Хотя я могу успешно создать хранимую процедуру, я получаю ошибку "TRANSACTION BEGIN END MISMATCH"
при ее использовании. Хранимая процедура отлично работает при удалении транзакции.SQL TRANSACTION Начинают несоответствие конца?
ALTER PROCEDURE Proc_LoanRepayment @LASAcctno [VARCHAR] (15),
@EntryDate [VARCHAR] (8),
@ValueDate [VARCHAR] (8),
@ModeofPayment VARCHAR(20),
@ChqNo VARCHAR(20),
@ChqDate VARCHAR(8),
@ChqAmt MONEY,
@CstBnkNo VARCHAR(20),
@Cstbnkid VARCHAR(20),
@CmpBnkNo VARCHAR(20),
@Cmpbnkid VARCHAR(20),
@Narration1 [VARCHAR] (100),
@Narration2 [VARCHAR] (100),
@EntryType VARCHAR(30),
@PostingString [VARCHAR] (max)
AS
BEGIN TRAN
DECLARE @string AS VARCHAR(max)
DECLARE Cur_A CURSOR FOR
SELECT *
FROM dbo.split(@PostingString, ',')
OPEN Cur_a
FETCH NEXT FROM cur_a INTO @string
WHILE @@FETCH_STATUS = 0
BEGIN
IF (object_id('TempDB..#Temp')) IS NOT NULL
BEGIN
DROP TABLE #Temp
END
-- declare @temp table (srno int identity,items varchar(max))
SELECT *
INTO #temp
FROM dbo.Split(@string, '|')
DECLARE @LoanNo AS VARCHAR(20),
@BankAcct AS VARCHAR(20),
@TDS AS MONEY,
@LASPAC AS MONEY,
@INTRND AS MONEY,
@INTRAC AS MONEY,
@STAXPLRVL AS MONEY,
@PNLINT AS MONEY,
@OVRDUEINT AS MONEY,
@STMPDTYRVL AS MONEY,
@PROFESRVL AS MONEY,
@DOCCHGRVL AS MONEY,
@CHQBNCRVL AS MONEY
ALTER TABLE #temp
ADD srno INT IDENTITY
SELECT @LoanNo = items
FROM #temp
WHERE srno = 1
SELECT @bankAcct = items
FROM #temp
WHERE srno = 2
SELECT @TDS = items
FROM #temp
WHERE srno = 3
SELECT @LASPAC = items
FROM #temp
WHERE srno = 4
SELECT @INTRND = items
FROM #temp
WHERE srno = 5
SELECT @INTRAC = items
FROM #temp
WHERE srno = 6
SELECT @STAXPLRVL = items
FROM #temp
WHERE srno = 7
SELECT @PNLINT = items
FROM #temp
WHERE srno = 8
SELECT @OVRDUEINT = items
FROM #temp
WHERE srno = 9
SELECT @STMPDTYRVL = items
FROM #temp
WHERE srno = 10
SELECT @PROFESRVL = items
FROM #temp
WHERE srno = 11
SELECT @DOCCHGRVL = items
FROM #temp
WHERE srno = 12
SELECT @CHQBNCRVL = items
FROM #temp
WHERE srno = 13
INSERT INTO Tbl_BankEntry
(LASAcctno,
EntryDate,
ValueDate,
ModeofPayment,
ChqNo,
ChqDate,
ChqAmt,
CstBnkNo,
Cstbnkid,
CmpBnkNo,
Cmpbnkid,
Narration1,
Narration2,
LoanNo,
BankAcct,
TDS,
LASPAC,
INTRND,
INTRAC,
STAXPLRVL,
PNLINT,
OVRDUEINT,
STMPDTYRVL,
PROFESRVL,
DOCCHGRVL,
CHQBNCRVL,
status,
mkrdt,
mkrid,
EntryType)
VALUES (@LASAcctno,
@EntryDate,
@ValueDate,
@ModeofPayment,
@ChqNo,
@ChqDate,
@ChqAmt,
@CstBnkNo,
@Cstbnkid,
@CmpBnkNo,
@Cmpbnkid,
@Narration1,
@Narration2,
@LoanNo,
@BankAcct,
@TDS,
@LASPAC,
@INTRND,
@INTRAC,
@STAXPLRVL,
@PNLINT,
@OVRDUEINT,
@STMPDTYRVL,
@PROFESRVL,
@DOCCHGRVL,
@CHQBNCRVL,
'P',
GETDATE(),
'c97176',
@EntryType )
FETCH NEXT FROM Cur_a INTO @string
END
CLOSE cur_a
DEALLOCATE cur_a
RETURN
COMMIT TRAN
@MitchWheat означает, что я не могу использовать транзакцию в случае курсора? – Arbaaz
уверен, что вы можете. Но милые щенки умирают каждый раз, когда вы делаете! :) –
Если вы находитесь в 2008 году, просмотрите параметры таблицы, а не разделите строки. –