питон SMTP TypeError: Sendmail() отсутствует 1 требуется позиционную аргумент: 'сбщ'

Question

import tkinter 
import smtplib 
import socket 

from email.parser import Parser 

smtp = smtplib.SMTP 

user = "" 
password = "" 

def connect(): 
    print(msg_entry.get()) 

    smtp("localhost",25) 
    #smtp.login(user,password) 
    smtp.sendmail(from_entry.get(),to_entry.get(),msg_entry.get()) 
    smtp.quit() 

app = tkinter.Tk() 
app.title("test") 


to_label = tkinter.Label(app,text="To:") 
to_entry = tkinter.Entry(app) 

from_label = tkinter.Label(app,text="From:") 
from_entry = tkinter.Entry(app) 

send_button = tkinter.Button(app,text="send",command=connect) 

msg_label = tkinter.Label(app,text="Email:") 
msg_entry = tkinter.Entry(app,width=50) 
#pack(add) the widget to the app. 
to_label.pack() 
to_entry.pack() 

from_label.pack() 
from_entry.pack() 

msg_label.pack() 
msg_entry.pack() 

send_button.pack() 

#draw the window, have this at the end 
app.mainloop() 

Всякий раз, когда я нажал на кнопку посыла я получаю эту ошибку

Exception in Tkinter callback 
Traceback (most recent call last): 
    File "C:\Python34\lib\tkinter\__init__.py", line 1533, in __call__ 
    return self.func(*args) 
    File "C:\Users\Joshua\Documents\Code\Python\Jmail\main.py", line 17, in connect 
    smtp.sendmail(from_entry.get(),to_entry.get(),msg_entry.get()) 
TypeError: sendmail() missing 1 required positional argument: 'msg' 

Answer 1

Попробуйте это:

smtp = smtplib.SMTP("localhost",25) 
smtp.sendmail(from_entry.get(),to_entry.get(),msg_entry.get())