Merge каждый Каждый 6 словарь в один словарь Список

Question

ПРОБЛЕМА:

[ 
{'field_id': u'36908'},{'field_name': u'Code'},{'field_value': u'900321'}, 
{'field_id': u'36909'},{'field_name': u'Description'}, {'field_value': u'TIG 2.4MM TUNGSTEN (EACH ROD)'}, 
{'field_id': u'36910'}, {'field_name': u'Quantity'}, {'field_value': u'2'}, 
{'field_id': u'36911'}, {'field_name': u'Price'}, {'field_value': u'21.00'}, 
{'field_id': u'36912'}, {'field_name': u'Line Total'}, {'field_value': u'42.00'}, 

{'field_id': u'36908'}, {'field_name': u'Code'}, {'field_value': u'92.01.15.08'}, 
{'field_id': u'36909'}, {'field_name': u'Description'}, {'field_value': u'BINZEL .8MM MIG TIPS MB15'}, 
{'field_id': u'36910'}, {'field_name': u'Quantity'}, {'field_value': u'6'}, 
{'field_id': u'36911'}, {'field_name': u'Price'}, {'field_value': u'2.60'}, 
{'field_id': u'36912'}, {'field_name': u'Line Total'}, {'field_value': u'15.60'}] 

Необходимое ВЫВОД:

[ 
{'Code':u'900321', 
'Description':u'TIG 2.4MM TUNGSTEN (EACH ROD)', 
'Quantity':u'2', 
'Price':u'21.00', 
'Line Total': u'42.00'}, 

{'Code':u'92.01.15.08', 
'Description': u'BINZEL .8MM MIG TIPS MB15', 
'Quantity':u'6', 
'Price':u'2.60', 
'Line Total': u'15.60'}] 

Я пытался получить мое решение в ниже пути, но не получают надлежащего результат.

first_list_dict= 
[{'field_id': u'36908'}, {'field_name': u'Code'}, {'field_value': u'900321'}, {'field_id': u'36909'}, {'field_name': u'Description'}, {'field_value': u'TIG 2.4MM TUNGSTEN (EACH ROD)'}, {'field_id': u'36910'}, {'field_name': u'Quantity'}, {'field_value': u'2'}, {'field_id': u'36911'}, {'field_name': u'Price'}, {'field_value': u'21.00'}, {'field_id': u'36912'}, {'field_name': u'Line Total'}, {'field_value': u'42.00'}, {'field_id': u'36908'}, {'field_name': u'Code'}, {'field_value': u'92.01.15.08'}, {'field_id': u'36909'}, {'field_name': u'Description'}, {'field_value': u'BINZEL .8MM MIG TIPS MB15'}, {'field_id': u'36910'}, {'field_name': u'Quantity'}, {'field_value': u'6'}, {'field_id': u'36911'}, {'field_name': u'Price'}, {'field_value': u'2.60'}, {'field_id': u'36912'}, {'field_name': u'Line Total'}, {'field_value': u'15.60'}] 

new_dict={} 

for l in first_list_dict: 
    new_dict.update({l.get('field_name'):l.get('field_value')}) 

Но я получил некоторые None результирующее значение в моем словаре выхода:

{u'Code': None, u'Description': None, u'Price': None, None: u'15.60', u'Line Total': None, u'Quantity': None} 

Answer 1

Примечания:

• с помощью питона generator function method для перебора списка
• испытывающим временные переменные для подсчета и хранения временных данных
• с помощью обновления словаря и получить методы

Код:

lst=[ 
{'field_id': u'36908'},{'field_name': u'Code'},{'field_value': u'900321'}, 
{'field_id': u'36909'},{'field_name': u'Description'}, {'field_value': u'TIG 2.4MM TUNGSTEN (EACH ROD)'}, 
{'field_id': u'36910'}, {'field_name': u'Quantity'}, {'field_value': u'2'}, 
{'field_id': u'36911'}, {'field_name': u'Price'}, {'field_value': u'21.00'}, 
{'field_id': u'36912'}, {'field_name': u'Line Total'}, {'field_value': u'42.00'}, 
{'field_id': u'36908'}, {'field_name': u'Code'}, {'field_value': u'92.01.15.08'}, 
{'field_id': u'36909'}, {'field_name': u'Description'}, {'field_value': u'BINZEL .8MM MIG TIPS MB15'}, 
{'field_id': u'36910'}, {'field_name': u'Quantity'}, {'field_value': u'6'}, 
{'field_id': u'36911'}, {'field_name': u'Price'}, {'field_value': u'2.60'}, 
{'field_id': u'36912'}, {'field_name': u'Line Total'}, {'field_value': u'15.60'}] 

new_lst=[] # List to save output 
dic={} # Temporary dictionary to create output dictionary 
count=0 # Count variable to count the list element 
def iterating_list(lst): # Function to iterate over list 
    for value in lst: 
     yield value 
iterating=iterating_list(lst) 

for value in iterating : 
    if value.get('field_name'): # If `field_name` matches in the given lists 
    #By default get method return `None` when there is no given key 
     dic.update({value.get('field_name'):next(iterating).get('field_value')}) 
     count+=1 
    if count==5: # Resetting when count reaches to 5 
     count=0 
     new_lst.append(dic) 
     dic={} 
print new_lst 

Выход:

[{u'Price': u'21.00', u'Code': u'900321', u'Description': u'TIG 2.4MM TUNGSTEN (EACH ROD)', u'Line Total': u'42.00', u'Quantity': u'2'}, 
{u'Price': u'2.60', u'Code': u'92.01.15.08', u'Description': u'BINZEL .8MM MIG TIPS MB15', u'Line Total': u'15.60', u'Quantity': u'6'}]