Как использовать левый внешнее соединение в Linq

Question

У меня есть SQL заявление

SELECT 
cci.[ID], cci.[OwnerFirstName], cci.[OwnerLastName], cci.[CompanyName], 
cci.[AddressLine1], cci.[AddressLine2], cci.[AddressLine3], cci.[AddressLine4], 
cci.[AddressLine5], cci.[AddressCity], sp1.[Abbreviation] AS [StateAbbreviation], 
sp2.[Abbreviation] AS [ProvinceAbbreviation], cci.[AddressPostalCode], 
cr1.[Name] AS [CountryName], cr2.[Name] AS [RegionName], cci.[AddressNote], 
cci.[Phone1], cci.[Phone2], cci.[Phone3], cci.[Phone4], cci.[Phone5], 
cci.[Fax1], cci.[Fax2], cci.[Fax3], cci.[Fax4], cci.[Fax5], cci.[Email1], 
cci.[Email2], cci.[Email3], cci.[Email4], cci.[Email5], cci.[CompanyWebSite], 
ci.[EIN], ci.[SSN], cli.[LegalName], cli.[LegalAddressLine1], cli.[LegalAddressLine2], 
cli.[LegalAddressLine3], cli.[LegalAddressLine4], cli.[LegalAddressLine5], 
cli.[LegalAddressCity], sp3.[Abbreviation] AS [LegalAddressStateAbbreviation], 
sp4.[Abbreviation] AS [LegalAddressProvinceAbbreviation], cli.[LegalAddressPostalCode], 
cr3.[Name] AS [LegalAddressCountryName], cr4.[Name] AS [LegalAddressRegionName], 
cli.[LegalAddressNote], cri.[FirstMonthFiscalYear], cri.[FirstMonthIncomeTaxYear], 
CONCAT(CONCAT(CONCAT(itfl.[TaxForm], ' - ('),itfl.[Description]), ')') AS [TaxForm], 
c.[CryptoPassPhrase], c.[CryptoVector], c.[CryptoMinSALTLen], 
c.[CryptoMaxSALTLen], c.[CryptoKeySize], c.[CryptoHash], c.[CryptoSALT], 
c.[CryptoIterations], ga.[AccountCode], ga.[UseAnalytics], 
CONCAT(CONCAT(CONCAT(CONCAT(e1.[LastName], ', '), e1.[FirstName]), ' '), e1.[MiddleName]) AS [CreatedBy], 
sd.[CreatedByID], sd.[CreatedDateTime], 
CONCAT(CONCAT(CONCAT(CONCAT(e2.[LastName], ', '), e2.[FirstName]), ' '), e2.[MiddleName]) AS [ModifiedBy], 
sd.[ModifiedByID], sd.[ModifiedDateTime], sd.[SiteDescription], 
s.[SMTPServer], s.[SMTPUserName], s.[SMTPUserName], s.[SMTPPassword], 
s.[SMTP_TO], s.[SMTP_CC], s.[SMTP_BCC], s.[SMTPEncoding] 
FROM [settings].[CompanyContactInformation] cci 
LEFT OUTER JOIN [settings].[CompanyIdentification] ci ON cci.[ID] = ci.[SiteID] 
LEFT OUTER JOIN [settings].[CompanyLegalInformation] cli ON cci.[ID] = cli.[ID] 
LEFT OUTER JOIN [settings].[CompanyReportInformation] cri ON cci.[ID] = cri.[SiteID] 
LEFT OUTER JOIN [settings].[Cryptography] c ON cci.[ID] = c.[SiteID] 
LEFT OUTER JOIN [settings].[GoogleAnalytics] ga ON cci.[ID] = ga.[SiteID] 
LEFT OUTER JOIN [settings].[IncomeTaxFormList] itfl ON cri.[TaxFormID] = itfl.[ID] 
LEFT OUTER JOIN [settings].[SiteDetails] sd ON cci.[ID] = sd.[SiteID] 
LEFT OUTER JOIN [settings].[SMTP] s ON cci.[ID] = s.[SiteID] 
LEFT OUTER JOIN [dbo].[Employee] e1 ON sd.[CreatedByID] = e1.[ID] 
LEFT OUTER JOIN [dbo].[Employee] e2 ON sd.[ModifiedByID] = e2.[ID] 
LEFT OUTER JOIN [dbo].[CountryOrRegion] cr1 ON cci.[AddressCountryID] = cr1.[ID] 
LEFT OUTER JOIN [dbo].[CountryOrRegion] cr2 ON cci.[AddressRegionID] = cr2.[ID] 
LEFT OUTER JOIN [dbo].[CountryOrRegion] cr3 ON cli.[LegalAddressCountryID] = cr3.[ID] 
LEFT OUTER JOIN [dbo].[CountryOrRegion] cr4 ON cli.[LegalAddressRegionID] = cr4.[ID] 
LEFT OUTER JOIN [dbo].[StateOrProvince] sp1 ON cci.[AddressStateID] = sp1.[ID] 
LEFT OUTER JOIN [dbo].[StateOrProvince] sp2 ON cci.[AddressProvinceID] = sp2.[ID] 
LEFT OUTER JOIN [dbo].[StateOrProvince] sp3 ON cli.[LegalAddressStateID] = sp3.[ID] 
LEFT OUTER JOIN [dbo].[StateOrProvince] sp4 ON cli.[LegalAddressProvinceID] = sp4.[ID] 

До сих пор у меня есть следующее заявление LINQ в LINQPad:

var q = (
    from cci in CompanyContactInformation 
    join sp1 in StateOrProvince on cci.AddressStateID equals sp1.ID into t1 
    from rt1 in t.DefaultIfEmpty() 
    select new { 
     cci.ID, cci.OwnerFirstName, cci.OwnerLastName, cci.CompanyName, 
     cci.AddressLine1, cci.AddressLine2,cci.AddressLine3, 
     cci.AddressLine4, cci.AddressLine5, cci.AddressCity, 
     StateAbbreviation = sp1.Abbreviation 
    }).ToList(); 
q.Dump(); 

И я получаю следующее сообщение об ошибке:

'LINQPad.User.StateOrProvince' is a 'type' but is used like a 'variable'

The type of one of the expressions in the join clause is incorrect. Type inference failed in the call to 'GroupJoin'.

Что я здесь делаю неправильно?

Answer 1

Решает проблему после вытягивания волос. Если бы плюрализировать некоторые из таблиц. Вот собственно заявление LINQ:

var q = ( from cci in CompanyContactInformation join ci in CompanyIdentifications on cci.ID equals ci.SiteID into t1 from rt1 in t1.DefaultIfEmpty() join cli in CompanyLegalInformation on cci.ID equals cli.ID into t2 from rt2 in t2.DefaultIfEmpty() join cri in CompanyReportInformation on cci.ID equals cri.SiteID into t3 from rt3 in t3.DefaultIfEmpty() join c in Cryptographies on cci.ID equals c.SiteID into t4 from rt4 in t4.DefaultIfEmpty() join ga in GoogleAnalytics on cci.ID equals ga.SiteID into t5 from rt5 in t5.DefaultIfEmpty() join itfl in IncomeTaxFormLists on rt3.TaxFormID equals itfl.ID into t6 from rt6 in t6.DefaultIfEmpty() join sd in SiteDetails on cci.ID equals sd.SiteID into t7 from rt7 in t7.DefaultIfEmpty() join s in SMTPs on cci.ID equals s.SiteID into t8 from rt8 in t8.DefaultIfEmpty() join e1 in Employees on rt7.CreatedByID equals e1.ID into t9 from rt9 in t9.DefaultIfEmpty() join e2 in Employees on rt7.ModifiedByID equals e2.ID into t10 from rt10 in t10.DefaultIfEmpty() join cr1 in CountryOrRegions on cci.AddressCountryID equals cr1.ID into t11 from rt11 in t11.DefaultIfEmpty() join cr2 in CountryOrRegions on cci.AddressRegionID equals cr2.ID into t12 from rt12 in t12.DefaultIfEmpty() join cr3 in CountryOrRegions on rt2.LegalAddressCountryID equals cr3.ID into t13 from rt13 in t13.DefaultIfEmpty() join cr4 in CountryOrRegions on rt2.LegalAddressRegionID equals cr4.ID into t14 from rt14 in t14.DefaultIfEmpty() join sp1 in StateOrProvinces on cci.AddressStateID equals sp1.ID into t15 from rt15 in t15.DefaultIfEmpty() join sp2 in StateOrProvinces on cci.AddressProvinceID equals sp2.ID into t16 from rt16 in t16.DefaultIfEmpty() join sp3 in StateOrProvinces on rt2.LegalAddressStateID equals sp3.ID into t17 from rt17 in t17.DefaultIfEmpty() join sp4 in StateOrProvinces on rt2.LegalAddressProvinceID equals sp4.ID into t18 from rt18 in t18.DefaultIfEmpty() select new { cci.ID, cci.OwnerFirstName, cci.OwnerLastName, cci.CompanyName, cci.AddressLine1, cci.AddressLine2, cci.AddressLine3, cci.AddressLine4, cci.AddressLine5, cci.AddressCity, StateAbbreviation = rt15.Abbreviation, ProvinceAbbreviation = rt16.Abbreviation, cci.AddressPostalCode, CountryName = rt11.Name, RegionName = rt12.Name, cci.AddressNote, cci.Phone1, cci.Phone2, cci.Phone3, cci.Phone4, cci.Phone5, cci.Fax1, cci.Fax2, cci.Fax3, cci.Fax4, cci.Fax5, cci.Email1, cci.Email2, cci.Email3, cci.Email4, cci.Email5, cci.CompanyWebSite, rt1.EIN, rt1.SSN, rt2.LegalName, rt2.LegalAddressLine1, rt2.LegalAddressLine2, rt2.LegalAddressLine3, rt2.LegalAddressLine4, rt2.LegalAddressLine5, rt2.LegalAddressCity, LegalAddressStateAbbreviation = rt17.Abbreviation, LegalAddressProvinceAbbreviation = rt18.Abbreviation, rt2.LegalAddressPostalCode, LegalAddressCountryName = rt13.Name, LegalAddressRegionName = rt14.Name, rt2.LegalAddressNote, rt3.FirstMonthFiscalYear, rt3.FirstMonthIncomeTaxYear, TaxForm = rt6.TaxForm + " - (" + rt6.Description + ")", rt4.CryptoPassPhrase, rt4.CryptoVector, rt4.CryptoMinSALTLen, rt4.CryptoMaxSALTLen, rt4.CryptoKeySize, rt4.CryptoHash, rt4.CryptoSALT, rt4.CryptoIterations, rt5.AccountCode, rt5.UseAnalytics, CreatedBy = rt9.LastName + ", " + rt9.FirstName + " " + rt9.MiddleName, rt7.CreatedByID, rt7.CreatedDateTime, ModifiedBy = rt10.LastName + ", " + rt10.FirstName + " " + rt10.MiddleName, rt7.ModifiedByID, rt7.ModifiedDateTime, rt7.SiteDescription, rt8.SMTPServer, rt8.SMTPUserName, rt8.SMTPPassword, rt8.SMTP_TO, rt8.SMTP_CC, rt8.SMTP_BCC, rt8.SMTPEncoding }).ToList(); q.Dump();