-1
Привет, У меня есть небольшая проблема при создании встроенной формы с помощью проверки на стороне сервера. У меня есть два файла index.php, которые я использую в качестве контроллера для добавления данных в базу данных и form.php для отображения формы. Это то, что у меня есть:PHP inline validation
index.php
<?php
include '../includes/dbconn.php';
# add joke link pressed
if (isset($_GET['add_joke']))
{
// Build the list of authors for drop-down list
try
{
$result = $dbConnection->query('SELECT id, name FROM author');
}
catch (PDOException $e)
{
$error = 'Error fetching list of authors.' . '<br />' . $e -> getMessage();
include '../includes/error.php';
exit();
}
foreach ($result as $row)
{
$authors_in_db[] = array(
'id' => $row['id'],
'name' => $row['name']
);
}
include 'form.php';
exit();
}
# add joke to the database
if (isset($_GET['add_joke_to_db']))
{
# continue with adding joke to the database
try
{
$sql = 'INSERT INTO joke SET
joke_text = :joke_text,
joke_date = CURDATE(),
author_id = :author_id';
$s = $dbConnection -> prepare($sql);
$s -> bindValue(':joke_text', $_POST['joke_text']);
$s -> bindValue(':author_id', $_POST['author']);
$s -> execute();
}
catch (PDOException $e)
{
$error = 'Error adding joke.' . '<br />' . $e -> getMessage();
include '../includes/error.php';
exit();
}
header('Location: .');
exit();
}
# delete joke from the database
if (isset($_GET['delete_joke']))
{
try
{
$sql = 'DELETE FROM joke WHERE id = :id';
$s = $dbConnection -> prepare($sql);
$s -> bindValue(':id', $_POST['id']);
$s -> execute();
}
catch (PDOException $e)
{
$error = 'Error deleting joke.' . '<br />' . $e -> getMessage();
include '../includes/error.php';
exit();
}
header ('Location: .');
exit();
}
# select all jokes from the database
try
{
$sql = 'SELECT joke.id, joke.joke_text, joke.joke_date, author.name, author.email
FROM joke INNER JOIN author
ON author_id = author.id';
$result = $dbConnection -> query($sql);
}
catch (PDOException $e)
{
$error = 'Error fetching jokes.' . '<br />' . $e -> getMessage();
include '../includes/error.php';
exit();
}
# add each data item within an array
foreach ($result as $row)
{
$jokes_in_db[] = array(
'joke.id' => $row['id'],
'joke.joke_text' => $row['joke_text'],
'joke.joke_date' => $row['joke_date'],
'author.name' => $row['name'],
'author.email' => $row['email']
);
}
включают 'jokes.php'; ? >
и form.php
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="utf-8">
<title>Add Joke</title>
<link rel="stylesheet" type="text/css" href="../includes/styles.css" />
</head>
<body>
<h1>Add Joke</h1>
<form action="?add_joke_to_db" method="post">
<div>
<label for="joke_text">Type your joke here:</label>
<textarea id="joke_text" name="joke_text" rows="3" required></textarea>
<span class="error">* <?php echo $joke_textError;?></span>
</div>
<div>
<label for="author">Author:</label>
<select name="author" id="author">
<option value="">Select one</option>
<?php foreach ($authors_in_db as $data): ?>
<option value="<?php echo htmlspecialchars($data['id'], ENT_QUOTES, 'UTF-8'); ?>">
<?php echo htmlspecialchars($data['name'], ENT_QUOTES, 'UTF-8'); ?>
</option>
<?php endforeach; ?>
</select>
<span class="error">* <?php echo $author_textError;?></span>
</div>
<div>
<input type="submit" value="Add">
</div>
</form>
</body>
Каков ваш вопрос? будьте более конкретными! – Akshay
Барни, чтобы сделать его более понятным. Как получить встроенное сообщение об ошибке, показывающее, отсутствует ли joke_text. –