Невозможно создать объект с Hibernate. SQLGrammarException

Question

Я провел весь день, чтобы решить эту проблему. Ошибка возникает в соответствии с session.getTransaction().commit();

private SessionFactory sessionFactory = new Configuration().configure().buildSessionFactory(); 

@Override 
public void initGroup(Group group) throws BotException { 
    Session session = sessionFactory.openSession(); 

    try { 
     session.beginTransaction(); 
     session.persist(group); 
     session.getTransaction().commit(); 
    } catch (PersistenceException e) 
    { 
     throw new BotException("You are already registred"); 
    } 
    finally { 
     session.close(); 
     sessionFactory.close(); 
    } 

Удивительно, но у меня есть та же функция для объекта «Станция», но он работает отлично

Это странно так много. Я не знаю, как его решить.

Это мой Group.class

@Entity 
@Table(name = "group") 
public class Group { 
    private String name; 
    private String password; 
    private String telegramId; 
    private int experience; 
    private int money; 
    private String nowStation; 

    public Group() {} 

public Group(String name, String password, String telegramId) { 
    this.name = name; 
    this.password = password; 
    this.telegramId = telegramId; 
} 

@Id 
@Column(name = "name", nullable = false, length = 45) 
public String getName() { 
    return name; 
} 

public void setName(String name) { 
    this.name = name; 
} 

@Basic 
@Column(name = "password", nullable = false, length = 45) 
public String getPassword() { 
    return password; 
} 

public void setPassword(String password) { 
    this.password = password; 
} 

@Basic 
@Column(name = "telegram_id", nullable = false, length = 45) 
public String getTelegramId() { 
    return telegramId; 
} 

public void setTelegramId(String telegramId) { 
    this.telegramId = telegramId; 
} 

@Basic 
@Column(name = "experience", nullable = true) 
public int getExperience() { 
    return experience; 
} 

public void setExperience(int experience) { 
    this.experience = experience; 
} 

@Basic 
@Column(name = "money", nullable = true) 
public int getMoney() { 
    return money; 
} 

public void setMoney(int money) { 
    this.money = money; 
} 

@Basic 
@Column(name = "now_station", nullable = true, length = 45) 
public String getNowStation() { 
    return nowStation; 
} 

public void setNowStation(String nowStation) { 
    this.nowStation = nowStation; 
} 

и hibernate.cfg.xml

<?xml version='1.0' encoding='utf-8'?> 
<!DOCTYPE hibernate-configuration PUBLIC 
     "-//Hibernate/Hibernate Configuration DTD//EN" 
     "http://www.hibernate.org/dtd/hibernate-configuration-3.0.dtd"> 
<hibernate-configuration> 
    <session-factory> 
     <property name="connection.url">jdbc:mysql://localhost:3306/game_data_base</property> 
     <property name="connection.driver_class">com.mysql.jdbc.Driver</property> 
     <property name="dialect">org.hibernate.dialect.MySQLDialect</property> 
     <property name="connection.username">root</property> 
     <property name="connection.password">*******</property> 
     <mapping class="model.Group"/> 
     <mapping class="model.Station"/> 
     <mapping class="model.User"/> 
     <!-- DB schema will be updated if needed --> 
     <!-- <property name="hbm2ddl.auto">update</property> --> 
    </session-factory> 
</hibernate-configuration> 

Ошибки

сен 25, 2016 7:42:54 PM org.telegram.telegrambots.logging.BotLogger severe 
19:42:54.374 [PMPUTestBot Telegram Executor] DEBUG org.hibernate.service.internal.AbstractServiceRegistryImpl - Implicitly destroying ServiceRegistry on de-registration of all child ServiceRegistries 
SEVERE: BOTSESSION 
19:42:54.374 [PMPUTestBot Telegram Executor] INFO org.hibernate.orm.connections.pooling - HHH10001008: Cleaning up connection pool [jdbc:mysql://localhost:3306/game_data_base] 
javax.persistence.PersistenceException: org.hibernate.exception.SQLGrammarException: could not execute statement 
19:42:54.374 [PMPUTestBot Telegram Executor] DEBUG org.hibernate.boot.registry.internal.BootstrapServiceRegistryImpl - Implicitly destroying Boot-strap registry on de-registration of all child ServiceRegistries 
    at org.hibernate.internal.ExceptionConverterImpl.convert(ExceptionConverterImpl.java:147) 
    at org.hibernate.internal.ExceptionConverterImpl.convert(ExceptionConverterImpl.java:155) 
    at org.hibernate.internal.ExceptionConverterImpl.convert(ExceptionConverterImpl.java:162) 
    at org.hibernate.internal.SessionImpl.doFlush(SessionImpl.java:1411) 
    at org.hibernate.internal.SessionImpl.managedFlush(SessionImpl.java:475) 
    at org.hibernate.internal.SessionImpl.flushBeforeTransactionCompletion(SessionImpl.java:3168) 
    at org.hibernate.internal.SessionImpl.beforeTransactionCompletion(SessionImpl.java:2382) 
    at org.hibernate.engine.jdbc.internal.JdbcCoordinatorImpl.beforeTransactionCompletion(JdbcCoordinatorImpl.java:467) 
    at org.hibernate.resource.transaction.backend.jdbc.internal.JdbcResourceLocalTransactionCoordinatorImpl.beforeCompletionCallback(JdbcResourceLocalTransactionCoordinatorImpl.java:146) 
    at org.hibernate.resource.transaction.backend.jdbc.internal.JdbcResourceLocalTransactionCoordinatorImpl.access$100(JdbcResourceLocalTransactionCoordinatorImpl.java:38) 
    at org.hibernate.resource.transaction.backend.jdbc.internal.JdbcResourceLocalTransactionCoordinatorImpl$TransactionDriverControlImpl.commit(JdbcResourceLocalTransactionCoordinatorImpl.java:220) 
    at org.hibernate.engine.transaction.internal.TransactionImpl.commit(TransactionImpl.java:68) 
    at dao.GroupDaoImpl.initGroup(GroupDaoImpl.java:32) 

Спасибо :)

Answer 1

Group является SQL ключевых слов , Переименуйте свой стол в другое место

@Table(name = "my_group")