ForLoops Самое большое и самое маленькое число

Question

так как бы вы нашли самое большое и самое маленькое число здесь?

import java.util.Scanner; 

public class Loops2 { 
    public static void main (String args[]) { 

     Scanner input = new Scanner(System.in); 
     System.out.println("Type 10 numbers"); 

     for (int i = 0; i < 10; i++) { 
      int number = input.nextInt(); 
      System.out.println(number); 
     } 
    } 
} 

Answer 1

List<Integer> list = new ArrayList<Integer>(); 
    Scanner input = new Scanner(System.in); 
    System.out.println("Type 10 numbers"); 

    for (int i = 0; i < 10; i++) { 
     int number = input.nextInt(); 
     System.out.println(number); 
     list.add(number); 
    } 
    Collections.sort(list); 
    System.out.println("the small: "+ list.get(0)); 
    System.out.println("the big: "+list.get(list.size() - 1)); 

Answer 2

Предполагая, что вы пытаетесь сделать, это найти наибольшее и наималейшее числа в массиве целых чисел:

public static void main (String args[]) { 

    Scanner input = new Scanner(System.in); 
    System.out.println("Type 10 numbers"); 

    //I will create the array here... 

    int[] nums = new int[10]; 

    //assigning numbers/ints 

    for(int i = 0; i < 10; i++) { 
    nums[i] = input.nextInt(); 
    } 

    //now to find the largest and smallest (in this order) 

    int largest = 0; 

    for(int j = 0; j < nums.length; j++)//usage of the 1-line rule :) 
     if(nums[j] > largest) 
     largest = nums[j]; 

    int smallest = largest; 

    //I'm doing this, so that it keeps checking for something lower than the largest number... 

    for(int k = 0; k < nums.length; k++)//usage of the 1-line rule again :) 
     if(nums[k] < smallest) 
      smallest = nums[k]; 

    System.out.println("Largest: " + largest); 
    System.out.println("Smallest: " + smallest); 


} 

Надеется, что это помогает!

Answer 3

Это, вероятно, лучший способ реализовать это

import java.util.Scanner; 

public class FindLargestSmallestNumber { 

    public static void main(String[] args) { 

     Scanner input = new Scanner(System.in); 
     System.out.println("Type 10 numbers"); 
     //array of 10 numbers 
     int numbers[] = new int[10]; 

     for (int i = 0; i < 10; i++) { 
      int number = input.nextInt(); 
      System.out.println(number); 
      numbers[i] = number ; 
     } 

     //assign first element of an array to largest and smallest 
     int smallest = numbers[0]; 
     int largetst = numbers[0]; 

     for(int i=1; i< numbers.length; i++) 
     { 
      if(numbers[i] > largetst) 
       largetst = numbers[i]; 
      else if (numbers[i] < smallest) 
       smallest = numbers[i]; 

     } 

     System.out.println("Largest Number is : " + largetst); 
     System.out.println("Smallest Number is : " + smallest); 
    } 
} 

Answer 4

import java.util.Scanner; 

public class LargestSmallestNumbers { 

    private static Scanner input; 

    public static void main(String[] args) { 
     int count,items; 
     int newnum =0 ; 
     int highest=0; 
     int lowest =0; 

     input = new Scanner(System.in); 
     System.out.println("How many numbers you want to enter?"); 
     items = input.nextInt(); 

     System.out.println("Enter "+items+" numbers: "); 


     for (count=0; count<items; count++){ 
      newnum = input.nextInt();    
      if (highest<newnum) 
       highest=newnum; 

      if (lowest==0) 
       lowest=newnum; 

      else if (newnum<=lowest) 
       lowest=newnum; 
      } 

     System.out.println("The highest number is "+highest); 
     System.out.println("The lowest number is "+lowest); 
    } 
}