Как разделить макет XML с помощью Intent.ACTION_SEND

Question

Я искал везде, но не нашел решения ...

У меня есть две раскладки XML для использования. Я надул и правильно назначил представления.

shareLayout = LayoutInflater.from(getApplicationContext()).inflate(R.layout.share_every_for_self_game_layout, null); 
    contentView = (LinearLayout) shareLayout.findViewById(R.id.share_container_layout_id); 

Проблема в том, что общее изображение всегда пуст.

Вот мой код

private void shareResultToFacebook(){ 
    try { 
     Bitmap bitmap = getBitmapFromView(contentView); 

     Intent shareIntent = new Intent(); 
     shareIntent.setAction(Intent.ACTION_SEND); 
     shareIntent.putExtra(Intent.EXTRA_STREAM, getImageUri(this, bitmap)); 
     shareIntent.setType("image/jpeg"); 
     startActivity(Intent.createChooser(shareIntent, getResources().getText(R.string.send_to))); 

    }catch (Exception e){ 
     e.getMessage(); 
    } 

} 

//create bitmap from view and returns it 
private Bitmap getBitmapFromView(View view) { 
    try { 

     view.setDrawingCacheEnabled(true); 

     view.buildDrawingCache(); 
     //Define a bitmap with the same size as the view 
     Bitmap returnedBitmap = Bitmap.createBitmap(800, 600, Bitmap.Config.ARGB_8888); 
     //Bind a canvas to it 
     Canvas canvas = new Canvas(returnedBitmap); 
     //Get the view's background 
     Drawable bgDrawable = view.getBackground(); 
     if (bgDrawable != null) { 
      //has background drawable, then draw it on the canvas 
      bgDrawable.draw(canvas); 
     } else { 
      //does not have background drawable, then draw white background on the canvas 
      canvas.drawColor(Color.WHITE); 
     } 
     // draw the view on the canvas 
     view.draw(canvas); 
     //return the bitmap 
     return returnedBitmap; 
    }catch (Exception e){ 
     Global.logError("getBitmapFromView", e); 
    } 
    return null; 
} 


public Uri getImageUri(Context inContext, Bitmap inImage) { 
    try { 
     ByteArrayOutputStream bytes = new ByteArrayOutputStream(); 
     inImage.compress(Bitmap.CompressFormat.JPEG, 100, bytes); 
     String path = MediaStore.Images.Media.insertImage(inContext.getContentResolver(), 
       inImage, "", ""); 
     return Uri.parse(path); 
    }catch (Exception e){ 
     e.getMessage(); 
    } 
    return null; 
} 

Answer 1

Я нашел решение

я изменил свое getBitmapFromView тело метода

private Bitmap getBitmapFromView(LinearLayout view) { 
    try { 

     view.setDrawingCacheEnabled(true); 

     view.measure(View.MeasureSpec.makeMeasureSpec(800, View.MeasureSpec.UNSPECIFIED), 
       View.MeasureSpec.makeMeasureSpec(600, View.MeasureSpec.UNSPECIFIED)); 
     view.layout(0, 0, view.getMeasuredWidth(), view.getMeasuredHeight()); 

     view.buildDrawingCache(true); 
     Bitmap returnedBitmap = Bitmap.createBitmap(view.getDrawingCache()); 

     //Define a bitmap with the same size as the view 
     view.setDrawingCacheEnabled(false); 

     return returnedBitmap; 
    }catch (Exception e){ 
     Global.logError("getBitmapFromView", e); 
    } 
    return null; 
} 

И все работает отлично;)

Answer 2

private Bitmap getBitmapFromView(LinearLayout view) { 
    try { 

     view.setDrawingCacheEnabled(true); 

     view.buildDrawingCache(); 
     //Define a bitmap with the same size as the view 
     Bitmap returnedBitmap = Bitmap.createBitmap(800, 600, Bitmap.Config.ARGB_8888); 
     //Bind a canvas to it 
     Canvas canvas = new Canvas(returnedBitmap); 
     //Get the view's background 
     Drawable bgDrawable = view.getBackground(); 
     if (bgDrawable != null) { 
      //has background drawable, then draw it on the canvas 
      bgDrawable.draw(canvas); 
     } else { 
      //does not have background drawable, then draw white background on the canvas 
      canvas.drawColor(Color.RED); 
     } 
     // draw the view on the canvas 
     view.draw(canvas); 
     //return the bitmap 
     return returnedBitmap; 
    }catch (Exception e){ 
     // Global.logError("getBitmapFromView", e); 
    } 
    return null; 
}