Мне нужен код, который позволяет мне найти наивысший балл в моем .txt doc

Question

Также с моим усреднением он несколько раз печатает имя слишком много раз. У меня есть этот код, но борюсь с указанием оценки низкого до самого высокого в моем текстовый файл, он выглядит следующим образом:
имя, 1
имя, 4
имя, 7
имя, 9
имя, 10

Это мой код:

import sys 

Viewclassnum= input ('Which class do you want to view 1,2 or 3?') 
print('please input a, b or c') 
print('a)Alphabeically') 
print('b)average') 
print('c)highest to lowest') 
Viewclasssort= input ('how would you like to view it:') 



                            #setting variable fd to open the file set to File_name (from when the program asked the user for 

if Viewclassnum=='1' and Viewclasssort=='a': 
    with open('class1.txt', 'r') as r: 
     for line in sorted(r): 
      print(line, end='') 
    Again=input('Do you want to view another class yes or no?') 
    if Again=='yes': 
     Viewclassnum= input ('Which class do you want to view 1,2 or 3?') 
     print('please input a, b or c') 
     print('a)Alphabeically') 
     print('b)average') 
     print('c)highest to lowest') 
     Viewclasssort= input ('how would you like to view it:') 
    if Again=='no': 
     print('Bye') 


if Viewclassnum=='1' and Viewclasssort=='b': 
    fd = open('class1.txt') 
    lines = [line.strip() for line in fd] 
    f = {} 
    for line in lines: 
    split = [i for i in line.split(',')] 
    key = split[0] 
    f[key] = [int(n) for n in split[1:]] 
    avg_mark = lambda name:sum(f[name])/len(f[name]) 
    for i in sorted(f.keys(),key=avg_mark,reverse=True): 
     print (i,avg_mark(i),"\n") 
    Again=input('Do you want to view another class yes or no?') 
    if Again=='yes': 
     Viewclassnum= input ('Which class do you want to view 1,2 or 3?') 
     print('please input a, b or c') 
     print('a)Alphabeically') 
     print('b)average') 
     print('c)highest to lowest') 
     Viewclasssort= input ('how would you like to view it:') 
    if Again=='no': 
     print('Bye') 

выход:

Which class do you want to view 1,2 or 3?1 
please input a, b or c 
a)Alphabeically 
b)average 
c)highest to lowest 
how would you like to view it:a 
name,3 
name,8 
name,9 
2name,4 
2name,7 
2name,8 
Do you want to view another class yes or no?yes 
Which class do you want to view 1,2 or 3?1 
please input a, b or c 
a)Alphabeically 
b)average 
c)highest to lowest 
how would you like to view it:b 
name 3.0 

name 8.0 

name 9.0 

2name 9.0 

2name 4.0 

name 9.0 (repeated don't know why) 

name 7.0 

Я также хотел бы, чтобы сгруппировать все имена вместе, так что это выглядит следующим образом:

имя, 3,5,6
2name, 4,5,6

и только три последние показаны оценки. Для самого высокого до самого низкого балла я бы ожидать такой результат: имени, 10 2name, 8 5name, 4 3name, 5

Благодаря

Answer 1

Вот как я думаю, я бы справиться с этим. Безусловные словари не упорядочены, они не сортируются, поэтому я составил список объектов Student, которые можно сортировать.

я уменьшил много вашего ввода кода, который был повторен 3 раза

import sys 

class Student: 
    def __init__(self, name, marks): 
     self.name = name 
     self.marks = marks 
    def avg_mark(self): 
     return sum(self.marks)/len(self.marks) 
    def __str__(self): 
     return '{0}: {1}, {2}'.format(self.name, self.marks, self.avg_mark()) 

def load_grades(filename): 
    fd = open(filename, 'r') 
    f = {} 
    for line in fd: 
     split = line.split(',') 
     key = split[0] 
     marks = [int(n) for n in split[1:]] 
     try: 
      f[key] += marks 
     except KeyError: 
      f[key] = marks 
    students = [] 
    for key, values in f.items(): 
     students.append(Student(key, values[-3:])) 
    return students 

def sort_by_name(students): 
    def get_name(student): 
    return student.name 
    students = sorted(students, key=get_name) 
    return students 

def sort_by_avg(students): 
    def get_avg(student): 
     return student.avg_mark() 
    students = sorted(students, key=get_avg) 
    return students 


again = True 

while again: 
    class_num = input ('Which class do you want to view 1,2 or 3?') 
    print('please input a, b or c') 
    print('a)Alphabeically') 
    print('b)average') 
    print('c)highest to lowest') 
    sort = input ('how would you like to view it:') 

    if class_num =="1" and sort =="a": 
     students = load_grades('class1.txt') 
     students = sort_by_name(students) 
    elif class_num =="1" and sort =="b": 
     students = load_grades('class1.txt') 
     students = sort_by_avg(students) 

    for student in students: 
     print(student) 


    Again=input('Do you want to view another class yes or no?') 
    again = (Again=='yes') 

print('bye') 

Пример вывода:

Which class do you want to view 1,2 or 3?1 
please input a, b or c 
a)Alphabeically 
b)average 
c)highest to lowest 
how would you like to view it:a 
2name: [4, 7, 8, 69], 22.0 
name: [3, 8, 9], 6.666666666666667 
Do you want to view another class yes or no?yes 
Which class do you want to view 1,2 or 3?1 
please input a, b or c 
a)Alphabeically 
b)average 
c)highest to lowest 
how would you like to view it:b 
name: [3, 8, 9], 6.666666666666667 
2name: [4, 7, 8, 69], 22.0 
Do you want to view another class yes or no?no 
bye