Сформировать XML из коллекции с помощью XDocument

Question

У меня есть объект, как под

class DBDetails 
    { 
     public int ServerId { get; set; } 
     public string Title { get; set; } 
     public string Address { get; set; } 
     public int DBId { get; set; } 
     public string DbName { get; set; } 
     public string UserId { get; set; } 
     public string Password { get; set; } 
    } 

Она заполняется в соответствии с

List<DBDetails> lstDBDetails = new List<DBDetails>(); 
lstDBDetails.Add(new DBDetails { ServerId = 1, Title = "IISDevdb1", Address = "Address1", DBId = 1, DbName = "db1", UserId = "u1", Password = "p1" }); 
lstDBDetails.Add(new DBDetails { ServerId = 2, Title = "iis2", Address = "Address2", DBId = 2, DbName = "db2", UserId = "u2", Password = "p2" }); 
lstDBDetails.Add(new DBDetails { ServerId = 1, Title = "IISDevdb1", Address = "Address1", DBId = 3, DbName = "db3", UserId = "u3", Password = "p3" }); 

Мне нужно создать следующий XML от него

<DataBaseServers> 
    <DataBaseServer id="1" title="IISDevdb1" address="Address1"> 
    <DataBases>  
     <database id="1" name="db1" userID="u1" password="p1" /> 
     <database id="3" name="db3" userID="u3" password="p3" /> 
    </DataBases> 
    </DataBaseServer> 
    <DataBaseServer id="2" title="iis2" address="Address2"> 
    <DataBases>  
     <database id="1" name="db2" userID="u2" password="p2" />  
    </DataBases> 
</DataBaseServers> 

Как это сделать с помощью XDocument?

Мой неудачный выстрел

var res = (from x in lstDBDetails 
         group x by x.ServerId into g 
         select new 
         { 
          A = g.Key , 
          B = g.ToList() 
         }); 

      var doc = new XDocument(
       new XElement("DataBaseServers", 
        res.Select(x => 
         new XElement("DataBaseServer", 
          new XAttribute("id", x.A),        
           new XElement("DataBases", 
            x.B.Select(y => 
            new XElement("database", 
             new XAttribute("id", y.DBId), 
             new XAttribute("name", y.DbName), 
             new XAttribute("userID", y.UserId), 
             new XAttribute("password", y.Password)))))))); 

Answer 1

var res = (from x in lstDBDetails 
         group x by new { x.ServerId, x.Title,x.Address } into g 
         select new 
         { 
          ServerId = g.Key.ServerId, 
          Title = g.Key.Title, 
          Address = g.Key.Address, 
          B = g.ToList() 
         }); 

      var doc = new XDocument(
       new XElement("DataBaseServers", 
        res.Select(x => 
         new XElement("DataBaseServer", 
          new XAttribute("id", x.ServerId), 
          new XAttribute("title", x.Title), 
          new XAttribute("address", x.Address), 
           new XElement("DataBases", 
            x.B.Select(y => 
            new XElement("database", 
             new XAttribute("id", y.DBId), 
             new XAttribute("name", y.DbName), 
             new XAttribute("userID", y.UserId), 
             new XAttribute("password", y.Password))))))));