У меня есть ниже запрос: И я хочу, чтобы сделать эту ось динамика в процедурахКак сделать динамический стержень в Oracle PL SQL
SELECT *
FROM ( SELECT tcsd AS Aggregator,
country,
SUM (COUNT) AS total,
COUNT (dest_addr) AS bnum,
time_stamp
FROM t_raw_intl_sms_aggr
GROUP BY tcsd,
COUNT,
country,
time_stamp
ORDER BY tcsd,
COUNT,
country,
time_stamp) PIVOT (SUM (total) AS total,
COUNT (bnum) AS bnum_total
FOR time_stamp
IN (TO_DATE ('20150801', 'yyyymmdd') AS DAY_20150801_TOTAL,
TO_DATE ('20150802', 'yyyymmdd') AS DAY_20150802_TOTAL,
TO_DATE ('20150803', 'yyyymmdd') AS DAY_20150803_TOTAL,
TO_DATE ('20150804', 'yyyymmdd') AS DAY_20150804_TOTAL,
TO_DATE ('20150805', 'yyyymmdd') AS DAY_20150805_TOTAL,
TO_DATE ('20150806', 'yyyymmdd') AS DAY_20150806_TOTAL,
TO_DATE ('20150807', 'yyyymmdd') AS DAY_20150807_TOTAL,
TO_DATE ('20150808', 'yyyymmdd') AS DAY_20150808_TOTAL,
TO_DATE ('20150809', 'yyyymmdd') AS DAY_20150809_TOTAL,
TO_DATE ('20150810', 'yyyymmdd') AS DAY_20150810_TOTAL,
TO_DATE ('20150811', 'yyyymmdd') AS DAY_20150811_TOTAL,
TO_DATE ('20150812', 'yyyymmdd') AS DAY_20150812_TOTAL,
TO_DATE ('20150813', 'yyyymmdd') AS DAY_20150813_TOTAL,
TO_DATE ('20150814', 'yyyymmdd') AS DAY_20150814_TOTAL,
TO_DATE ('20150815', 'yyyymmdd') AS DAY_20150815_TOTAL,
TO_DATE ('20150816', 'yyyymmdd') AS DAY_20150816_TOTAL,
TO_DATE ('20150817', 'yyyymmdd') AS DAY_20150817_TOTAL,
TO_DATE ('20150818', 'yyyymmdd') AS DAY_20150818_TOTAL,
TO_DATE ('20150819', 'yyyymmdd') AS DAY_20150819_TOTAL,
TO_DATE ('20150820', 'yyyymmdd') AS DAY_20150820_TOTAL,
TO_DATE ('20150821', 'yyyymmdd') AS DAY_20150821_TOTAL,
TO_DATE ('20150822', 'yyyymmdd') AS DAY_20150822_TOTAL,
TO_DATE ('20150823', 'yyyymmdd') AS DAY_20150823_TOTAL,
TO_DATE ('20150824', 'yyyymmdd') AS DAY_20150824_TOTAL,
TO_DATE ('20150825', 'yyyymmdd') AS DAY_20150825_TOTAL,
TO_DATE ('20150826', 'yyyymmdd') AS DAY_20150826_TOTAL,
TO_DATE ('20150827', 'yyyymmdd') AS DAY_20150827_TOTAL,
TO_DATE ('20150828', 'yyyymmdd') AS DAY_20150828_TOTAL,
TO_DATE ('20150829', 'yyyymmdd') AS DAY_20150829_TOTAL,
TO_DATE ('20150830', 'yyyymmdd') AS DAY_20150830_TOTAL,
TO_DATE ('20150831', 'yyyymmdd') AS DAY_20150831_TOTAL))
ORDER BY aggregator, country
и выше результатов:
SYBASE Papua New Guinea 1 1 2 1 1 1 1
SYBASE Peru 2 13 9 20 43 36 12 19 27 18 23 73 33 41 18 17 12 31 35 41 15 40 23 34 24 31 63 31 20
SYBASE Poland 2 3 8 8 2 10 23 10 17 13 21 21 26 6 11 13 17 14 18 11 7 7 10 4
SYBASE Portugal (includes Azores) 8 7 15 13 14 59 47 40 32 39 50 78 41 47 26 42 68 56 64 51 41 62 90 74 62 40 44 46 55
Я уже Хранилище образцов:
CREATE OR REPLACE PROCEDURE intl_sms_aggr (p_cursor IN OUT SYS_REFCURSOR)
AS
l_query LONG := 'SELECT * FROM ( SELECT tcsd AS Aggregator,
country,
SUM (COUNT) AS total,
COUNT (dest_addr) AS bnum,
time_stamp
FROM t_raw_intl_sms_aggr
GROUP BY tcsd,
COUNT,
country,
time_stamp
ORDER BY tcsd,
COUNT,
country,
time_stamp) PIVOT (SUM (total) AS total,
COUNT (bnum) AS bnum_total
FOR time_stamp
IN (';
BEGIN
FOR x IN (select time_stamp from prev_month)
LOOP
l_query := l_query|| REPLACE (' TO_DATE(''$X$'',''yyyymmdd'') as DAY_$X$_TOTAL, ','$X$',x.time_stamp);
END LOOP;
l_query := l_query || ')) ORDER BY aggregator, country';
-- OPEN p_cursor FOR l_query;
DBMS_OUTPUT.put_line ('query: ' || l_query);
END;
/
Но у меня есть проблема в последнем цикле, который является запятой, пожалуйста, помогите мне восстановить мой сценарий, вот моя проблема:
SELECT *
FROM ( SELECT tcsd AS Aggregator,
country,
SUM (COUNT) AS total,
COUNT (dest_addr) AS bnum,
time_stamp
FROM t_raw_intl_sms_aggr
GROUP BY tcsd,
COUNT,
country,
time_stamp
ORDER BY tcsd,
COUNT,
country,
time_stamp) PIVOT (SUM (total) AS total,
COUNT (bnum) AS bnum_total
FOR time_stamp
IN (TO_DATE ('20150801', 'yyyymmdd') AS DAY_20150801_TOTAL,
TO_DATE ('20150802', 'yyyymmdd') AS DAY_20150802_TOTAL,
TO_DATE ('20150803', 'yyyymmdd') AS DAY_20150803_TOTAL,
TO_DATE ('20150804', 'yyyymmdd') AS DAY_20150804_TOTAL,
TO_DATE ('20150805', 'yyyymmdd') AS DAY_20150805_TOTAL,
TO_DATE ('20150806', 'yyyymmdd') AS DAY_20150806_TOTAL,
TO_DATE ('20150807', 'yyyymmdd') AS DAY_20150807_TOTAL,
TO_DATE ('20150808', 'yyyymmdd') AS DAY_20150808_TOTAL,
TO_DATE ('20150809', 'yyyymmdd') AS DAY_20150809_TOTAL,
TO_DATE ('20150810', 'yyyymmdd') AS DAY_20150810_TOTAL,
TO_DATE ('20150811', 'yyyymmdd') AS DAY_20150811_TOTAL,
TO_DATE ('20150812', 'yyyymmdd') AS DAY_20150812_TOTAL,
TO_DATE ('20150813', 'yyyymmdd') AS DAY_20150813_TOTAL,
TO_DATE ('20150814', 'yyyymmdd') AS DAY_20150814_TOTAL,
TO_DATE ('20150815', 'yyyymmdd') AS DAY_20150815_TOTAL,
TO_DATE ('20150816', 'yyyymmdd') AS DAY_20150816_TOTAL,
TO_DATE ('20150817', 'yyyymmdd') AS DAY_20150817_TOTAL,
TO_DATE ('20150818', 'yyyymmdd') AS DAY_20150818_TOTAL,
TO_DATE ('20150819', 'yyyymmdd') AS DAY_20150819_TOTAL,
TO_DATE ('20150820', 'yyyymmdd') AS DAY_20150820_TOTAL,
TO_DATE ('20150821', 'yyyymmdd') AS DAY_20150821_TOTAL,
TO_DATE ('20150822', 'yyyymmdd') AS DAY_20150822_TOTAL,
TO_DATE ('20150823', 'yyyymmdd') AS DAY_20150823_TOTAL,
TO_DATE ('20150824', 'yyyymmdd') AS DAY_20150824_TOTAL,
TO_DATE ('20150825', 'yyyymmdd') AS DAY_20150825_TOTAL,
TO_DATE ('20150826', 'yyyymmdd') AS DAY_20150826_TOTAL,
TO_DATE ('20150827', 'yyyymmdd') AS DAY_20150827_TOTAL,
TO_DATE ('20150828', 'yyyymmdd') AS DAY_20150828_TOTAL,
TO_DATE ('20150829', 'yyyymmdd') AS DAY_20150829_TOTAL,
TO_DATE ('20150830', 'yyyymmdd') AS DAY_20150830_TOTAL,
TO_DATE ('20150831', 'yyyymmdd') AS DAY_20150831_TOTAL,))
ORDER BY aggregator, country
Привет @ Utsav, я пробовал ваши предложения, но все тот же результат: BEGIN curCount: = 0; SELECT COUNT (*) INTO o_count FROM prev_month; ДЛЯ х В (ВЫБРАТЬ ИЗ time_stamp prev_month) LOOP ЕСЛИ curCount = o_count ТОГДА l_query: = l_query || REPLACE ('TO_DATE (' '$ X $' ',' 'yyyymmdd' ') как DAY_ $ X $ _TOTAL', '$ X $', x.time_stamp); ELSE l_query: = l_query || REPLACE ('TO_DATE (' '$ X $' ',' 'yyyymmdd' ') как DAY_ $ X $ _TOTAL,', '$ X $', x.time_stamp); END IF; END LOOP; l_query: = l_query || ')) ORDER BY aggregator, country'; END; –
Попробуйте добавить 2 разных dbms_output.put_line в условие if и else в цикле и повторить разные значения. Затем мы можем проверить правильность нашей логики. – Utsav
Привет @Utsav, я снова попробовал ваше предложение, если у меня в dbms_output.put_line нет результата, а в моем другом - тот же результат. Есть ли предложения? У меня нет другой идеи. Благодарю. –