Динамически меняющееся имя переменной в unix through for loop

Question

Today=$(date) 
for i in {2..15} 
do 
week_{$i}=$(date -d "$Today +$i week") 
echo ${week_2} 
done 

Я не получаю никаких значений на выходе в BASH.

Answer 1

Один из способов ...

 
    Today=$(date) 
    for i in {2..15} 
    do 
     tmp=$(date -d "$Today +$i week") 
     eval week_${i}=\$tmp 
     eval echo \$week_${i} 
    done 

Второй путь ...

 
    Today=$(date) 
    for i in {2..15} 
    do 
     week_[$i]=$(date -d "$Today +$i week") 
     echo ${week_[$i]} 
    done 

Третий путь ...

Today=$(date) 
    for i in {2..15} 
    do 
     eval echo \${week_${i}:=$(date -d "$Today +$i week")} > /dev/null 
    done 

    for i in {2..15} 
    do 
     eval echo \$week_${i} 
    done