скрыть поле ввода, если загрузка выполнена успешно

Question

Я хотел бы скрыть поле ввода, если загрузка выполнена успешно. Я попытался скрыть его, поставив $sub =1; и if($sub==0), как показано ниже, но он скрывает входные данные всякий раз, когда нажимают кнопку «Отправить», когда загрузка не удалась. есть идеи?

<?php 

function uploadFile ($file_field = null, $check_image = false, $random_name = false) { 

//Config Section  
//Set file upload path 
$path = 'productpic/'; //with trailing slash 
//Set max file size in bytes 
$max_size = 2097152; 
//Set default file extension whitelist 
$whitelist_ext = array('jpg','png','gif'); 
//Set default file type whitelist 
$whitelist_type = array('image/jpeg', 'image/png','image/gif'); 

//The Validation 
// Create an array to hold any output 
$out = array('error'=>null); 

if (!$file_field) { 
$out['error'][] = "Please specify a valid form field name";   
} 

if (!$path) { 
$out['error'][] = "Please specify a valid upload path";    
} 

if (count($out['error'])>0) { 
return $out; 
} 

//Make sure that there is a file 
if((!empty($_FILES[$file_field])) && ($_FILES[$file_field]['error'] == 0)) { 

// Get filename 
$file_info = pathinfo($_FILES[$file_field]['name']); 
$name = $file_info['filename']; 
$ext = $file_info['extension']; 

//Check file has the right extension   
if (!in_array($ext, $whitelist_ext)) { 
    $out['error'][] = "Invalid file Extension"; 
} 

//Check that the file is of the right type 
if (!in_array($_FILES[$file_field]["type"], $whitelist_type)) { 
    $out['error'][] = "Invalid file Type"; 
} 

//Check that the file is not too big 
if ($_FILES[$file_field]["size"] > $max_size) { 
    $out['error'][] = "We are sorry, the image must be less than 2MB"; 
} 

//If $check image is set as true 
if ($check_image) { 
    if (!getimagesize($_FILES[$file_field]['tmp_name'])) { 
    $out['error'][] = "The file you trying to upload is not an Image, we only accept images"; 
    } 
} 

//Create full filename including path 
if ($random_name) { 

    // Generate random filename 
    $tmp = str_replace(array('.',' '), array('',''), microtime()); 

    if (!$tmp || $tmp == '') { 
    $out['error'][] = "File must have a name"; 
    }  
    $newname = $tmp.'.'.$ext;         
} else { 
    $newname = $name.'.'.$ext; 
} 

//Check if file already exists on server 
if (file_exists($path.$newname)) { 
    $out['error'][] = "The image you trying to upload already exists, please upload only once"; 
} 

if (count($out['error'])>0) { 
    //The file has not correctly validated 
    return $out; 
} 

if (move_uploaded_file($_FILES[$file_field]['tmp_name'], $path.$newname)) { 
    //Success 

    $out['filepath'] = $path; 
    $out['filename'] = $newname; 
    return $out; 
} else { 
    $out['error'][] = "Server Error!"; 
} 

} else { 
$out['error'][] = "Please select a photo"; 
return $out; 
}  
} 
?> 

<?php 

if (isset($_POST['submit'])) { 
$sub=1; 
$file = uploadFile('file', true, false); 
if (is_array($file['error'])) { 
$message = ''; 
foreach ($file['error'] as $msg) { 
    $message .= '<p>'.$msg.'</p>';  
} 
} else { 
$message = "File uploaded successfully"; 
} 
echo $message; 
} 
?> 
<form action="" method="post" enctype="multipart/form-data" name="form1" id="form1"> 
<?php 
ini_set("display_errors", 0); 
if($sub==0) 
{ 
?> 
<input name="file" type="file" size="20" /> 
<input name="submit" type="submit" value="Upload" /> 
<?php 
} 
?> 
</form> 

Answer 1

Попробуйте

if (is_array($file['error'])) { 
$message = ''; 
foreach ($file['error'] as $msg) { 
    $message .= '<p>'.$msg.'</p>';  
} 
} else { 
$message = "File uploaded successfully"; 
$sub=1; // keep here sub=1 
} 

В $ к югу = 1 выполняется при отправке нажимается, так как оно дано в if (isset($_POST['submit'])) это означает, что, если представить это set.It следует, когда загрузка будет завершена.