Возврат мульти столбцов в результате одной таблицы с нулевыми значениями

Question

У меня есть одна таблица, как:

 
mysql> select RefID,State,StartTime,EndTime from execReports limit 5; 
+--------------------------------------+-----------+---------------------+---------------------+ 
| RefID        | State  | StartTime   | EndTime    | 
+--------------------------------------+-----------+---------------------+---------------------+ 
| 00019a52-8480-4431-9ad2-3767c3933627 | Completed | 2016-04-18 13:45:00 | 2016-04-18 13:45:01 | 
| 00038a8a-995e-4cb2-a335-cb05d5b3e92d | Aborted | 2016-05-03 04:00:00 | 2016-05-03 04:00:02 | 
| 001013f8-0b86-456f-bd59-a7ef066e565f | Completed | 2016-04-14 03:30:00 | 2016-04-14 03:30:11 | 
| 001f8d23-3022-4271-bba0-200494de678a | Failed | 2016-04-30 05:00:00 | 2016-04-30 05:00:02 | 
| 0027ba42-1c37-4e50-a7d6-a4e24056e080 | Completed | 2016-04-18 03:45:00 | 2016-04-18 03:45:02 | 
+--------------------------------------+-----------+---------------------+---------------------+ 

можно извлечь счетчик Exec для каждого состояния с:

 
mysql> select distinct State,count(StartTime) as nbExec from execReports group by State; 
+-----------+--------+ 
| State  | nbExec | 
+-----------+--------+ 
| Aborted |  3 | 
| Completed | 14148 | 
| Failed |  49 | 
+-----------+--------+ 
4 rows in set (0.02 sec) 

можно извлечь кол Exec на каждую неделю с:

 

mysql> select distinct extract(week from StartTime) as Week, count(StartTime) as nbExec from execReports group by Week; 
+------+--------+ 
| Week | nbExec | 
+------+--------+ 
| 14 | 1317 | 
| 15 | 3051 | 
| 16 | 3066 | 
| 17 | 3059 | 
| 18 | 3059 | 
| 19 | 652 | 
+------+--------+ 
6 rows in set (0.01 sec) 

Но я хотел бы, чтобы извлечь таблицу пересечения, как:

 

+------+---------+-----------+--------+---------+---------+ 
| Week | nbExec | Completed | Failed | Running | Aborted | 
+------+---------+-----------+--------+---------+---------+ 
| 14 | 1317 | 1312 | 3 | 1 | 1 | 
| 15 | 3051 | 3050 | 1 | 0 | 0 | 
| 16 | 3066 | 3060 | 3 | 2 | 1 | 
| 17 | 3059 | 3058 | 0 | 1 | 0 | 
| 18 | 3059 | 3057 | 1 | 0 | 1 | 
| 19 | 652 | 652  | 0 | 0 | 0 | 
+------+---------+-----------+--------+---------+---------+ 

Я застрял на этом несколько дней. Любая помощь оценивается.

С уважением

Answer 1

Вы можете присоединиться к нескольким столам для этого. Если вы хотите для динамического ряда к колонке, проверить это: MySQL pivot row into dynamic number of columns

SELECT 
    a.week, 
    count(a.StartTime) as nbExec, 
    count(b1.StartTime) as Completed, 
    count(b2.StartTime) as Failed, 
    count(b3.StartTime) as Running, 
    count(b4.StartTime) as Aborted, 

FROM execReports a 
LEFT JOIN execReports b1 ON a.refID = b1.refID and b1.state ='Completed' 
LEFT JOIN execReports b2 ON a.refID = b2.refID and b2.state ='Failed' 
LEFT JOIN execReports b3 ON a.refID = b3.refID and b3.state ='Running' 
LEFT JOIN execReports b4 ON a.refID = b4.refID and b4.state ='Aborted' 
GROUP BY 1 

Answer 2

select extract(week from StartTime) as Week, count(StartTime) as nbExec, 
     sum(if(state="Completed",1,0)) Completed, 
     sum(if(state="Failed",1,0)) Failed, 
     sum(if(state="Aborted",1,0)) Aborted 
    from execReports group by Week; 

demo