У меня есть модель Entity Framework с двумя таблицами, клиентом и почтовым индексом. Почтовый индекс может иметь много клиентов, клиент может иметь 1 почтовый индекс. Они соединены в почтовый индекс. Две таблицы отображаются в виде.Объект Entity Framework отсутствует связанные данные
У меня есть несколько клиентов, которые не имеют почтового индекса в модели, однако в БД они делают!
Я провел несколько тестов и обнаружил почтовые индексы, которые возвращали клиентов, когда я делаю Postcode.Clients
, но не всех клиентов? В db почтовый индекс имел 14 связанных клиентов, но EF возвращал только первые 6. В основном определенные почтовые индексы не возвращают все данные.
Lazy loading включен, и я попытался отключить его без везения.
Любые идеи?
Я использую VS 2010, C#, .NET 4.0, EF4 и SQL Server 2008
Благодаря
UPDATE:
Я бежал через это в LINQPad. Я стараюсь использовать следующий код:
Client c = Clients.Where(a => a.ClientId == 9063202).SingleOrDefault();
c.PostcodeView.Dump();
Это возвращает null.
Я тогда взять сгенерированный SQL и запустите в отдельном запросе SQL и он работает правильно (после того, как я добавляю @ в начале имени переменной)
SELECT TOP (2)
[Extent1].[ClientId] AS [ClientId],
[Extent1].[Surname] AS [Surname],
[Extent1].[Forename] AS [Forename],
[Extent1].[FlatNo] AS [FlatNo],
[Extent1].[StNo] AS [StNo],
[Extent1].[Street] AS [Street],
[Extent1].[Town] AS [Town],
[Extent1].[Postcode] AS [Postcode]
FROM (SELECT
[ClientView].[ClientId] AS [ClientId],
[ClientView].[Surname] AS [Surname],
[ClientView].[Forename] AS [Forename],
[ClientView].[FlatNo] AS [FlatNo],
[ClientView].[StNo] AS [StNo],
[ClientView].[Street] AS [Street],
[ClientView].[Town] AS [Town],
[ClientView].[Postcode] AS [Postcode]
FROM [dbo].[ClientView] AS [ClientView]) AS [Extent1]
WHERE 9063202 = [Extent1].[ClientId]
GO
-- Region Parameters
DECLARE @EntityKeyValue1 VarChar(8) = 'G15 6NB'
-- EndRegion
SELECT
[Extent1].[Postcode] AS [Postcode],
[Extent1].[ltAstId] AS [ltAstId],
[Extent1].[ltLhoId] AS [ltLhoId],
[Extent1].[ltChcpId] AS [ltChcpId],
[Extent1].[ltCppId] AS [ltCppId],
[Extent1].[ltWardId] AS [ltWardId],
[Extent1].[ltAst] AS [ltAst],
[Extent1].[ltCpp] AS [ltCpp],
[Extent1].[ltWard] AS [ltWard],
[Extent1].[WardNo] AS [WardNo],
[Extent1].[Councillor] AS [Councillor],
[Extent1].[ltAdminCentre] AS [ltAdminCentre],
[Extent1].[ltChcp] AS [ltChcp],
[Extent1].[Forename] AS [Forename],
[Extent1].[Surname] AS [Surname],
[Extent1].[AreaNo] AS [AreaNo],
[Extent1].[LtAomId] AS [LtAomId],
[Extent1].[OOHltCoordinatorId] AS [OOHltCoordinatorId],
[Extent1].[OvernightltCoordinatorId] AS [OvernightltCoordinatorId],
[Extent1].[DayltCoordinatorId] AS [DayltCoordinatorId]
FROM (SELECT
[PostcodeView].[Postcode] AS [Postcode],
[PostcodeView].[ltAstId] AS [ltAstId],
[PostcodeView].[ltLhoId] AS [ltLhoId],
[PostcodeView].[ltChcpId] AS [ltChcpId],
[PostcodeView].[ltCppId] AS [ltCppId],
[PostcodeView].[ltWardId] AS [ltWardId],
[PostcodeView].[ltAst] AS [ltAst],
[PostcodeView].[ltCpp] AS [ltCpp],
[PostcodeView].[ltWard] AS [ltWard],
[PostcodeView].[WardNo] AS [WardNo],
[PostcodeView].[Councillor] AS [Councillor],
[PostcodeView].[ltAdminCentre] AS [ltAdminCentre],
[PostcodeView].[ltChcp] AS [ltChcp],
[PostcodeView].[Forename] AS [Forename],
[PostcodeView].[Surname] AS [Surname],
[PostcodeView].[AreaNo] AS [AreaNo],
[PostcodeView].[LtAomId] AS [LtAomId],
[PostcodeView].[DayltCoordinatorId] AS [DayltCoordinatorId],
[PostcodeView].[OOHltCoordinatorId] AS [OOHltCoordinatorId],
[PostcodeView].[OvernightltCoordinatorId] AS [OvernightltCoordinatorId]
FROM [dbo].[PostcodeView] AS [PostcodeView]) AS [Extent1]
WHERE [Extent1].[Postcode] = @EntityKeyValue1
Показать код может быть полезно. – Yakimych 2010-12-16 12:50:34