Так что мне нужно знать, как я могу подключить сразу две базы данных. Что я делаю, это получение некоторой информации из одной таблицы db и ее перенос в другую БД.OOPHP соединяет две базы данных
Я пробовал следующее.
public function sitelistingcron()
{
$sqlk = mysql_query("SELECT * FROM customer_detail WHERE approvedforsite = 2 OR approvedforsite = 3");
include_once('database2.php');
$fet = new Dbase();
$fet->Connect();
$fet->DB();
while($row = mysql_fetch_array($sqlk)){
//ADD
$this->customer_id = $row['customer_id'];
$this->tradingname = $row['TradingName'];
$this->phone = $row['Phone'];
$this->street = $row['Street'];
$this->city = $row['City'];
$this->state = $row['State'];
$this->postcode = $row['PostCode'];
$this->approved = $row['approvedforsite'];
$this->description = $row['Description'];
if($this->approved = 2)
{
$sqk = mysql_query("INSERT INTO approved_business_info (id, tradingname, phonenumber, street, postcode, suburb, discription) VALUES ({$this->customer_id}, '{$this->tradingname}', '{$this->phone}', '{$this->street}', '{$this->city}', '{$this->postcode}', '{$this->description}') ON DUPLICATE KEY UPDATE id = {$this->customer_id}, tradingname ='{$this->tradingname}', phonenumber ='{$this->phone}', street = '{$this->street}', postcode = '{$this->postcode}', suburb = '{$this->city}', discription = '{$this->discription}'") or mysql_error();
print "INSERT INTO approved_business_info (id, tradingname, phonenumber, street, postcode, suburb, discription) VALUES ({$this->customer_id}, '{$this->tradingname}', '{$this->phone}', '{$this->street}', '{$this->city}', '{$this->postcode}', '{$this->description}') ON DUPLICATE KEY UPDATE id = {$this->customer_id}, tradingname ='{$this->tradingname}', phonenumber ='{$this->phone}', street = '{$this->street}', postcode = '{$this->postcode}', suburb = '{$this->city}', discription = '{$this->discription}'";
}
//REMOVE
if($this->approved = 3)
{
$sqk = mysql_query("DELETE FROM `approved_business_info` WHERE id = {$this->customer_id}");
}
}
}
'$ result = sql_query ($ conn1, $ sql1); $ sql2 = makeInsertStatements ($ result); sql_update ($ conn2, $ sql2); ' – bdares
Как * вы подключаетесь к db? Просто сделайте это дважды ...? – deceze
, пожалуйста, прекратите использовать старую функцию 'mysql_ *' и научитесь использовать [PDO] (http://php.net/pdo) или [MySQLi] (http://php.net/mysqli) с подготовленными операторами. –