Как получить уникальный идентификатор конкретного зрения

Question

//inflating row 
customView1=inflater.inflate(R.layout.single_row_materialdimension, null); 

container = (ViewGroup) findViewById(R.id.container); 
container.addView(customView1, 0, new ViewGroup.LayoutParams(ViewGroup.LayoutParams.FILL_PARENT, ViewGroup.LayoutParams.FILL_PARENT)); 

//Getting child Count from parent inflated the child 
int child = container.getChildCount(); 
container.setTag(child + 1); 

for (int i = 0; i < child; i++) { 
    Log.e("ChildAt", "" + container.getChildAt(i)); 
    View childView = container.getChildAt(i); 
    Log.e("childView ", "childView" + childView); 
    TextView tv1=(TextView)childView.findViewById(R.id.txt_parent_plus_id); 

    // setting onClickListner to inflated child 
    //i want to get unique id when i click on the inflated child** 
    tv1.setOnClickListener(handleOnClick(tv1)); 
} 

//i want to get unique id when i click on the inflated child** 

View.OnClickListener handleOnClick(final View view) { 
    return new View.OnClickListener() { 
     @Override 
     public void onClick(View v) { 
      // TODO Auto-generated method stub 
      Log.e("Clicked", "Clicked" + container.getTag()); 
     } 
    }; 
} 

Answer 1

Использование SETID() и GetId() методы.

for (int i = 0; i < child; i++) { 
Log.e("ChildAt", "" + container.getChildAt(i)); 
View childView = container.getChildAt(i); 
TextView tv1=(TextView)childView.findViewById(R.id.txt_parent_plus_id); 
tv1.setId(i); 
} 


tv1.setOnClickListener(new View.OnClickListener() { 

     @Override 
     public void onClick(View v) { 

      int id=tv1.getId(); 
      Log.e("Clicked", "Clicked" + String.valueOf(id))); 
     } 
    });