Mysql данные петли из 2 таблицы

Question

У меня есть 2 таблицы, как показано ниже:

Таблица 1: common_member

+-----------+-----------+ 
| uid  | username | 
+-----------+-----------+ 
| 1   | haha  | 
| 2   | walao  | 
| 3   | alamak | 
| 4   | hero  | 
| 5   | theone | 
| 6   | nobody | 
+-----------+-----------+ 

Таблица 2: labour_slog

+--------------+-------------+--------------+-------------+ 
| uid   | slaveid  | masterid  | bytime  | 
+--------------+-------------+--------------+-------------+ 
| 1   | 2   | 3   | 123456  | 
| 4   | 5   | 6   | 456789  | 
+--------------+-------------+--------------+-------------+ 

я выборки данных, как сценарий ниже:

$queryLabourSlog = DB::query("SELECT * FROM ".DB::table('labour_slog')." ORDER BY id desc"); 
    while($rowLabourSlog = DB::fetch($queryLabourSlog)) { 
     $user_list_slog[] = $rowLabourSlog; 
    }; 
    array_multisort($idss, SORT_DESC, $user_list_slog); 

В моем HTML, я использую

<!--{loop $user_list_slog $value}-->{$value[uid]} on {$value[bytime]} forced hire {$value[masterid]}'s employee {$value[slaveid]}.<!--{/loop}--> 

HTML, будет отображаться:

1 on 123456 forced hire 3's employee 2. 
4 on 456789 forced hire 6's employee 5. 

Как присоединиться к имени пользователя СРЕДУ Table 1 «s, чтобы получить дисплей цикла, как показано ниже?

haha on 123456 forced hire alamak's employee walao. 
hero on 456789 forced hire nobody's employee theone. 

Спасибо.

Answer 1

SELECT table_slog.*, u1.`name`, u2.`name` FROM `table_slog` LEFT JOIN `common_member` AS u1 ON `table_slog`.`uid`=u1.`uid` LEFT JOIN `common_member` AS u2 ON `table_slog`.`slaveid`=u2.`uid` LEFT JOIN `common_member` AS u3 ON `table_slog`.`masterid`=u3.uid ORDER BY `id` DESC 

Answer 2

Нечто подобное:

SELECT `uid_main`.`username` AS `main_username`, 
    `uid_main`.`uid` AS `main_uid`, 
    `uid_master`.`username` AS `master_username`, 
    `uid_master`.`uid` AS `master_uid`, 
    `uid_slave`.`username` AS `slave_username`, 
    `uid_slave`.`uid` AS `slave_uid`, 
    `ls`.`bytime` AS `bytime` 
FROM `labour_slog` AS `ls` 
    LEFT JOIN `common_member` AS `uid_main` ON (`ls`.`uid` = `cm`.uid) 
    LEFT JOIN `common_member` AS `uid_master` ON (`ls`.`master_id` = `cm`.uid) 
    LEFT JOIN `common_member` AS `uid_master` ON (`ls`.`slave_id` = `cm`.uid) 
ORDER BY `cm`.`uid` DESC