Загрузка изображений с регистрацией формы

Question

Привет это мой код формы:

echo "<form method=\"POST\" action=\"\">\n"; 
echo "<td>User Id</td><td> <input type=\"text\" name=\"user_id\"></td>\n"; 
echo "</tr>\n"; 
echo "<tr>\n"; 
echo "<td>Full Name</td><td> <input type=\"text\" name=\"full_name\"> </td>\n"; 
echo "</tr>\n"; 
echo "<tr>\n"; 
echo "<td>Qualification</td><td> <input type=\"text\" name=\"qualification\"></td>\n"; 
echo "</tr>\n"; 
echo "<tr>\n"; 
echo "<td>Locality</td><td> <input type=\"text\" name=\"locality\"></td>\n"; 
echo "</tr>\n"; 
echo "<tr>\n"; 
echo "<td>Description</td><td> <input type=\"text\" name=\"description\"></td>\n"; 
echo "</tr>\n"; 
echo "<tr>\n"; 
echo "<td>Languages Known</td><td><input type=\"text\" name=\"language\"></td>\n"; 
echo "</tr>\n"; 
echo "<tr>\n"; 
echo "<td>Experience</td><td><input type=\"text\" name=\"experience\"></td>\n"; 
echo "</tr>\n"; 
echo "<tr>\n"; 
echo "<td>Dress</td><td><input type=\"text\" name=\"dress_code\"></td>\n"; 
echo "</tr>\n"; 
echo "<tr>\n"; 
echo "<td>Bank Details</td><td><input type=\"text\" name=\"bank_details\"></td>\n"; 
echo "</tr>\n"; 
echo "<tr>\n"; 
echo "<td>Two Wheelers</td><td><input type=\"text\" name=\"two_wheeler\"></td>\n"; 
echo "</tr>\n"; 
echo "<tr>\n"; 
echo "<td>Threshold</td><td><input type=\"text\" name=\"threshold\"></td>\n"; 
echo "</tr>\n"; 
echo "<tr>\n"; 
echo "<td><input name=\"pic1\" type=\"file\"></td><td><input name=\"pic\" type=\"submit\" value=\"Upload Image\"></td>\n"; // Kindly check this line 
echo "</tr>\n"; 
echo "<tr>\n"; 
echo "<td>Photo 2</td><td><input type=\"text\" name=\"pic2\"></td>\n"; 
echo "</tr>\n"; 
echo "<tr>\n"; 
echo "<td>Photo 3</td><td><input type=\"text\" name=\"pic3\"></td>\n"; 
echo "</tr>\n"; 
echo "<tr>\n"; 
echo "<td>Photo 4</td><td><input type=\"text\" name=\"pic4\"></td>\n"; 
echo "</tr>\n"; 
echo "<tr>\n"; 
echo "<td>Photo 5</td><td><input type=\"text\" name=\"pic5\"></td>\n"; 
echo "</tr>\n"; 
echo "<tr>\n"; 
echo "<td>ID Number</td><td><input type=\"text\" name=\"id_proof\"></td>\n"; 
echo "</tr>\n"; 
echo "<tr>\n"; 
echo "<td>Contact Details</td><td><input type=\"text\" name=\"contact_details\"></td>\n"; 
echo "</tr>\n"; 
echo "<tr>\n"; 
echo "<td>Date</td><td><input type=\"text\" name=\"datetime_added\"></td>\n"; 
echo "</tr>\n"; 
echo "<tr>\n"; 
echo "<td><input id=\"button\" type=\"submit\" name=\"btn-signup\" value=\"Sign-Up\"></td>\n"; 
echo "</tr>\n"; 
echo "</form>\n"; 

У меня есть путаница, что, как я могу загрузить изображение в базе данных с form.Below мой файл PHP

if(isset($_POST['btn-signup'])) 
{ 
$user_id = mysql_real_escape_string($_POST['user_id']); 
$full_name = mysql_real_escape_string($_POST['full_name']); 
$qualification = mysql_real_escape_string($_POST['qualification']); 
$locality = mysql_real_escape_string($_POST['locality']); 
$description = mysql_real_escape_string($_POST['description']); 
$language = mysql_real_escape_string($_POST['language']); 
$experience = mysql_real_escape_string($_POST['experience']); 
$dress_code = mysql_real_escape_string($_POST['dress_code']); 
$bank_details = mysql_real_escape_string($_POST['bank_details']); 
$two_wheeler = mysql_real_escape_string($_POST['two_wheeler']); 
$threshold = mysql_real_escape_string($_POST['threshold']); 
$pic1 = mysql_real_escape_string($_POST['pic1']); 
$pic2 = mysql_real_escape_string($_POST['pic2']); 
$pic3 = mysql_real_escape_string($_POST['pic3']); 
$pic4 = mysql_real_escape_string($_POST['pic4']); 
$pic5 = mysql_real_escape_string($_POST['pic5']); 
$id_proof = mysql_real_escape_string($_POST['id_proof']); 
$contact_details = mysql_real_escape_string($_POST['contact_details']); 
$datetime_added = mysql_real_escape_string($_POST['dtetime_added']); 

$uname = trim($uname); 
$email = trim($email); 
$upass = trim($upass); 

$target = "upload/"; 
$target = $target . basename($_FILES['photo']['name']); 

//This gets all the other information from the form 
$pic1=($_FILES['photo']['name']); 

//Writes the photo to the server 
if(move_uploaded_file($_FILES['photo']['tmp_name'], $target)) 
{ 

//Tells you if its all ok 
echo "The file ". basename($_FILES['uploadedfile']['name']). " has been  uploaded, and your information has been added to the directory"; 
} 
else { 

//Gives and error if its not 
echo "Sorry, there was a problem uploading your file."; 
} 


// email exist or not 
$query = "SELECT user_id FROM promoter WHERE user_id='$user_id'"; 
$result = mysql_query($query); 

$count = mysql_num_rows($result); // if email not found then register 

if($count == 0){ 

    if(mysql_query("INSERT INTO promoter(user_id,full_name,qualification,locality,description,language,experience,dress_code,bank_details,two_wheeler,threshold,pic2,pic3,pic4,pic5,id_proof,contact_details,datetime_added, target) VALUES('$user_id','$full_name','$qualification','$locality','$description','$language','$experience','$dress_code','$bank_details','$two_wheeler','$threshold','$pic2','$pic3','$pic4','$pic5','$id_proof','$contact_details','$datetime_added','$target')")) 
    { 
     ?> 
     <script>alert('successfully registered ');</script> 
     <?php 
    } 
    else 
    { 
     ?> 
     <script>alert('error while registering you...');</script> 
     <?php 
    }  
} 
else{ 
     ?> 
     <script>alert('Sorry Email ID already taken ...');</script> 
     <?php 
} 

} 

Там я дал пять вариантов фото в форме, но я тестирую только в первом pic1. Помогите мне, как загрузить файл с моим кодом. Я смущен, как добавить изображение или добавить путь к изображению. Пожалуйста, скорректируйте мой код.

Answer 1

enctype="multipart/form-data" Добавить в свой тег формы

echo "<form method=\"POST\" action=\"\" enctype=\"multipart/form-data\">\n";