В моем текущем весеннем проекте, я пытаюсь себе аннотации шаблона из javax.validation.constraints с полем поплавка, таким образом:использование @Pattern с Float полем
@Pattern(regexp = "[0-9]{2}.[0-9]{2}")
private Float preco;
но при попытке вставить или обновить юридическое лицо с этим полем, я получаю эту ошибку:
Caused by: javax.validation.UnexpectedTypeException: HV000030: No validator could be found for type: java.lang.Float.
at org.hibernate.validator.internal.engine.constraintvalidation.ConstraintValidatorManager.verifyResolveWasUnique(ConstraintValidatorManager.java:218)
at org.hibernate.validator.internal.engine.constraintvalidation.ConstraintValidatorManager.findMatchingValidatorClass(ConstraintValidatorManager.java:193)
at org.hibernate.validator.internal.engine.constraintvalidation.ConstraintValidatorManager.getInitializedValidator(ConstraintValidatorManager.java:97)
at org.hibernate.validator.internal.engine.constraintvalidation.ConstraintTree.validateConstraints(ConstraintTree.java:125)
at org.hibernate.validator.internal.engine.constraintvalidation.ConstraintTree.validateConstraints(ConstraintTree.java:91)
at org.hibernate.validator.internal.metadata.core.MetaConstraint.validateConstraint(MetaConstraint.java:83)
at org.hibernate.validator.internal.engine.ValidatorImpl.validateConstraint(ValidatorImpl.java:547)
at org.hibernate.validator.internal.engine.ValidatorImpl.validateConstraintsForDefaultGroup(ValidatorImpl.java:487)
at org.hibernate.validator.internal.engine.ValidatorImpl.validateConstraintsForCurrentGroup(ValidatorImpl.java:451)
at org.hibernate.validator.internal.engine.ValidatorImpl.validateInContext(ValidatorImpl.java:403)
at org.hibernate.validator.internal.engine.ValidatorImpl.validate(ValidatorImpl.java:206)
at org.hibernate.cfg.beanvalidation.BeanValidationEventListener.validate(BeanValidationEventListener.java:137)
at org.hibernate.cfg.beanvalidation.BeanValidationEventListener.onPreInsert(BeanValidationEventListener.java:95)
at org.hibernate.action.internal.EntityInsertAction.preInsert(EntityInsertAction.java:218)
at org.hibernate.action.internal.EntityInsertAction.execute(EntityInsertAction.java:97)
at org.hibernate.engine.spi.ActionQueue.executeActions(ActionQueue.java:463)
at org.hibernate.engine.spi.ActionQueue.executeActions(ActionQueue.java:349)
at org.hibernate.event.internal.AbstractFlushingEventListener.performExecutions(AbstractFlushingEventListener.java:350)
at org.hibernate.event.internal.DefaultFlushEventListener.onFlush(DefaultFlushEventListener.java:56)
at org.hibernate.internal.SessionImpl.flush(SessionImpl.java:1222)
at org.hibernate.internal.SessionImpl.managedFlush(SessionImpl.java:425)
at org.hibernate.engine.transaction.internal.jdbc.JdbcTransaction.beforeTransactionCommit(JdbcTransaction.java:101)
at org.hibernate.engine.transaction.spi.AbstractTransactionImpl.commit(AbstractTransactionImpl.java:177)
at org.hibernate.jpa.internal.TransactionImpl.commit(TransactionImpl.java:77)
Я пытаюсь добавить это в мой проект:
@Component
public class FloatEditor extends PropertyEditorSupport {
@Override
public void setAsText(String text) {
if (!text.isEmpty()) {
Float numero = Float.parseFloat(text);
setValue(numero);
}
}
}
и добавьте л ine к методу intiBinder от моего контроллера:
binder.registerCustomEditor(Float.class, new FloatEditor());
но такая же ошибка случается. Кто-нибудь знает, как сделать эту работу?