Просмотр посещаемости datewise с помощью phpmysql

<?php require_once('Connections/dbconnect.php'); ?> 
<?php 
$c=$_GET['Class']; 
$s=$_GET['Section']; 
$f=$_GET['fmonth']; 
$t=$_GET['tmonth']; 
$count=1; 
mysql_select_db($database_dbconnect, $dbconnect); 
$query_classwise = "SELECT Name_of_Student, Roll_no, Section, 
GROUP_CONCAT(if(DAY(`Date`) = 1, `Status`, NULL)) AS 'day1', 
GROUP_CONCAT(if(DAY(`Date`) = 2, `Status`, NULL)) AS 'day2', 
GROUP_CONCAT(if(DAY(`Date`) = 3, `Status`, NULL)) AS 'day3', 
GROUP_CONCAT(if(DAY(`Date`) = 4, `Status`, NULL)) AS 'day4', 
GROUP_CONCAT(if(DAY(`Date`) = 5, `Status`, NULL)) AS 'day5', 
GROUP_CONCAT(if(DAY(`Date`) = 6, `Status`, NULL)) AS 'day6', 
GROUP_CONCAT(if(DAY(`Date`) = 7, `Status`, NULL)) AS 'day7', 
GROUP_CONCAT(if(DAY(`Date`) = 8, `Status`, NULL)) AS 'day8', 
GROUP_CONCAT(if(DAY(`Date`) = 9, `Status`, NULL)) AS 'day9', 
GROUP_CONCAT(if(DAY(`Date`) = 10, `Status`, NULL)) AS'day10', 
GROUP_CONCAT(if(DAY(`Date`) = 11, `Status`, NULL)) AS 'day11', 
GROUP_CONCAT(if(DAY(`Date`) = 12, `Status`, NULL)) AS 'day12', 
GROUP_CONCAT(if(DAY(`Date`) = 13, `Status`, NULL)) AS 'day13', 
GROUP_CONCAT(if(DAY(`Date`) = 14, `Status`, NULL)) AS 'day14', 
GROUP_CONCAT(if(DAY(`Date`) = 15, `Status`, NULL)) AS 'day15', 
GROUP_CONCAT(if(DAY(`Date`) = 16, `Status`, NULL)) AS 'day16', 
GROUP_CONCAT(if(DAY(`Date`) = 17, `Status`, NULL)) AS 'day17', 
GROUP_CONCAT(if(DAY(`Date`) = 18, `Status`, NULL)) AS 'day18', 
GROUP_CONCAT(if(DAY(`Date`) = 19, `Status`, NULL)) AS 'day19', 
GROUP_CONCAT(if(DAY(`Date`) = 20, `Status`, NULL)) AS 'day20', 
GROUP_CONCAT(if(DAY(`Date`) = 21, `Status`, NULL)) AS 'day21', 
GROUP_CONCAT(if(DAY(`Date`) = 22, `Status`, NULL)) AS 'day22', 
GROUP_CONCAT(if(DAY(`Date`) = 23, `Status`, NULL)) AS 'day23', 
GROUP_CONCAT(if(DAY(`Date`) = 24, `Status`, NULL)) AS 'day24', 
GROUP_CONCAT(if(DAY(`Date`) = 25, `Status`, NULL)) AS 'day25', 
GROUP_CONCAT(if(DAY(`Date`) = 26, `Status`, NULL)) AS 'day26', 
GROUP_CONCAT(if(DAY(`Date`) = 27, `Status`, NULL)) AS 'day27', 
GROUP_CONCAT(if(DAY(`Date`) = 28, `Status`, NULL)) AS 'day28', 
GROUP_CONCAT(if(DAY(`Date`) = 29, `Status`, NULL)) AS 'day29', 
GROUP_CONCAT(if(DAY(`Date`) = 30, `Status`, NULL)) AS 'day30', 
GROUP_CONCAT(if(DAY(`Date`) = 31, `Status`, NULL)) AS 'day31', 
COUNT(if(`Status`='Y', `Status`, NULL)) AS 'total' FROM `attendance` 
WHERE `Date` BETWEEN '$f' AND '$t' GROUP BY Name_of_Student" ; 
$classwise = mysql_query($query_classwise, $dbconnect) or die(mysql_error()); 
$row_classwise = mysql_fetch_assoc($classwise); 
$totalRows_classwise = mysql_num_rows($classwise); 
?>

Мой запрос очень долго, я не понимаю, правильно ли мой запрос или нет, мои знания в PHP очень ограничено, я пытаюсь вывести, используя следующий код PHP:Просмотр посещаемости datewise с помощью phpmysql

<html xmlns="http://www.w3.org/1999/xhtml"> 
<head> 
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> 
<title>Untitled Document</title> 
<style type="text/css"> 
<!-- 
.style1 {color: #666600} 
.style2 {color: #000000} 
--> 
</style> 
</head> 
<body> 
<table width="640" border="0" align="center" cellpadding="4" cellspacing="4"> 
<tr> 
<td width="48" bgcolor="#000000"><div align="center">SL No</div></td> 
<td width="225" bgcolor="#000000"><div align="center">Name of Student</div></td> 
<td width="45" bgcolor="#000000"><div align="center">Roll no</div></td> 
<td width="45" bgcolor="#000000">Day 1 </td> 
<td width="45" bgcolor="#000000">Day 2</td> 
<td width="45" bgcolor="#000000">Day 3 </td> 
</tr> 
<?php do { ?> 
<tr> 
<td bgcolor="#333333"><div align="center"><?php echo $count++; ?></div></td> 
<td bgcolor="#333333"><?php echo $row_classwise['Name_of_Student']; ?></td> 
<td bgcolor="#333333"><div align="center"><?php echo $row_classwise['Roll_no']; 
?> </div></td> 
<td bgcolor="#333333"><?php echo $row_classwise['day1']; ?></td> 
<td bgcolor="#333333"><?php echo $row_classwise['day2']; ?></td> 
<td bgcolor="#333333"><?php echo $row_classwise['day3']; ?></td> 
</tr> 
<?php } while ($row_classwise = mysql_fetch_assoc($classwise)); ?> 
</table> 
</body> 
</html> 
<?php 
mysql_free_result($classwise); 
?>

Я хочу получить правильные Y или N под каждым днем (день1, день2 и т. Д.). До сих пор это не выход желаемого resultI может обеспечить таблицу, если это необходимо ...

Вот мой новый запрос, я хочу поставить -/- и - где день суббота и воскресенье или праздник:

SELECT Students.Name_of_Student, Students.Roll_no, Students.Class, Students.Section, allDays.aDay, 
GROUP_CONCAT(IFNULL(attendance.Status, '-') ORDER BY TimePeriod.`time` DESC SEPARATOR '/') AS Status 
FROM (SELECT DISTINCT Name_of_Student, Roll_no, Class, Section FROM attendance) AS Students 
CROSS JOIN (SELECT 1 AS aDay UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9 UNION 
SELECT 10 AS aDay UNION SELECT 11 UNION SELECT 12 UNION SELECT 13 UNION SELECT 14 UNION SELECT 15 UNION SELECT 16 UNION SELECT 17 UNION SELECT 18 UNION SELECT 19 UNION 
SELECT 20 AS aDay UNION SELECT 21 UNION SELECT 22 UNION SELECT 23 UNION SELECT 24 UNION SELECT 25 UNION SELECT 26 UNION SELECT 27 UNION SELECT 28 UNION SELECT 29 UNION 
SELECT 30 UNION SELECT 31) allDays 
CROSS JOIN (SELECT 'Morning' AS `time` UNION SELECT 'Afternoon') TimePeriod 
LEFT OUTER JOIN attendance ON Students.Name_of_Student = attendance.Name_of_Student AND allDays.aDay = DAY(`Date`) 
AND BINARY TimePeriod.`time` = BINARY attendance.`time` where Date Between '$f' and '$t' and Students.Section='$s' and Students.Class='$c' 
GROUP BY Students.Name_of_Student, Students.Roll_no, Students.Section, allDays.aDay 
ORDER BY Students.Name_of_Student, allDays.aDay

источник

2013-07-04 Mawia HL

Что такое статус в запросе, он содержит 1,0 или что? – Naeem

@Nomi Для настоящего 'Y' и для Absent' N' –

здесь вы можете найти таблицу: http://stackoverflow.com/questions/17468945/attendance-view/17469153?noredirect=1#comment25385300_17469153 –

Вместо того, чтобы пытаться получить целую линейную линию, возможно, легче получить строку на человека в день. Затем в вашем php-коде вы бросаете новую строку, когда человек меняется.

SQL-то вроде этого: -

SELECT Students.Name_of_Student, Students.Roll_no, Students.Section, allDays.aDay, attendence.Status 
FROM (SELECT DISTINCT Name_of_Student FROM attendence WHERE `Date` BETWEEN '$f' AND '$t') AS Students 
CROSS JOIN (
SELECT 1 AS aDay UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9 UNION 
SELECT 10 AS aDay UNION SELECT 11 UNION SELECT 12 UNION SELECT 13 UNION SELECT 14 UNION SELECT 15 UNION SELECT 16 UNION SELECT 17 UNION SELECT 18 UNION SELECT 19 UNION 
SELECT 20 AS aDay UNION SELECT 21 UNION SELECT 22 UNION SELECT 23 UNION SELECT 24 UNION SELECT 25 UNION SELECT 26 UNION SELECT 27 UNION SELECT 28 UNION SELECT 29 UNION 
SELECT 30 UNION SELECT 31 
) allDays 
LEFT OUTER JOIN attendence 
ON Students.Name_of_Student = attendence.Name_of_Student AND allDays.aDay = DAY(`Date`) 
WHERE `Date` BETWEEN '$f' AND '$t'

Это получает список студентов (что было бы проще, если бы у вас был студенческий стол), а также список всех дней месяца. Затем присоединяемся к тем, у кого есть левое соединение против участия.

РНР затем будет что-то вроде этого (не тестировалось)

<html xmlns="http://www.w3.org/1999/xhtml"> 
<head> 
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> 
<title>Untitled Document</title> 
<style type="text/css"> 
<!-- 
.style1 {color: #666600} 
.style2 {color: #000000} 
--> 
</style> 
</head> 
<body> 
<table width="640" border="0" align="center" cellpadding="4" cellspacing="4"> 
<tr> 
<td width="48" bgcolor="#000000"><div align="center">SL No</div></td> 
<td width="225" bgcolor="#000000"><div align="center">Name of Student</div></td> 
<td width="45" bgcolor="#000000"><div align="center">Roll no</div></td> 
<td width="45" bgcolor="#000000">Day 1 </td> 
<td width="45" bgcolor="#000000">Day 2</td> 
<td width="45" bgcolor="#000000">Day 3 </td> 
</tr> 
<?php 
$PrevName_of_Student = ''; 
while ($row_classwise = mysql_fetch_assoc($classwise)) 
{ 
    if ($PrevName_of_Student != $row_classwise['Name_of_Student']) 
    { 
     if ($PrevName_of_Student ! = '') 
     { 
      echo '</tr>'; 
     } 
     ?><tr> 
     <td bgcolor="#333333"><div align="center"><?php echo $count++; ?></div></td> 
     <td bgcolor="#333333"><?php echo $row_classwise['Name_of_Student']; ?></td> 
     <td bgcolor="#333333"><div align="center"><?php echo $row_classwise['Roll_no'];?></div></td> 
     <?php 
     $PrevName_of_Student = $row_classwise['Name_of_Student']; 
    } 
?> 
    <td bgcolor="#333333"><?php echo $row_classwise['Status']; ?></td> 
    </tr> 
<?php 
} 
if ($PrevName_of_Student ! = '') 
{ 
    echo '</tr>'; 
} 
?> 
</table> 
</body> 
</html> 
<?php 
mysql_free_result($classwise); 
?>

Полагая, что вместе вы получите что-то вроде этого (проверено и работает)

<?php 

$link = mysql_connect('localhost', 'root', ''); 
If (!$link) 
{ 
    die ('Could not connect: ' . mysql_error()); 
} 
@mysql_select_db('testarea') or die ('Unable to select database'); 

$query = "SELECT Students.Name_of_Student, Students.Roll_no, Students.Section, allDays.aDay, attendance.Status, TimePeriod.`time` 
FROM (SELECT DISTINCT Name_of_Student, Roll_no, Section FROM attendance) AS Students 
CROSS JOIN (
SELECT 1 AS aDay UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9 UNION 
SELECT 10 AS aDay UNION SELECT 11 UNION SELECT 12 UNION SELECT 13 UNION SELECT 14 UNION SELECT 15 UNION SELECT 16 UNION SELECT 17 UNION SELECT 18 UNION SELECT 19 UNION 
SELECT 20 AS aDay UNION SELECT 21 UNION SELECT 22 UNION SELECT 23 UNION SELECT 24 UNION SELECT 25 UNION SELECT 26 UNION SELECT 27 UNION SELECT 28 UNION SELECT 29 UNION 
SELECT 30 UNION SELECT 31 
) allDays 
CROSS JOIN (SELECT 'Morning' AS `time` UNION SELECT 'Afternoon') TimePeriod 
LEFT OUTER JOIN attendance 
ON Students.Name_of_Student = attendance.Name_of_Student AND allDays.aDay = DAY(`Date`) AND BINARY TimePeriod.`time` = BINARY attendance.`time` 
ORDER BY Students.Name_of_Student, allDays.aDay, TimePeriod.`time` DESC"; 

$classwise = mysql_query($query); 

?> 
<html xmlns="http://www.w3.org/1999/xhtml"> 
<head> 
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> 
<title>Untitled Document</title> 
<style type="text/css"> 
<!-- 
.style1 {color: #666600} 
.style2 {color: #000000} 
--> 
</style> 
</head> 
<body> 
<table width="640" border="0" align="center" cellpadding="4" cellspacing="4"> 
<tr> 
<td width="48" ><div align="center">SL No</div></td> 
<td width="225" ><div align="center">Name of Student</div></td> 
<td width="45" ><div align="center">Roll no</div></td> 
<?php 
for($iCnt = 1; $iCnt <=31; $iCnt++) 
{ 
    foreach(array("Morning", "Afternoon") AS $TimePeriod) 
    { 
     echo "<td width='45' >Day $iCnt $TimePeriod</td>"; 
    } 
} 
echo "</tr>"; 
$PrevName_of_Student = ''; 
$count = 0; 
while ($row_classwise = mysql_fetch_assoc($classwise)) 
{ 
    if ($PrevName_of_Student != $row_classwise['Name_of_Student']) 
    { 
     if ($PrevName_of_Student != '') 
     { 
      echo '</tr>'; 
     } 
     echo "<tr>"; 
     echo "<td ><div align='center'>".$count++."</div></td>"; 
     echo "<td >".$row_classwise['Name_of_Student']."</td>"; 
     echo "<td ><div align='center'>".$row_classwise['Roll_no']."</div></td>"; 
     $PrevName_of_Student = $row_classwise['Name_of_Student']; 
    } 
    echo "<td >".$row_classwise['Status']."</td>"; 
} 
if ($PrevName_of_Student != '') 
{ 
    echo '</tr>'; 
} 
mysql_free_result($classwise); 
?> 
</table> 
</body> 
</html>

EDIT - слияние утром и днем записи за день для лица: -

<?php 

$link = mysql_connect('localhost', 'root', ''); 
If (!$link) 
{ 
    die ('Could not connect: ' . mysql_error()); 
} 
@mysql_select_db('testarea') or die ('Unable to select database'); 

$query = "SELECT Students.Name_of_Student, Students.Roll_no, Students.Section, allDays.aDay, GROUP_CONCAT(IFNULL(attendance.Status, '-') ORDER BY TimePeriod.`time` DESC SEPARATOR '/') AS Status 
FROM (SELECT DISTINCT Name_of_Student, Roll_no, Section FROM attendance) AS Students 
CROSS JOIN (
SELECT 1 AS aDay UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9 UNION 
SELECT 10 AS aDay UNION SELECT 11 UNION SELECT 12 UNION SELECT 13 UNION SELECT 14 UNION SELECT 15 UNION SELECT 16 UNION SELECT 17 UNION SELECT 18 UNION SELECT 19 UNION 
SELECT 20 AS aDay UNION SELECT 21 UNION SELECT 22 UNION SELECT 23 UNION SELECT 24 UNION SELECT 25 UNION SELECT 26 UNION SELECT 27 UNION SELECT 28 UNION SELECT 29 UNION 
SELECT 30 UNION SELECT 31 
) allDays 
CROSS JOIN (SELECT 'Morning' AS `time` UNION SELECT 'Afternoon') TimePeriod 
LEFT OUTER JOIN attendance 
ON Students.Name_of_Student = attendance.Name_of_Student AND allDays.aDay = DAY(`Date`) AND BINARY TimePeriod.`time` = BINARY attendance.`time` 
GROUP BY Students.Name_of_Student, Students.Roll_no, Students.Section, allDays.aDay 
ORDER BY Students.Name_of_Student, allDays.aDay"; 

$classwise = mysql_query($query); 

?> 
<html xmlns="http://www.w3.org/1999/xhtml"> 
<head> 
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> 
<title>Untitled Document</title> 
<style type="text/css"> 
<!-- 
.style1 {color: #666600} 
.style2 {color: #000000} 
--> 
</style> 
</head> 
<body> 
<table width="640" border="0" align="center" cellpadding="4" cellspacing="4"> 
<tr> 
<td width="48" ><div align="center">SL No</div></td> 
<td width="225" ><div align="center">Name of Student</div></td> 
<td width="45" ><div align="center">Roll no</div></td> 
<?php 
for($iCnt = 1; $iCnt <=31; $iCnt++) 
{ 
    echo "<td width='45' >Day $iCnt </td>"; 
} 
echo "</tr>"; 
$PrevName_of_Student = ''; 
$count = 0; 
while ($row_classwise = mysql_fetch_assoc($classwise)) 
{ 
    if ($PrevName_of_Student != $row_classwise['Name_of_Student']) 
    { 
     if ($PrevName_of_Student != '') 
     { 
      echo '</tr>'; 
     } 
     echo "<tr>"; 
     echo "<td ><div align='center'>".$count++."</div></td>"; 
     echo "<td >".$row_classwise['Name_of_Student']."</td>"; 
     echo "<td ><div align='center'>".$row_classwise['Roll_no']."</div></td>"; 
     $PrevName_of_Student = $row_classwise['Name_of_Student']; 
    } 
    echo "<td >".$row_classwise['Status']."</td>"; 
} 
if ($PrevName_of_Student != '') 
{ 
    echo '</tr>'; 
} 
mysql_free_result($classwise); 
?> 
</table> 
</body> 
</html>

EDIT - обновленный запрос.

Примечание. Я поставил предложения, чтобы ограничить учащихся в подборе, который получает список учеников. Далее проверьте даты, которые я поставил в ВКЛЮЧЕННЫЙ пункт ЛЕВЫЙ ВНЕШНИЙ ПРИСОЕДИНЕНИЕ, чтобы получить фактическое посещение. Это было даже если ученик не посещал какие-либо классы за это время, они все равно появятся в отчете (только с -/- за каждый день).

SELECT Students.Name_of_Student, Students.Roll_no, Students.Class, Students.Section, allDays.aDay, 
GROUP_CONCAT(IFNULL(attendance.Status, '-') ORDER BY TimePeriod.`time` DESC SEPARATOR '/') AS Status 
FROM (SELECT DISTINCT Name_of_Student, Roll_no, Class, Section FROM attendance where Section='$s' AND Class='$c') AS Students 
CROSS JOIN (SELECT 1 AS aDay UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9 UNION 
SELECT 10 AS aDay UNION SELECT 11 UNION SELECT 12 UNION SELECT 13 UNION SELECT 14 UNION SELECT 15 UNION SELECT 16 UNION SELECT 17 UNION SELECT 18 UNION SELECT 19 UNION 
SELECT 20 AS aDay UNION SELECT 21 UNION SELECT 22 UNION SELECT 23 UNION SELECT 24 UNION SELECT 25 UNION SELECT 26 UNION SELECT 27 UNION SELECT 28 UNION SELECT 29 UNION 
SELECT 30 UNION SELECT 31) allDays 
CROSS JOIN (SELECT 'Morning' AS `time` UNION SELECT 'Afternoon') TimePeriod 
LEFT OUTER JOIN attendance ON Students.Name_of_Student = attendance.Name_of_Student AND allDays.aDay = DAY(`Date`) 
AND BINARY TimePeriod.`time` = BINARY attendance.`time` 
AND Date Between '$f' and '$t' 
GROUP BY Students.Name_of_Student, Students.Roll_no, Students.Section, allDays.aDay 
ORDER BY Students.Name_of_Student, allDays.aDay

источник

2013-07-04 14:11:03 Kickstart

Спасибо большое. то, что я хочу сделать, это что-то вроде этого http://postimg.org/image/t46xc1laz/ Еще раз спасибо. –

Я только что протестировал ваш php-код и придумал пустой ... он ничего не печатает .. –

Ваш запрос не работает ... 'unknown column Students.Roll_no' –

Просмотр посещаемости datewise с помощью phpmysql

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