Twitter 4j Нет проблем с проверкой подлинности. Соответствующие обсуждения можно найти в Интернете. Исключение

Question

Я использую twitter4j, я могу успешно войти в свою учетную запись Twitter, но когда я пытаюсь опубликовать что-то, возникает следующее исключение.

Мой код

try 
     { 

     Bitmap bmpFinal = getBitmapFromURL(Imagename.trim()); 
     Log.d("ImagePath",Imagename); 

     Configuration conf = new ConfigurationBuilder() 
     .setOAuthConsumerKey(TWITTER_CONSUMER_KEY) 
     .setOAuthConsumerSecret(TWITTER_CONSUMER_SECRET) 
     .setOAuthAccessToken(access_token) 
     .setOAuthAccessTokenSecret(access_token_secret) 
     .setMediaProviderAPIKey("320954b8bf13ffd7463a4dbe667b9dd2") 
     .build(); 

     Uri tempUri = getImageUri(getApplicationContext(), bmpFinal); 

     File finalFile = new File(getRealPathFromURI(tempUri));// THIS IS IMPORTANT. TWITPIC NEEDS THE ACTUAL/ABSOLUTE PATH OF THE IMAGE. JUST THE URI DOES NOT WORK!!!! 

     ImageUpload upload = new ImageUploadFactory(conf).getInstance(MediaProvider.TWITPIC); 

     String url = upload.upload(finalFile); 
     Log.e("TWITTER URL RESPONSE", url); 
     Log.d("TWITTER URL RESPONSE", url); 
     // END OF FIRST STEP: 

     // SECOND STEP IS TO UPLOAD TO TWITTER 

     ConfigurationBuilder builder = new ConfigurationBuilder(); 

     builder.setOAuthConsumerKey(TWITTER_CONSUMER_KEY); 
     builder.setOAuthConsumerSecret(TWITTER_CONSUMER_SECRET); 

     AccessToken accessToken = new AccessToken(access_token, access_token_secret); 
     Twitter twitter = new TwitterFactory(builder.build()).getInstance(accessToken); 

     String finalStatusWithURL = null; 

     if (status.trim().length() > 0) { 

      finalStatusWithURL = status + ":\n " + url; 

     } else { 
      finalStatusWithURL = url; 
     } 
     twitter4j.Status response = twitter.updateStatus(finalStatusWithURL); 
     Log.e("TWITTER RESPONSE", response.getText()); 
     } 
     catch(Exception e) 
     { 
      Log.d("Exception ",""+e); 
     } 
     return null; 
    } 

Logcat Исключение

06-14 12:51:31.117: D/Exception(3302): No authentication challenges found 
06-14 12:51:31.117: D/Exception(3302): Relevant discussions can be found on the Internet at: 
06-14 12:51:31.117: D/Exception(3302): http://www.google.co.jp/search?q=ea09dc6d or 
06-14 12:51:31.117: D/Exception(3302): http://www.google.co.jp/search?q=051c1797 
06-14 12:51:31.117: D/Exception(3302): TwitterException{exceptionCode=[ea09dc6d-051c1797 0237e8c8-9e66d70f], statusCode=-1, message=null, code=-1, retryAfter=-1, rateLimitStatus=null, version=3.0.2} 

Answer 1

twitter = new TwitterFactory().getInstance(); 
    //Retrieve access token      
    authProvider.retrieveAccessToken(authConsumer,verifier); 

    //Initialize access token of twitter4j 
    AccessToken mAccessToken = new AccessToken(authConsumer.getToken(),authConsumer.getTokenSecret()); 

    //optional to save it for future use      
    ProjectUtil.setAccessTokenTwitter((MainActivity)mScreen, mAccessToken.getToken()); 
    ProjectUtil.setAccessSecretTwitter((MainActivity)mScreen, mAccessToken.getTokenSecret()); 

    //Set twitter4j.Twitter Oauth      
    twitter.setOAuthConsumer(AppConstants.CONSUMER_KEY, AppConstants.CONSUMER_SECRET); 
    twitter.setOAuthAccessToken(mAccessToken); 
    //message      
    StatusUpdate ad=new StatusUpdate("my messgae"); 

    //Image from sdcard  
    File file = new File(Environment.getExternalStorageDirectory()+"/myimage.png"); 
    InputStream inputStream = new FileInputStream(file); 
    ad.setMedia("myMedia",inputStream); 

    twitter4j.Status response = twitter.updateStatus(ad); 



    Log.d("Status", response.getText());