Как получить будние дни из запроса?

Question

Как мне получить имя будний день после OrderH_dtmInitiated колонки

SELECT 
    Convert(char(8), OrderH_dtmInitiated, 112) AS BookingDate, 
    --(To derived weekdays name from OrderH_dtmInitiated namely weekdays here) 
    [OrderH_strEmailConfirmationSent], [OrderH_strEmail] 
FROM 
    [VISTAIT].[dbo].[tblOrderHistory] 
WHERE 
    OrderH_strEmailConfirmationSent IS NULL 
    AND OrderH_dtmInitiated >= (SELECT DATEADD(dd, 0, DATEDIFF(dd, 0, GETDATE()-1))) 
ORDER BY 
    Convert(char(8), OrderH_dtmInitiated, 112) 

Answer 1

Вы можете использовать datename:

SELECT 
    Convert(char(8), OrderH_dtmInitiated, 112) As BookingDate, 
    Datename (weekday, OrderH_dtmInitiated) As NameOfDay, 
    [OrderH_strEmailConfirmationSent] 
    ,[OrderH_strEmail] 
FROM [VISTAIT].[dbo].[tblOrderHistory] 
WHERE OrderH_strEmailConfirmationSent is NULL And OrderH_dtmInitiated >= (SELECT DATEADD(dd, 0, DATEDIFF(dd, 0, GETDATE()-1))) 
ORDER by Convert(char(8), OrderH_dtmInitiated, 112) 

Answer 2

SELECT 
Convert(char(8), OrderH_dtmInitiated, 112)as datebooking, 
    Datename (weekday, OrderH_dtmInitiated) As NameOfDay, 
    count(distinct OrderH_strCinemaId)as cinemassite, 
    count(distinct OrderH_intID)as TotalBookingMade, 
    SUM(case when OrderH_strEmailConfirmationSent like 'Y' then 1 else 0 end) as OrderH_strEmailConfirmationSent, 
    SUM(case when OrderH_strEmailConfirmationSent is NULL then 1 else 0 end) as EmailHavingNull 

FROM [VISTAIT].[dbo].[tblOrderHistory] 
WHERE OrderH_dtmInitiated >= '2015-05-07' 
GROUP BY Convert(char(8), OrderH_dtmInitiated, 112) 
ORDER by Convert(char(8), OrderH_dtmInitiated, 112)