SQL Query: Получить столбцы с различным условием

Question

Мне нужно получить несколько столбцов с различным состоянием из другой таблицы. Что я есть, как показано ниже

SELECT 
(SELECT COUNT(*) FROM Table1 WHERE Price >= 0 Price < 10) AS 'Group1', 
(SELECT COUNT(*) FROM Table1 WHERE Price >= 10 AND Price < 20) AS 'Group2', 
(SELECT COUNT(*) FROM Table1 WHERE Price >= 20 AND Price < 30) AS 'Group3', 
(SELECT COUNT(*) FROM Table2 WHERE Price >= 0 Price < 10) AS 'Group4', 
(SELECT COUNT(*) FROM Table2 WHERE Price >= 10 AND Price < 20) AS 'Group5', 
(SELECT COUNT(*) FROM Table2 WHERE Price >= 20 AND Price < 30) AS 'Group6' 

Просто удивительно, есть ли лучший способ реструктурировать лучший запрос для выше условия?

Answer 1

Существует,

SELECT SUM(CASE WHEN Price >= 0 Price < 10 THEN 1 END) AS 'Group1', 
     SUM(CASE WHEN Price >= 10 AND Price < 20 THEN 1 END) AS 'Group2', 
     SUM(CASE WHEN Price >= 20 AND Price < 30 THEN 1 END) AS 'Group3', 
     SUM(CASE WHEN Price >= 0 Price < 10 THEN 1 END) AS 'Group4', 
     SUM(CASE WHEN Price >= 10 AND Price < 20 THEN 1 END) AS 'Group5', 
     SUM(CASE WHEN Price >= 20 AND Price < 30 THEN 1 END) AS 'Group6' 
FROM table2 

Answer 2

Суммируя table1 к вышеупомянутому замечательный запрос на J W.

SELECT SUM(CASE WHEN T1.Price >= 0 Price < 10 THEN 1 END) AS 'Group1', 
     SUM(CASE WHEN T1.Price >= 10 AND Price < 20 THEN 1 END) AS 'Group2', 
     SUM(CASE WHEN T1.Price >= 20 AND Price < 30 THEN 1 END) AS 'Group3', 
     SUM(CASE WHEN T2.Price >= 0 Price < 10 THEN 1 END) AS 'Group4', 
     SUM(CASE WHEN T2.Price >= 10 AND Price < 20 THEN 1 END) AS 'Group5', 
     SUM(CASE WHEN T2.Price >= 20 AND Price < 30 THEN 1 END) AS 'Group6' 
FROM table1 T1, table2 T2