2015-10-21 2 views
12

Я следую за Force directed Graph. Как предотвратить перекрытие ссылки (линии) в силе направленного графика. Ожидаемый результат должен быть равен this. Текущие данные JSON не содержат родительских отношений дочерних отношений.как предотвратить перекрытие ссылки в силе направленного графа?

Вот мой код:

var width = 960, 
 
    height = 500; 
 

 
var color = d3.scale.category20(); 
 

 
var force = d3.layout.force() 
 
    .charge(-120) 
 
    .linkDistance(30) 
 
    .size([width, height]); 
 

 
var svg = d3.select("body").append("svg") 
 
    .attr("width", width) 
 
    .attr("height", height); 
 

 
var graph = { 
 
    "nodes":[ 
 
    {"name":"Myriel","group":1}, 
 
    {"name":"Napoleon","group":1}, 
 
    {"name":"Mlle.Baptistine","group":1}, 
 
    {"name":"Mme.Magloire","group":1}, 
 
    {"name":"CountessdeLo","group":1}, 
 
    {"name":"Geborand","group":1}, 
 
    {"name":"Champtercier","group":1}, 
 
    {"name":"Cravatte","group":1}, 
 
    {"name":"Count","group":1}, 
 
    {"name":"OldMan","group":1}, 
 
    {"name":"Labarre","group":2}, 
 
    {"name":"Valjean","group":2}, 
 
    {"name":"Marguerite","group":3}, 
 
    {"name":"Mme.deR","group":2}, 
 
    {"name":"Isabeau","group":2}, 
 
    {"name":"Gervais","group":2}, 
 
    {"name":"Tholomyes","group":3}, 
 
    {"name":"Listolier","group":3}, 
 
    {"name":"Fameuil","group":3}, 
 
    {"name":"Blacheville","group":3}, 
 
    {"name":"Favourite","group":3}, 
 
    {"name":"Dahlia","group":3}, 
 
    {"name":"Zephine","group":3}, 
 
    {"name":"Fantine","group":3}, 
 
    {"name":"Mme.Thenardier","group":4}, 
 
    {"name":"Thenardier","group":4}, 
 
    {"name":"Cosette","group":5}, 
 
    {"name":"Javert","group":4}, 
 
    {"name":"Fauchelevent","group":0}, 
 
    {"name":"Bamatabois","group":2}, 
 
    {"name":"Perpetue","group":3}, 
 
    {"name":"Simplice","group":2}, 
 
    {"name":"Scaufflaire","group":2}, 
 
    {"name":"Woman1","group":2}, 
 
    {"name":"Judge","group":2}, 
 
    {"name":"Champmathieu","group":2}, 
 
    {"name":"Brevet","group":2}, 
 
    {"name":"Chenildieu","group":2}, 
 
    {"name":"Cochepaille","group":2}, 
 
    {"name":"Pontmercy","group":4}, 
 
    {"name":"Boulatruelle","group":6}, 
 
    {"name":"Eponine","group":4}, 
 
    {"name":"Anzelma","group":4}, 
 
    {"name":"Woman2","group":5}, 
 
    {"name":"MotherInnocent","group":0}, 
 
    {"name":"Gribier","group":0}, 
 
    {"name":"Jondrette","group":7}, 
 
    {"name":"Mme.Burgon","group":7}, 
 
    {"name":"Gavroche","group":8}, 
 
    {"name":"Gillenormand","group":5}, 
 
    {"name":"Magnon","group":5}, 
 
    {"name":"Mlle.Gillenormand","group":5}, 
 
    {"name":"Mme.Pontmercy","group":5}, 
 
    {"name":"Mlle.Vaubois","group":5}, 
 
    {"name":"Lt.Gillenormand","group":5}, 
 
    {"name":"Marius","group":8}, 
 
    {"name":"BaronessT","group":5}, 
 
    {"name":"Mabeuf","group":8}, 
 
    {"name":"Enjolras","group":8}, 
 
    {"name":"Combeferre","group":8}, 
 
    {"name":"Prouvaire","group":8}, 
 
    {"name":"Feuilly","group":8}, 
 
    {"name":"Courfeyrac","group":8}, 
 
    {"name":"Bahorel","group":8}, 
 
    {"name":"Bossuet","group":8}, 
 
    {"name":"Joly","group":8}, 
 
    {"name":"Grantaire","group":8}, 
 
    {"name":"MotherPlutarch","group":9}, 
 
    {"name":"Gueulemer","group":4}, 
 
    {"name":"Babet","group":4}, 
 
    {"name":"Claquesous","group":4}, 
 
    {"name":"Montparnasse","group":4}, 
 
    {"name":"Toussaint","group":5}, 
 
    {"name":"Child1","group":10}, 
 
    {"name":"Child2","group":10}, 
 
    {"name":"Brujon","group":4}, 
 
    {"name":"Mme.Hucheloup","group":8} 
 
    ], 
 
    "links":[ 
 
    {"source":1,"target":0,"value":1}, 
 
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    {"source":20,"target":19,"value":4}, 
 
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    {"source":62,"target":41,"value":1}, 
 
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    {"source":62,"target":60,"value":3}, 
 
    {"source":63,"target":59,"value":5}, 
 
    {"source":63,"target":48,"value":5}, 
 
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    {"source":71,"target":25,"value":1}, 
 
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    {"source":76,"target":58,"value":1} 
 
    ] 
 
} 
 

 
//d3.json("miserables.json", function(error, graph) { 
 
    force 
 
     .nodes(graph.nodes) 
 
     .links(graph.links) 
 
     .start(); 
 

 
    var link = svg.selectAll(".link") 
 
     .data(graph.links) 
 
    .enter().append("line") 
 
     .attr("class", "link") 
 
     .style("stroke-width", function(d) { return Math.sqrt(d.value); }); 
 

 
    var node = svg.selectAll(".node") 
 
     .data(graph.nodes) 
 
    .enter().append("circle") 
 
     .attr("class", "node") 
 
     .attr("r", 5) 
 
     .style("fill", function(d) { return color(d.group); }) 
 
     .call(force.drag); 
 

 
    node.append("title") 
 
     .text(function(d) { return d.name; }); 
 

 
    force.on("tick", function() { 
 
    link.attr("x1", function(d) { return d.source.x; }) 
 
     .attr("y1", function(d) { return d.source.y; }) 
 
     .attr("x2", function(d) { return d.target.x; }) 
 
     .attr("y2", function(d) { return d.target.y; }); 
 

 
    node.attr("cx", function(d) { return d.x; }) 
 
     .attr("cy", function(d) { return d.y; }); 
 
    }); 
 
//});
.node { 
 
    stroke: #fff; 
 
    stroke-width: 1.5px; 
 
} 
 

 
.link { 
 
    stroke: #999; 
 
    stroke-opacity: .6; 
 
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/d3/3.4.0/d3.min.js"></script>

+0

Я думаю, что это невозможно для всех графиков.Я заинтересован в том, как это может быть достигнуто во всех случаях, когда это возможно, хотя. – Oliver

+0

См https://stackoverflow.com/questions/29006725/avoid-links-criss-cross-overlap-in-d3-js-using-force-layout –

+1

Я не думаю, что это возможно, если у вас есть филиалы, которые связаны к другим ветвям одного и того же родителя. Пример вы показали только работает во всех случаях, когда узел подключается к одному из родителей, и это собственные дети. – myrcutio

ответ

0

Я хотел, чтобы оставить комментарий, но не хватает репутации, так что я «отвечать» вместо - жаль, что это не так большая часть ответа ...

Ваш пример ожидаемого результата - это дерево/ациклика, которое более или менее волшебным образом решает проблему перекрывающихся ссылок. Вы можете видеть в этом примере от Майка Бостока (http://bl.ocks.org/mbostock/1062288), что перекрытие ссылок не так просто, как данные, являющиеся деревом.

Итак ...

если ваши данные дерево, вы можете быть счастливым и связь перекрытия может быть не проблема. Вы заметите, что перекрытие в примере Бостока происходит, когда узлы-братья имеют разные расстояния между ссылками (что приводит к перекрытию связи племянницы/племянника - тети/дяди). Контролируя расстояния между ссылками (возможно, делая их функцией глубины дерева с более длинными ссылками рядом с корнем), I думаю, что предотвратит любое перекрытие в вашем дереве.

Если ваши данные имеют циклы (например, в данных Miserables), предотвращение перекрытия намного сложнее и не будет просто сортироваться. Как говорят другие, я не думаю, что это возможно с любым макетом D3.

1

Если вы перекрываете, вы имеете в виду несколько связей между двумя узлами, тогда их можно разрешить, вычерчивая их как дуги с увеличивающейся кривизной, чтобы визуально отделить их.

Если вы перекрываете, то вы имеете в виду пересекающие края, тогда это возможно только в том случае, если ваш график плоский - https://en.wikipedia.org/wiki/Planarity_testing - и, глядя на ваш график, его нет - есть как минимум 2 подграфа с почти полной связностью. Вы должны были бы алгоритм макета график, который специально пытается уменьшить край переездов, и плохие новости о том, что в том, что что это NP-полная задача

Crossing Номер является NP-Complete: DOI: 10,1137/0604033 https://en.wikipedia.org/wiki/Crossing_number_(graph_theory)

некоторых методы могут быть использованы на полных подграфах, заменив их края наборов с сливающимися краями или мотивами, но это заходя в графику рисунок исследования: нет простого ответа

слившихся Чертежи: Визуализация непланарных диаграмм в Planar Путь DOI: 10.1007/978-3-540-24595-7_1

Motif Упрощение: Улучшение сети визуализации Читаемости с вентилятором, разъемом и Clique Глифами DOI: 10.1145/2470654.2466444

Короче говоря, единственный гарантированный способ не получить краевые переходы не рисовать края. Может быть, попробуйте взглянуть на визуализацию матричного типа для графиков? - https://bost.ocks.org/mike/miserables/

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