Как я могу поместить каждый многобайтовый символ/emoji с пробелами вокруг него в строке?

Question

Я хотел бы заполнить каждый многобайтовый символ пробелами с обеих сторон. Я могу их разбить, но я хотел бы оставить их и просто надеть их.

Например: .

Использование подчеркивания для представления пробелов: в ______

Answer 1

Используйте этот monsterous- already-cooked regex:

$regex = "[\\x{fe00}-\\x{fe0f}\\x{2712}\\x{2714}\\x{2716}\\x{271d}\\x{2721}\\x{2728}\\x{2733}\\x{2734}\\x{2744}\\x{2747}\\x{274c}\\x{274e}\\x{2753}-\\x{2755}\\x{2757}\\x{2763}\\x{2764}\\x{2795}-\\x{2797}\\x{27a1}\\x{27b0}\\x{27bf}\\x{2934}\\x{2935}\\x{2b05}-\\x{2b07}\\x{2b1b}\\x{2b1c}\\x{2b50}\\x{2b55}\\x{3030}\\x{303d}\\x{1f004}\\x{1f0cf}\\x{1f170}\\x{1f171}\\x{1f17e}\\x{1f17f}\\x{1f18e}\\x{1f191}-\\x{1f19a}\\x{1f201}\\x{1f202}\\x{1f21a}\\x{1f22f}\\x{1f232}-\\x{1f23a}\\x{1f250}\\x{1f251}\\x{1f300}-\\x{1f321}\\x{1f324}-\\x{1f393}\\x{1f396}\\x{1f397}\\x{1f399}-\\x{1f39b}\\x{1f39e}-\\x{1f3f0}\\x{1f3f3}-\\x{1f3f5}\\x{1f3f7}-\\x{1f4fd}\\x{1f4ff}-\\x{1f53d}\\x{1f549}-\\x{1f54e}\\x{1f550}-\\x{1f567}\\x{1f56f}\\x{1f570}\\x{1f573}-\\x{1f579}\\x{1f587}\\x{1f58a}-\\x{1f58d}\\x{1f590}\\x{1f595}\\x{1f596}\\x{1f5a5}\\x{1f5a8}\\x{1f5b1}\\x{1f5b2}\\x{1f5bc}\\x{1f5c2}-\\x{1f5c4}\\x{1f5d1}-\\x{1f5d3}\\x{1f5dc}-\\x{1f5de}\\x{1f5e1}\\x{1f5e3}\\x{1f5ef}\\x{1f5f3}\\x{1f5fa}-\\x{1f64f}\\x{1f680}-\\x{1f6c5}\\x{1f6cb}-\\x{1f6d0}\\x{1f6e0}-\\x{1f6e5}\\x{1f6e9}\\x{1f6eb}\\x{1f6ec}\\x{1f6f0}\\x{1f6f3}\\x{1f910}-\\x{1f918}\\x{1f980}-\\x{1f984}\\x{1f9c0}\\x{3297}\\x{3299}\\x{a9}\\x{ae}\\x{203c}\\x{2049}\\x{2122}\\x{2139}\\x{2194}-\\x{2199}\\x{21a9}\\x{21aa}\\x{231a}\\x{231b}\\x{2328}\\x{2388}\\x{23cf}\\x{23e9}-\\x{23f3}\\x{23f8}-\\x{23fa}\\x{24c2}\\x{25aa}\\x{25ab}\\x{25b6}\\x{25c0}\\x{25fb}-\\x{25fe}\\x{2600}-\\x{2604}\\x{260e}\\x{2611}\\x{2614}\\x{2615}\\x{2618}\\x{261d}\\x{2620}\\x{2622}\\x{2623}\\x{2626}\\x{262a}\\x{262e}\\x{262f}\\x{2638}-\\x{263a}\\x{2648}-\\x{2653}\\x{2660}\\x{2663}\\x{2665}\\x{2666}\\x{2668}\\x{267b}\\x{267f}\\x{2692}-\\x{2694}\\x{2696}\\x{2697}\\x{2699}\\x{269b}\\x{269c}\\x{26a0}\\x{26a1}\\x{26aa}\\x{26ab}\\x{26b0}\\x{26b1}\\x{26bd}\\x{26be}\\x{26c4}\\x{26c5}\\x{26c8}\\x{26ce}\\x{26cf}\\x{26d1}\\x{26d3}\\x{26d4}\\x{26e9}\\x{26ea}\\x{26f0}-\\x{26f5}\\x{26f7}-\\x{26fa}\\x{26fd}\\x{2702}\\x{2705}\\x{2708}-\\x{270d}\\x{270f}]|\\x{23}\\x{20e3}|\\x{2a}\\x{20e3}|\\x{30}\\x{20e3}|\\x{31}\\x{20e3}|\\x{32}\\x{20e3}|\\x{33}\\x{20e3}|\\x{34}\\x{20e3}|\\x{35}\\x{20e3}|\\x{36}\\x{20e3}|\\x{37}\\x{20e3}|\\x{38}\\x{20e3}|\\x{39}\\x{20e3}|\\x{1f1e6}[\\x{1f1e8}-\\x{1f1ec}\\x{1f1ee}\\x{1f1f1}\\x{1f1f2}\\x{1f1f4}\\x{1f1f6}-\\x{1f1fa}\\x{1f1fc}\\x{1f1fd}\\x{1f1ff}]|\\x{1f1e7}[\\x{1f1e6}\\x{1f1e7}\\x{1f1e9}-\\x{1f1ef}\\x{1f1f1}-\\x{1f1f4}\\x{1f1f6}-\\x{1f1f9}\\x{1f1fb}\\x{1f1fc}\\x{1f1fe}\\x{1f1ff}]|\\x{1f1e8}[\\x{1f1e6}\\x{1f1e8}\\x{1f1e9}\\x{1f1eb}-\\x{1f1ee}\\x{1f1f0}-\\x{1f1f5}\\x{1f1f7}\\x{1f1fa}-\\x{1f1ff}]|\\x{1f1e9}[\\x{1f1ea}\\x{1f1ec}\\x{1f1ef}\\x{1f1f0}\\x{1f1f2}\\x{1f1f4}\\x{1f1ff}]|\\x{1f1ea}[\\x{1f1e6}\\x{1f1e8}\\x{1f1ea}\\x{1f1ec}\\x{1f1ed}\\x{1f1f7}-\\x{1f1fa}]|\\x{1f1eb}[\\x{1f1ee}-\\x{1f1f0}\\x{1f1f2}\\x{1f1f4}\\x{1f1f7}]|\\x{1f1ec}[\\x{1f1e6}\\x{1f1e7}\\x{1f1e9}-\\x{1f1ee}\\x{1f1f1}-\\x{1f1f3}\\x{1f1f5}-\\x{1f1fa}\\x{1f1fc}\\x{1f1fe}]|\\x{1f1ed}[\\x{1f1f0}\\x{1f1f2}\\x{1f1f3}\\x{1f1f7}\\x{1f1f9}\\x{1f1fa}]|\\x{1f1ee}[\\x{1f1e8}-\\x{1f1ea}\\x{1f1f1}-\\x{1f1f4}\\x{1f1f6}-\\x{1f1f9}]|\\x{1f1ef}[\\x{1f1ea}\\x{1f1f2}\\x{1f1f4}\\x{1f1f5}]|\\x{1f1f0}[\\x{1f1ea}\\x{1f1ec}-\\x{1f1ee}\\x{1f1f2}\\x{1f1f3}\\x{1f1f5}\\x{1f1f7}\\x{1f1fc}\\x{1f1fe}\\x{1f1ff}]|\\x{1f1f1}[\\x{1f1e6}-\\x{1f1e8}\\x{1f1ee}\\x{1f1f0}\\x{1f1f7}-\\x{1f1fb}\\x{1f1fe}]|\\x{1f1f2}[\\x{1f1e6}\\x{1f1e8}-\\x{1f1ed}\\x{1f1f0}-\\x{1f1ff}]|\\x{1f1f3}[\\x{1f1e6}\\x{1f1e8}\\x{1f1ea}-\\x{1f1ec}\\x{1f1ee}\\x{1f1f1}\\x{1f1f4}\\x{1f1f5}\\x{1f1f7}\\x{1f1fa}\\x{1f1ff}]|\\x{1f1f4}\\x{1f1f2}|\\x{1f1f5}[\\x{1f1e6}\\x{1f1ea}-\\x{1f1ed}\\x{1f1f0}-\\x{1f1f3}\\x{1f1f7}-\\x{1f1f9}\\x{1f1fc}\\x{1f1fe}]|\\x{1f1f6}\\x{1f1e6}|\\x{1f1f7}[\\x{1f1ea}\\x{1f1f4}\\x{1f1f8}\\x{1f1fa}\\x{1f1fc}]|\\x{1f1f8}[\\x{1f1e6}-\\x{1f1ea}\\x{1f1ec}-\\x{1f1f4}\\x{1f1f7}-\\x{1f1f9}\\x{1f1fb}\\x{1f1fd}-\\x{1f1ff}]|\\x{1f1f9}[\\x{1f1e6}\\x{1f1e8}\\x{1f1e9}\\x{1f1eb}-\\x{1f1ed}\\x{1f1ef}-\\x{1f1f4}\\x{1f1f7}\\x{1f1f9}\\x{1f1fb}\\x{1f1fc}\\x{1f1ff}]|\\x{1f1fa}[\\x{1f1e6}\\x{1f1ec}\\x{1f1f2}\\x{1f1f8}\\x{1f1fe}\\x{1f1ff}]|\\x{1f1fb}[\\x{1f1e6}\\x{1f1e8}\\x{1f1ea}\\x{1f1ec}\\x{1f1ee}\\x{1f1f3}\\x{1f1fa}]|\\x{1f1fc}[\\x{1f1eb}\\x{1f1f8}]|\\x{1f1fd}\\x{1f1f0}|\\x{1f1fe}[\\x{1f1ea}\\x{1f1f9}]|\\x{1f1ff}[\\x{1f1e6}\\x{1f1f2}\\x{1f1fc}]"; 

Внутри preg_replace_callback():

var_dump(preg_replace_callback("@$regex@u", function($match) { 
    return $match[0]." "; 
}, '')); 

Выходы:

string(18) "  " 

Live demo

Answer 2

Я нашел this function, что кто-то добавил в PHP документации, которая разделяет строку многобайтовой в массив символов (например, str_split) и модифицировал его.

function addSpaces($string) { 
    $strlen = mb_strlen($string); 
    $new_string = ''; 
    while ($strlen) { 
     $char = mb_substr($string,0,1,"UTF-8"); 
     if (strlen($char) > 1) { 
      $new_string .= " $char "; 
     } else { 
      $new_string .= $char; 
     } 
     $string = mb_substr($string,1,$strlen,"UTF-8"); 
     $strlen = mb_strlen($string); 
    } 
    return $new_string; 
} 

This question есть другие способы сделать это разделение, которые могут быть так же изменены. Модификация, если strlen одного из разделенных символов больше 1, то это многобайтовый, поэтому добавьте пробелы.

Answer 3

Простой регулярное выражение замены может работать, как хорошо ...

mb_regex_encoding("UTF-8"); 

echo mb_ereg_replace(
    '([^\p{L}\s])', 
    ' \\1 ', 
    'text other text ' 
); 

выходы: text other text

---

function pad_emojis($string) { 
    $default_encoding = mb_regex_encoding(); 
    mb_regex_encoding("UTF-8"); 
    $string = mb_ereg_replace('([^\p{L}\s])', ' \\1 ', $string); 
    mb_regex_encoding($default_encoding); 
    return $string; 
}