VALUES('100002','123456','ACCOUNT1','123456','ACCOUNT1','123456','ACCOUNT1'); 
INSERT INTO [#abcd1] ([FatherNum],[FR],[FRName], [UK], [UKName], [USA], [USAName]) VALUES('100002','123321','ACCOUNT2','123321','ACCOUNT3',NULL,NULL); 
INSERT INTO [#abcd1] ([FatherNum],[FR],[FRName], [UK], [UKName], [USA], [USAName]) VALUES('100003',NULL,NULL,'125467','TESTA',NULL,NULL); 
INSERT INTO [#abcd1] ([FatherNum],[FR],[FRName], [UK], [UKName], [USA], [USAName]) VALUES('100003',NULL,NULL,NULL,NULL,'45725','TESTB'); 

SELECT * FROM dbo.#abcd1 

Я только удалось получить это далеко:

SELECT * FROM (
SELECT Company, FatherNum, FormatCode,AcctName FROM #abcd 
) temptable 
PIVOT 
(MAX(FormatCode) FOR Company IN ([FR], [UK], [USA])) T1 

Answer 1

Необходимо до unpivot данных до поворота

SELECT FatherNum, 
     [FR], 
     [FR Name], 
     [UK], 
     [UK Name], 
     [USA], 
     [USA Name] 
FROM (SELECT FatherNum, 
       FormatCode, 
       NEW, 
       value 
     FROM #abcd 
       CROSS APPLY (VALUES (Company,FormatCode), 
            (Company + ' NAME',AcctName)) CS (NEW, value)) temptable 
     PIVOT (Max(value) 
      FOR NEW IN ([FR],[FR Name], 
         [UK],[UK Name], 
         [USA],[USA Name])) T1 

Результат:

╔═══════════╦════════╦══════════╦════════╦══════════╦════════╦══════════╗ 
║ FatherNum ║ FR ║ FR Name ║ UK ║ UK Name ║ USA ║ USA Name ║ 
╠═══════════╬════════╬══════════╬════════╬══════════╬════════╬══════════╣ 
║ 100002 ║ 123321 ║ ACCOUNT2 ║ 123321 ║ ACCOUNT3 ║ NULL ║ NULL  ║ 
║ 100002 ║ 123456 ║ ACCOUNT1 ║ 123456 ║ ACCOUNT1 ║ 123456 ║ ACCOUNT1 ║ 
║ 100003 ║ NULL ║ NULL  ║ 125467 ║ TESTA ║ NULL ║ NULL  ║ 
║ 100000 ║ NULL ║ NULL  ║ NULL ║ NULL  ║ 45725 ║ TESTB ║ 
╚═══════════╩════════╩══════════╩════════╩══════════╩════════╩══════════╝