Я новичок в использовании сервлета. Я хочу запустить простой код сервлета helloWorld, но при запуске я получаю эту ошибку 404: запрошенный ресурс() недоступен.новый сервлет helloWorld
мое название проекта - «ServletPractice».
мой Java класс:
package one;
import java.io.IOException;
import java.io.PrintWriter;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
public class HelloWorld extends HttpServlet {
private String message;
public void init(){
message = "hello world";
}
public void doGet(HttpServletRequest request , HttpServletResponse response) throws IOException , ServletException{
response.setContentType("text/html");
PrintWriter out = response.getWriter();
out.println("<h1>" + message + "</h1>");
}
public void destroy()
{
// do nothing.
}
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
}
}
и мой web.xml является:
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" version="3.0">
<display-name>ServletPractice</display-name>
<servlet>
<servlet-name>Faces Servlet</servlet-name>
<servlet-class>javax.faces.webapp.FacesServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>Faces Servlet</servlet-name>
<url-pattern>/faces/*</url-pattern>
</servlet-mapping>
<context-param>
<param-name>javax.servlet.jsp.jstl.fmt.localizationContext</param-name>
<param-value>resources.application</param-value>
</context-param>
<context-param>
<description>State saving method: 'client' or 'server' (=default). See JSF Specification 2.5.2</description>
<param-name>javax.faces.STATE_SAVING_METHOD</param-name>
<param-value>client</param-value>
</context-param>
<context-param>
<description>
This parameter tells MyFaces if javascript code should be allowed in
the rendered HTML output.
If javascript is allowed, command_link anchors will have javascript code
that submits the corresponding form.
If javascript is not allowed, the state saving info and nested parameters
will be added as url parameters.
Default is 'true'</description>
<param-name>org.apache.myfaces.ALLOW_JAVASCRIPT</param-name>
<param-value>true</param-value>
</context-param>
<context-param>
<description>
If true, rendered HTML code will be formatted, so that it is 'human-readable'
i.e. additional line separators and whitespace will be written, that do not
influence the HTML code.
Default is 'true'</description>
<param-name>org.apache.myfaces.PRETTY_HTML</param-name>
<param-value>true</param-value>
</context-param>
<context-param>
<param-name>org.apache.myfaces.DETECT_JAVASCRIPT</param-name>
<param-value>false</param-value>
</context-param>
<context-param>
<description>
If true, a javascript function will be rendered that is able to restore the
former vertical scroll on every request. Convenient feature if you have pages
with long lists and you do not want the browser page to always jump to the top
if you trigger a link or button action that stays on the same page.
Default is 'false'
</description>
<param-name>org.apache.myfaces.AUTO_SCROLL</param-name>
<param-value>true</param-value>
</context-param>
<listener>
<listener-class>org.apache.myfaces.webapp.StartupServletContextListener</listener-class>
</listener>
<servlet>
<servlet-name>ServletPractice</servlet-name>
<servlet-class>ServletPractice</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>ServletPractice</servlet-name>
<url-pattern>/ServletPractice</url-pattern>
</servlet-mapping>
</web-app>
ошибка:
HTTP Status 404 -
type: Status report
message:
description: The requested resource() is not available.
Apache Tomcat/7.0.16
и мой адрес в адресной строки является: локальный: 9090 /ServletPractice/WEB-INF/web.xml
, пожалуйста, помогите мне. thank
как вы пытаетесь обратиться к этому сервлет? – Sanjeev
Класс сервлета неправильный, вам нужно передать его классу HelloWorld –
@hossein Сторона примечания: вам не нужен «главный» метод в сервлет. – Bhushan