ipython ноутбук не работает на ipython 2.2.0

Question

Я попытался запустить IPython ноутбук. Я введённое в командной строке:

IPython ноутбук

Я получаю эту ошибку (трассировка стека)

Traceback (most recent call last): 
File "/usr/local/bin/ipython", line 11, in <module> 
sys.exit(start_ipython()) 
File "/usr/local/Cellar/python/2.7.8_1/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/IPython/__init__.py", line 120, in start_ipython 
return launch_new_instance(argv=argv, **kwargs) 
File "/usr/local/Cellar/python/2.7.8_1/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/IPython/config/application.py", line 563, in launch_instance 
app.initialize(argv) 
File "<string>", line 2, in initialize 
File "/usr/local/Cellar/python/2.7.8_1/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/IPython/config/application.py", line 92, in catch_config_error 
return method(app, *args, **kwargs) 
File "/usr/local/Cellar/python/2.7.8_1/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/IPython/terminal/ipapp.py", line 321, in initialize 
super(TerminalIPythonApp, self).initialize(argv) 
File "<string>", line 2, in initialize 
File "/usr/local/Cellar/python/2.7.8_1/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/IPython/config/application.py", line 92, in catch_config_error 
return method(app, *args, **kwargs) 
File "/usr/local/Cellar/python/2.7.8_1/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/IPython/core/application.py", line 381, in initialize 
self.parse_command_line(argv) 
File "/usr/local/Cellar/python/2.7.8_1/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/IPython/terminal/ipapp.py", line 316, in parse_command_line 
return super(TerminalIPythonApp, self).parse_command_line(argv) 
File "<string>", line 2, in parse_command_line 
File "/usr/local/Cellar/python/2.7.8_1/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/IPython/config/application.py", line 92, in catch_config_error 
return method(app, *args, **kwargs) 
File "/usr/local/Cellar/python/2.7.8_1/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/IPython/config/application.py", line 475, in parse_command_line 
return self.initialize_subcommand(subc, subargv) 
File "<string>", line 2, in initialize_subcommand 
File "/usr/local/Cellar/python/2.7.8_1/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/IPython/config/application.py", line 92, in catch_config_error 
return method(app, *args, **kwargs) 
File "/usr/local/Cellar/python/2.7.8_1/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/IPython/config/application.py", line 406, in initialize_subcommand 
subapp = import_item(subapp) 
File "/usr/local/Cellar/python/2.7.8_1/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/IPython/utils/importstring.py", line 42, in import_item 
module = __import__(package, fromlist=[obj]) 
File "/usr/local/Cellar/python/2.7.8_1/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/IPython/html/notebookapp.py", line 40, in <module> 
check_for_zmq('2.1.11', 'IPython.html') 
File "/usr/local/Cellar/python/2.7.8_1/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/IPython/utils/zmqrelated.py", line 37, in check_for_zmq 
raise ImportError("%s requires pyzmq >= %s"%(required_by, minimum_version)) 
ImportError: IPython.html requires pyzmq >= 2.1.11 

Я использую Python 2.7.8 и iphython 2.2.0

Answer 1

Возможно, вам нужно установить новейшую версию pyzmq по адресу:

pip install --upgrade pyzmq