Python месяц и день разница

Question

Скажем, у меня есть две даты:

2016-05-05 и 2016-08-10

Я хочу выходные 26 (дней) 2 (месяцев) и 10 (дней)

2016-05-05 - 2016-05-31 = 26 days 

2016-06-01 - 2016-07-31 = 2 months 

2016-08-01 - 2016-08-10 = 10 days 

Answer 1

from datetime import datetime 

def months_between(date1,date2): 
    if date1>date2: 
     date1,date2=date2,date1 
    m1=date1.year*12+date1.month 
    m2=date2.year*12+date2.month 
    months=m2-m1 
    if date1.day>date2.day: 
     months-=1 
    elif date1.day==date2.day: 
     seconds1=date1.hour*3600+date1.minute+date1.second 
     seconds2=date2.hour*3600+date2.minute+date2.second 
     if seconds1>seconds2: 
      months-=1 
    return months 

date_format = "%Y-%m-%d" 

date1 = "2016-05-05" 
date2 = "2016-05-31" 
date3 = "2016-06-01" 
date4 = "2016-07-31" 
date5 = "2016-08-01" 
date6 = "2016-08-10" 

date1_datetime = datetime.strptime(date1, date_format) 
date2_datetime = datetime.strptime(date2, date_format) 
date3_datetime = datetime.strptime(date3, date_format) 
date4_datetime = datetime.strptime(date4, date_format) 
date5_datetime = datetime.strptime(date5, date_format) 
date6_datetime = datetime.strptime(date6, date_format) 

difference1 = date2_datetime - date1_datetime 
difference2 = months_between(date3_datetime, date4_datetime) 
difference3 = date2_datetime - date1_datetime 

print("%s - %s = %d days" % (date2, date1, difference1.days)) 
print("%s - %s = %d months" % (date3, date4, difference2)) 
print("%s - %s = %d days" % (date6, date5, difference3.days)) 

Выход:

2016-05-31 - 2016-05-05 = 26 days 
2016-07-31 - 2016-06-01 = 1 months 
2016-08-10 - 2016-08-01 = 26 days 

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