Как получить значение столбца, которое определено в другой таблице

Question

Любая помощь мне для отслеживания ожидаемого результата? Я также добавил структуры базы данных

TABLE1

ID Work Id Question      Column Column Type 
1 1 What is your name?  field1 String 
2 1 is you have mobile number? field2 boolean 
3 2 is you have passport?  field2 boolean 
4 2 are you indian?    field4 boolean 
5 2 abc?       field5 Number 
6 3 cde?       field2 boolean 

TABLE2

Id WorkId field1 field2 field3 field4 field5 
1 1 JOHN  1   
2 2   1  0 1 
3 3   0   

Ожидаемый выходной

Work Id Question     Answer 
1 What is your name?   JOHN 
1 is you have mobile number? 1 
2 is you have passport?   1 
2 are you indian?     0 
2 abc?       1 
3 cde?       0 

Структура таблица

CREATE DATABASE /*!32312 IF NOT EXISTS*/`testtest` /*!40100 DEFAULT CHARACTER SET utf8 */; 

USE `testtest`; 

/*Table structure for table `table1` */ 

DROP TABLE IF EXISTS `table1`; 

CREATE TABLE `table1` (
    `Id` int(11) NOT NULL AUTO_INCREMENT, 
    `WorkId` int(11) DEFAULT NULL, 
    `Question` varchar(100) DEFAULT NULL, 
    `ColumnRef` varchar(100) DEFAULT NULL, 
    `ColumnType` varchar(100) DEFAULT NULL, 
    PRIMARY KEY (`Id`) 
) ENGINE=InnoDB AUTO_INCREMENT=7 DEFAULT CHARSET=utf8; 

/*Data for the table `table1` */ 

insert into `table1`(`Id`,`WorkId`,`Question`,`ColumnRef`,`ColumnType`) values (1,1,'What is your name?','field1','String'),(2,1,'is you have mobile number?','field2','boolean'),(3,2,'is you have passport?','field2','boolean'),(4,2,'are you indian?','field4','boolean'),(5,2,'abc?','field5','Number'),(6,3,'CDE?','field2','boolean'); 

/*Table structure for table `table2` */ 

DROP TABLE IF EXISTS `table2`; 

CREATE TABLE `table2` (
    `id` int(11) NOT NULL AUTO_INCREMENT, 
    `workid` int(11) DEFAULT NULL, 
    `field1` varchar(11) DEFAULT NULL, 
    `field2` int(11) DEFAULT NULL, 
    `field3` int(11) DEFAULT NULL, 
    `field4` int(11) DEFAULT NULL, 
    `field5` int(11) DEFAULT NULL, 
    PRIMARY KEY (`id`) 
) ENGINE=InnoDB AUTO_INCREMENT=4 DEFAULT CHARSET=utf8; 

/*Data for the table `table2` */ 

insert into `table2`(`id`,`workid`,`field1`,`field2`,`field3`,`field4`,`field5`) values (1,1,'JOHN',1,NULL,NULL,NULL),(2,2,NULL,1,NULL,0,1),(3,3,NULL,1,NULL,NULL,NULL); 

Answer 1

Надеется, что это поможет вам

SELECT t1.workid AS 'workid',t1.Question AS 'Question', 
COALESCE(`field1`,`field2`,`field3`,`field4`,`field5`) AS 'Answer' 
FROM table1 AS t1 
JOIN table2 AS t2 ON t1.workid = t2.workid 

SQL Fiddle